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The complete combustion of octane, \(\mathrm{C}_{8} \mathrm{H}_{18}\), a component of gasoline, proceeds as follows: $$ 2 \mathrm{C}_{8} \mathrm{H}_{18}(l)+25 \mathrm{O}_{2}(g) \longrightarrow 16 \mathrm{CO}_{2}(g)+18 \mathrm{H}_{2} \mathrm{O}(g) $$ (a) How many moles of \(\mathrm{O}_{2}\) are needed to burn \(1.50 \mathrm{~mol}\) of \(\mathrm{C}_{8} \mathrm{H}_{18}\) ? (b) How many grams of \(\mathrm{O}_{2}\) are needed to burn \(10.0 \mathrm{~g}\) of \(\mathrm{C}_{8} \mathrm{H}_{18}\) ? (c) Octane has a density of \(0.692 \mathrm{~g} / \mathrm{mL}\) at \(20^{\circ} \mathrm{C}\). How many grams of \(\mathrm{O}_{2}\) are required to burn \(15.0 \mathrm{gal}\) of \(\mathrm{C}_{8} \mathrm{H}_{18}\) (the capacity of an average fuel tank)? (d) How many grams of \(\mathrm{CO}_{2}\) are produced when \(15.0 \mathrm{gal}\) of \(\mathrm{C}_{8} \mathrm{H}_{18}\) are combusted?

Short Answer

Expert verified
(a) \(18.75\) moles of O鈧 are needed to burn 1.50 moles of C鈧圚鈧佲倛. (b) \(35.0\) grams of O鈧 are needed to burn 10.0 grams of C鈧圚鈧佲倛. (c) \(137,500\) grams of O鈧 are required to burn 15.0 gallons of C鈧圚鈧佲倛. (d) \(121,000\) grams of CO鈧 are produced when 15.0 gallons of C鈧圚鈧佲倛 are combusted.

Step by step solution

01

a) Find moles of O鈧 needed to burn 1.50 moles of C鈧圚鈧佲倛

Use the balanced chemical equation and the stoichiometry to find the moles of O鈧 needed: For every 2 moles of C鈧圚鈧佲倛, 25 moles of O鈧 are required. So, for 1.50 moles of C鈧圚鈧佲倛: Moles of O鈧 needed = (25/2) 脳 1.50 = \(18.75\) moles
02

b) Find grams of O鈧 needed to burn 10.0 g of C鈧圚鈧佲倛

First, find out the moles of C鈧圚鈧佲倛: Moles of C鈧圚鈧佲倛 = (10.0 g) / (114.22 g/mol) = \(0.0875 moles\) Next, use the stoichiometry to find the moles of O鈧 required: Moles of O鈧 needed = (25/2) 脳 0.0875 = \(1.094 moles\) Now, convert moles of O鈧 to grams: Grams of O鈧 = 1.094 moles 脳 (32.00 g/mol) = \(35.0 g\)
03

c) Find grams of O鈧 needed to burn 15.0 gal of C鈧圚鈧佲倛

First, convert 15.0 gal to mL, using the conversion factor 1 gal = 3,785.41 mL: Volume of C鈧圚鈧佲倛 = 15.0 gal 脳 (3,785.41 mL/gal) = \(56,781 mL\) Next, convert the volume of C鈧圚鈧佲倛 to grams, using the given density: Grams of C鈧圚鈧佲倛 = 56,781 mL 脳 (0.692 g/mL) = \(39,294 g\) Find out the moles of C鈧圚鈧佲倛: Moles of C鈧圚鈧佲倛 = (39,294 g) / (114.22 g/mol) = \(343.92 moles\) Now, use stoichiometry to find the moles of O鈧 required: Moles of O鈧 needed = (25/2) 脳 343.92 = \(4,297 moles\) Finally, convert moles of O鈧 to grams: Grams of O鈧 = 4,297 moles 脳 (32.00 g/mol) = \(137,500 g\)
04

d) Find grams of CO鈧 produced when burning 15.0 gal of C鈧圚鈧佲倛

We already calculated the moles of C鈧圚鈧佲倛 in part (c): Moles of C鈧圚鈧佲倛 = 343.92 moles Use stoichiometry to find the moles of CO鈧 produced: Moles of CO鈧 produced = (16/2) 脳 343.92 = \(2,751.36 moles\) Next, convert moles of CO鈧 to grams: Grams of CO鈧 = 2,751.36 moles 脳 (44.01 g/mol) = \(121,000 g\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Stoichiometry
The fundamental principle of stoichiometry lies in the law of conservation of mass, ensuring that in a chemical reaction, atoms are neither created nor destroyed, only rearranged. This aspect is crucial when dealing with reactions such as the combustion of octane.

Stoichiometry allows us to calculate the precise amounts of reactants needed to react completely with each other and the amounts of products formed. For instance, in the combustion of octane, we find that 2 moles of octane react with 25 moles of oxygen to produce 16 moles of carbon dioxide and 18 moles of water. This balance ensures that all the atoms in the reactants have a place in the products.

For educational clarity, it's worthwhile to depict stoichiometry as a mathematical roadmap that connects the quantities of all substances involved in a chemical reaction. Utilizing stoichiometry, students can determine how many moles of oxygen are required to fully burn a mole of octane, or how much of one product is formed from a certain amount of reactant.
Chemical Reactions
Chemical reactions are processes where reactants transform into products through breaking and forming chemical bonds. Reactions are represented by chemical equations that must be balanced, reflecting the conservation of mass and the rearrangement of atoms.

The complete combustion of octane is such a reaction where octane and oxygen are the reactants that, upon sufficient activation energy (like a spark in an engine), produce carbon dioxide and water as products.

To enable students to visualize and understand chemical reactions, it's beneficial to use models or drawings to represent the reactants and products. This provides a clear picture of the process, making it more approachable and less abstract. Emphasizing the role of energy in these reactions, such as the heat required for the combustion of octane, also aids in grounding the students' understanding.
Mole Concept
The mole concept is a bridge between the microscopic world of atoms and molecules and the macroscopic world we experience. One mole represents Avogadro's number (\(6.022 \times 10^{23}\) entities) of anything, be it atoms, molecules, ions, or other particles.

In the context of the combustion of octane, using the mole concept allows us to convert between the weight of octane and the number of molecules involved. For example, 1 mole of octane weighs approximately 114.22 grams, and the exercise often involves converting a given mass of octane to moles to use in stoichiometric calculations.

For better understanding, it can be compared to buying fruits where instead of counting each fruit, a 'bunch' or 'dozen' can be used. Similarly, chemists use moles to 'count' atoms and molecules, making it much easier to relate to the quantities involved in chemical reactions.
Gasoline Combustion
Gasoline combustion is a specific type of chemical reaction where hydrocarbon fuels, predominantly octane, react with oxygen to release energy in the form of heat and light, and produce carbon dioxide and water vapor as by-products. This process is crucial for the functioning of internal combustion engines.

Understanding gasoline combustion provides real-world context for the abstract concepts of stoichiometry and the mole concept. It makes clear why precise proportions of fuel and oxygen are needed鈥攖oo little oxygen and you get incomplete combustion, creating pollutants like carbon monoxide; too much, and you're wasting oxygen that could be used for more combustion events.

When teaching this concept, use animations or video demonstrations to illustrate how the engine's environment enables the rapid reaction of gasoline with oxygen. Highlighting the environmental impact of burning gasoline, such as the production of greenhouse gases, can also be a relevant addition to the discussion, connecting chemistry with ecological consciousness.

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Most popular questions from this chapter

A piece of aluminum foil \(1.00 \mathrm{~cm}^{2}\) and \(0.550-\mathrm{mm}\) thick is allowed to react with bromine to form aluminum bromide. (a) How many moles of aluminum were used? (The density of aluminum is \(2.699 \mathrm{~g} / \mathrm{cm}^{3}\).) (b) How many grams of aluminum bromide form, assuming the aluminum reacts completely?

Detonation of nitroglycerin proceeds as follows: (a) If a sample containing \(2.00 \mathrm{~mL}\) of nitroglycerin (density \(=1.592 \mathrm{~g} / \mathrm{mL}\) ) is detonated, how many total moles of gas are produced? (b) If each mole of gas occupies \(55 \mathrm{~L}\) under the conditions of the explosion, how many liters of gas are produced? (c) How many grams of \(\mathrm{N}_{2}\) are produced in the detonation?

Aluminum sulfide reacts with water to form aluminum hydroxide and hydrogen sulfide. (a) Write the balanced chemical equation for this reaction. (b) How many grams of aluminum hydroxide are obtained from \(14.2 \mathrm{~g}\) of aluminum sulfide?

Determine the empirical and molecular formulas of each of the following substances: (a) Styrene, a compound substance used to make Styrofoam cups and insulation, contains \(92.3 \% \mathrm{C}\) and \(7.7 \% \mathrm{H}\) by mass and has a molar mass of \(104 \mathrm{~g} / \mathrm{mol}\). (b) Caffeine, a stimulant found in coffee, contains \(49.5 \% \mathrm{C}\), \(5.15 \% \mathrm{H}, 28.9 \% \mathrm{~N}\), and \(16.5 \% \mathrm{O}\) by mass and has a molar mass of \(195 \mathrm{~g} / \mathrm{mol}\). (c) Monosodium glutamate (MSG), a flavor enhancer in certain foods, contains \(35.51 \% \mathrm{C}, 4.77 \% \mathrm{H}, 37.85 \% \mathrm{O}\), \(8.29 \% \mathrm{~N}\), and \(13.60 \% \mathrm{Na}\), and has a molar mass of \(169 \mathrm{~g} / \mathrm{mol}\).

Washing soda, a compound used to prepare hard water for washing laundry, is a hydrate, which means that a certain number of water molecules are included in the solid structure. Its formula can be written as \(\mathrm{Na}_{2} \mathrm{CO}_{3} \cdot x \mathrm{H}_{2} \mathrm{O}\), where \(x\) is the number of moles of \(\mathrm{H}_{2} \mathrm{O}\) per mole of \(\mathrm{Na}_{2} \mathrm{CO}_{3}\). When a 2.558-g sample of washing soda is heated at \(125^{\circ} \mathrm{C}\), all the water of hydration is lost, leaving \(0.948 \mathrm{~g}\) of \(\mathrm{Na}_{2} \mathrm{CO}_{3}\). What is the value of \(x\) ?

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