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State whether each of the statements below is true or false. Justify your answer in each case. (a) Electrolyte solutions conduct electricity because electrons are moving through the solution. (b) If you add a nonelectrolyte to an aqueous solution that already contains an electrolyte, the electrical conductivity will not change.

Short Answer

Expert verified
(a) False. Electrolyte solutions conduct electricity due to the movement of ions, not electrons, through the solution. (b) False. Adding a nonelectrolyte to an electrolyte solution can affect the electrical conductivity by changing the concentration of electrolyte ions in the solution.

Step by step solution

01

(a) Statement: Electrolyte solutions conduct electricity because electrons are moving through the solution.

This statement is false. Electrolyte solutions conduct electricity because of the movement of ions, not electrons, through the solution. When an electrolyte dissolves in water, it dissociates into its constituent ions. These free ions are able to move and carry an electric current in the presence of an electric field.
02

(b) Statement: If you add a nonelectrolyte to an aqueous solution that already contains an electrolyte, the electrical conductivity will not change.

This statement is false. Adding a nonelectrolyte to an electrolyte solution can affect the electrical conductivity. Nonelectrolytes are substances that do not dissociate into ions when dissolved in water. Therefore, adding a nonelectrolyte to an aqueous solution will not directly contribute to the conductivity. However, the presence of a nonelectrolyte may affect the concentration of the electrolyte ions in the solution, which can in turn affect the electrical conductivity. If the nonelectrolyte dilutes the electrolyte solution, the overall conductivity may decrease.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electrical Conductivity
Electrical conductivity in solutions is a measure of a substance's ability to allow the flow of an electric current. The current is carried by charged particles, which in the context of electrolyte solutions are ions. These ions originate from compounds that, when dissolved in water or another solvent, break apart and release positively and negatively charged particles.

Ions are crucial because they are the carriers of electric charge in the solution. The more ions present and the more mobile they are, the higher the electrical conductivity. Conversely, pure water or solutions with only nonelectrolytes (substances that do not produce ions) have very low electrical conductivity. For example, sugar or ethanol solutions conduct electricity poorly because these compounds dissolve without forming ions.
Ion Movement
Ion movement is essential for the conduction of electricity in electrolyte solutions. When dissolved in a solvent like water, electrolytes escape into the solution as cations and anions. These ions move freely in the solution, creating a path for electric current when an electric field is applied.

The mobility of the ions is influenced by factors such as the viscosity of the solution, the size and charge of the ions, and the temperature. Higher temperatures and lower viscosity generally increase ion mobility, improving conductivity. It is this motion of ions, rather than electrons as in metals, that is responsible for conducting electricity in liquid solutions.
Dissociation of Electrolytes
The dissociation of electrolytes is a process where ionic compounds separate into individual ions when they are dissolved in a solvent. This dissociation is critical for solutions to conduct electricity. Electrolytes can be strong or weak based on their ability to dissociate.

Strong electrolytes, like sodium chloride (table salt), dissociate completely in water, releasing a large number of ions and thereby increasing the solution’s conductivity. On the other hand, weak electrolytes only partially dissociate, resulting in fewer ions and lower conductivity. The degree of dissociation affects the concentration of ions in the solution, which is directly proportional to the electrical conductivity.
Nonelectrolyte Effect on Conductivity
Nonelectrolytes are substances that do not produce ions in solution and, therefore, do not contribute to electrical conductivity. When a nonelectrolyte is added to a solution containing electrolytes, it can influence the solution's properties and the movement of ions.

For instance, if a nonelectrolyte is added to an electrolyte solution, it may dilute the concentration of ions, potentially reducing the solution's overall conductivity. Moreover, the presence of nonelectrolyte molecules can also affect the ion mobility by increasing the viscosity of the solution or creating other interactions. Thus, while they don't contribute directly to conductivity, nonelectrolytes can have an indirect effect on the electrical conductivity of a solution.

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Most popular questions from this chapter

State whether each of the following statements is true or false. Justify your answer in each case. (a) \(\mathrm{NH}_{3}\) contains no \(\mathrm{OH}^{-}\)ions, and yet its aqueous solutions are basic. (b) HF is a strong acid. (c) Although sulfuric acid is a strong electrolyte, an aqueous solution of \(\mathrm{H}_{2} \mathrm{SO}_{4}\) contains more \(\mathrm{HSO}_{4}^{-}\)ions than \(\mathrm{SO}_{4}{ }^{2-}\) ions.

Indicate the concentration of each ion present in the solution formed by mixing (a) \(42.0 \mathrm{~mL}\) of \(0.170 \mathrm{M} \mathrm{NaOH}\) with \(37.6 \mathrm{~mL}\) of \(0.400 \mathrm{M} \mathrm{NaOH}\), (b) \(44.0 \mathrm{~mL}\) of \(0.100 \mathrm{M} \mathrm{Na}_{2} \mathrm{SO}_{4}\) with \(25.0 \mathrm{~mL}\) of \(0.150 \mathrm{M} \mathrm{KCl}\), (c) \(3.60 \mathrm{~g} \mathrm{KCl}\) in \(75.0 \mathrm{~mL}\) of \(0.250 \mathrm{M} \mathrm{CaCl}_{2}\) solution. Assume that the volumes are additive.

Indicate the concentration of each ion or molecule present in the following solutions: (a) \(0.25 \mathrm{M} \mathrm{NaNO}\), (b) \(1.3 \times 10^{-2} \mathrm{MMgSO}_{4}\), (c) \(0.0150 \quad M \quad \mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}\), (d) a mixture of \(45.0 \mathrm{~mL}\) of \(0.272 \mathrm{M} \mathrm{NaCl}\) and \(65.0 \mathrm{~mL}\) of \(0.0247 \mathrm{M}\left(\mathrm{NH}_{4}\right)_{2} \mathrm{CO}_{3}\). Assume that the volumes are additive.

Federal regulations set an upper limit of 50 parts per million (ppm) of \(\mathrm{NH}_{3}\) in the air in a work environment [that is, 50 molecules of \(\mathrm{NH}_{3}(g)\) for every million molecules in the air]. Air from a manufacturing operation was drawn through a solution containing \(1.00 \times 10^{2} \mathrm{~mL}\) of \(0.0105 \mathrm{M} \mathrm{HCl}\). The \(\mathrm{NH}_{3}\) reacts with \(\mathrm{HCl}\) according to: $$ \mathrm{NH}_{3}(a q)+\mathrm{HCl}(a q) \longrightarrow \mathrm{NH}_{4} \mathrm{Cl}(a q) $$ After drawing air through the acid solution for \(10.0 \mathrm{~min}\) at a rate of \(10.0 \mathrm{~L} / \mathrm{min}\), the acid was titrated. The remaining acid needed \(13.1 \mathrm{~mL}\) of \(0.0588 \mathrm{M} \mathrm{NaOH}\) to reach the equivalence point. (a) How many grams of \(\mathrm{NH}_{3}\) were drawn into the acid solution? (b) How many ppm of \(\mathrm{NH}_{3}\) were in the air? (Air has a density of \(1.20 \mathrm{~g} / \mathrm{L}\) and an average molar mass of \(29.0 \mathrm{~g} / \mathrm{mol}\) under the conditions of the experiment.) (c) Is this manufacturer in compliance with regulations?

Write balanced net ionic equations for the reactions that occur in each of the following cases. Identify the spectator ion or ions in each reaction. (a) \(\mathrm{Cr}_{2}\left(\mathrm{SO}_{4}\right)_{3}(a q)+\left(\mathrm{NH}_{4}\right)_{2} \mathrm{CO}_{3}(a q) \longrightarrow\) (b) \(\mathrm{Ba}\left(\mathrm{NO}_{3}\right)_{2}(a q)+\mathrm{K}_{2} \mathrm{SO}_{4}(a q) \longrightarrow\) (c) \(\mathrm{Fe}\left(\mathrm{NO}_{3}\right)_{2}(a q)+\mathrm{KOH}(a q)\)

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