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Complete and balance the following equations: (a) \(\mathrm{Mg}_{3} \mathrm{~N}_{2}(s)+\mathrm{H}_{2} \mathrm{O}(l) \longrightarrow\) (b) \(\mathrm{NO}(g)+\mathrm{O}_{2}(g) \longrightarrow\) (c) \(\mathrm{N}_{2} \mathrm{O}_{5}(g)+\mathrm{H}_{2} \mathrm{O}(l)\) (d) \(\mathrm{NH}_{3}(a q)+\mathrm{H}^{+}(a q) \longrightarrow\) (e) \(\mathrm{N}_{2} \mathrm{H}_{4}(l)+\mathrm{O}_{2}(g) \longrightarrow\) Which ones of these are redox reactions?

Short Answer

Expert verified
The balanced chemical equations are: (a) Mg3N2(s) + 6H鈧侽(l) 鈫 3Mg(OH)鈧(s) + 2NH鈧(g) (Redox reaction) (b) 2NO(g) + O鈧(g) 鈫 2NO鈧(g) (Redox reaction) (c) N鈧侽鈧(g) + 2H鈧侽(l) 鈫 2HNO鈧(aq) (Not a redox reaction) (d) NH鈧(aq) + H鈦(aq) 鈫 NH鈧勨伜(aq) (Not a redox reaction) (e) 2N鈧侶鈧(l) + O鈧(g) 鈫 2N鈧(g) + 4H鈧侽(g) (Redox reaction) The redox reactions are (a), (b), and (e).

Step by step solution

01

(a) Balancing the equation: Mg3N2(s) + H2O(l) 鈫

To balance this equation, we can first separate the ionic species: Mg3N2(s) 鈫 3Mg虏鈦(s) + 2N鲁鈦(s) H2O(l) 鈫 H鈧侽(l) Now, we can react 2N鲁鈦(s) with 6H鈧侽(l) to form six hydronium ions and two NO鈧冣伝 ions: 2N鲁鈦(s) + 6H鈧侽(l) 鈫 6OH鈦(l) + 2N鲁鈦(l) Finally, we can react 3Mg虏鈦(s) with 6OH鈦(l) to form Mg(OH)鈧(s): 3Mg虏鈦(s) + 6OH鈦(l) 鈫 3Mg(OH)鈧(s) Upon combining these steps, we get: Mg3N2(s) + 6H鈧侽(l) 鈫 3Mg(OH)鈧(s) + 2NH鈧(g)
02

(b) Balancing the equation: NO(g) + O2(g) 鈫

Observe that 2 atoms of oxygen are needed to have the same amount of oxygen atoms on both sides of the equation: 2NO(g) + O鈧(g) 鈫 2NO鈧(g)
03

(c) Balancing the equation: N2O5(g) + H2O(l) 鈫

Observe that 2 molecules of water are needed to generate 2 nitric acid molecules (HNO鈧): N鈧侽鈧(g) + 2H鈧侽(l) 鈫 2HNO鈧(aq)
04

(d) Balancing the equation: NH3(aq) + H鈦(aq) 鈫

Observe that the ammonium ion (NH鈧勨伜) is produced in this reaction: NH鈧(aq) + H鈦(aq) 鈫 NH鈧勨伜(aq)
05

(e) Balancing the equation: N2H4(l) + O2(g) 鈫

Observe that 2 molecules of N鈧侶鈧 are needed to react with 1 molecule of O鈧 to generate 2 molecules of N鈧 and 4 molecules of H鈧侽: 2N鈧侶鈧(l) + O鈧(g) 鈫 2N鈧(g) + 4H鈧侽(g) Now we proceed to identify the redox reactions:
06

(a) Identifying the redox reaction: Mg3N2(s) + 6H鈧侽(l) 鈫 3Mg(OH)鈧(s) + 2NH鈧(g)

Mg goes from the oxidation state of 0 to +2, and N goes from -3 to -3/+3, which indicates a transfer of electrons. This is a redox reaction.
07

(b) Identifying the redox reaction: 2NO(g) + O鈧(g) 鈫 2NO鈧(g)

N goes from the oxidation state of +2 to +4, and O goes from 0 to -2, which indicates a transfer of electrons. This is a redox reaction.
08

(c) Identifying the redox reaction: N鈧侽鈧(g) + 2H鈧侽(l) 鈫 2HNO鈧(aq)

No transfer of electrons occurs in this reaction as the oxidation state of oxygen remains -2. Hence, this is not a redox reaction.
09

(d) Identifying the redox reaction: NH鈧(aq) + H鈦(aq) 鈫 NH鈧勨伜(aq)

No transfer of electrons occurs in this reaction as the oxidation state of N remains -3 and H remains +1. Hence, this is not a redox reaction.
10

(e) Identifying the redox reaction: 2N鈧侶鈧(l) + O鈧(g) 鈫 2N鈧(g) + 4H鈧侽(g)

N goes from the oxidation state of -2 to 0, and O goes from 0 to -2, which indicates a transfer of electrons. This is a redox reaction. In conclusion, the redox reactions are: (a), (b), and (e).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Redox Reactions
Redox reactions are fundamental chemical processes where reduction and oxidation occur simultaneously. The term 'redox' is a portmanteau of reduction and oxidation. In simple terms, oxidation involves the loss of electrons, while reduction involves the gain of electrons. To visualize this, consider the electron as a currency in chemistry; during a redox reaction, one species pays electrons to another, changing the electron balance of each.

Using the examples provided in the exercise, in reaction (a), (b), and (e), we can see that redox reactions are taking place. For instance, in reaction (a), magnesium (Mg) atoms lose electrons and therefore get oxidized, while nitrogen (N) atoms gain electrons and get reduced. It's like a dance of electrons where one partner gives away electrons and becomes more positive, while the other receives electrons and becomes more negative.

In every redox process, there is a transfer of electrons from the reducing agent to the oxidizing agent. This electron transfer is what fundamentally characterizes a redox reaction. To improve understanding, always consider the conservation of charge and the movement of electrons when identifying redox reactions. Look for changes in oxidation states to pinpoint where the redox action is happening.
Oxidation States
Understanding oxidation states is crucial for mastering redox reactions. An oxidation state, often referred to as oxidation number, is a conceptual charge assigned to an atom within a molecule or ion, assuming that the compound is purely ionic. The rules for determining oxidation states include assigning free elements an oxidation state of 0, assigning oxygen a usual state of -2 (except in peroxides), hydrogen +1 (except when bonded to metals when it is -1), and summing the total oxidation states to equal the charge of the molecule or ion.

For example, in reaction (b), NO has nitrogen at +2 oxidation state, which changes to +4 in NO鈧, signaling an oxidation. Conversely, the oxygen in O鈧 starts with an oxidation state of 0 and ends up as -2 in NO鈧, showcasing a reduction. These changes in oxidation states are indicators that electrons are being transferred across participants in the reaction.

Oxidation states help in tallying the electrons as if accounting for them in a ledger. By balancing the change in oxidation numbers, you can ensure that electrons are conserved in your chemical equation. Always keep in mind that the overall charge of the system must remain constant before and after the reaction.
Chemical Nomenclature
Chemical nomenclature is like the language of chemistry. It provides a systematic way for scientists to name various chemical compounds. The nomenclature must convey the composition and structure of a compound clearly and unambiguously. For instance, in the given exercises, compounds like \(\mathrm{Mg}_{3} \mathrm{N}_{2}\) are named based on the elements present (magnesium nitride) and \(\mathrm{N}_{2} \mathrm{H}_{4}\) is called hydrazine.

There are different rules and systems for naming inorganic and organic compounds. Inorganic nomenclature, for instance, often involves prefixes and suffixes to indicate the number of atoms and the type of bond or complex. Hydrates, oxyanions, and acids have specific naming conventions too. A good grasp of chemical nomenclature will not only help you label compounds correctly but also give you hints about their potential reactivity and the type of reactions they might undergo, like redox reactions.

For thorough understanding, practice naming compounds by writing out the names and formulae and using nomenclature rules. This exercise can make it much easier to approach and solve chemical equations, especially when identifying the types of reactions they represent.

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Most popular questions from this chapter

Manganese silicide has the empirical formula MnSi and melts at \(1280^{\circ} \mathrm{C}\). It is insoluble in water but does dissolve in aqueous HF. (a) What type of compound do you expect MnSi to be: metallic, molecular, covalent- network, or ionic? (b) Write a likely balanced chemical equation for the reaction of \(\mathrm{MnSi}\) with concentrated aqueous HF.

Write a balanced equation for each of the following reactions: (a) Hydrogen cyanide is formed commercially by passing a mixture of methane, ammonia, and air over a catalyst at \(800^{\circ} \mathrm{C}\). Water is a by-product of the reaction. (b) Baking soda reacts with acids to produce carbon dioxide gas. (c) When barium carbonate reacts in air with sulfur dioxide, barium sulfate and carbon dioxide form.

Write a molecular formula for each compound, and indicate the oxidation state of the group \(5 \mathrm{~A}\) element in each formula: (a) phosphorous acid, (b) pyrophosphoric acid, (c) antimony trichloride, (d) magnesium arsenide, (e) diphosphorus pentoxide, (f) sodium phosphate.

You have two glass bottles, one containing oxygen and one filled with nitrogen. How could you determine which one is which? [Sections \(22.5\) and \(22.7\) ]

The standard heats of formation of \(\mathrm{H}_{2} \mathrm{O}(g), \mathrm{H}_{2} \mathrm{~S}(g), \mathrm{H}_{2} \mathrm{Se}(g)\), and \(\mathrm{H}_{2} \mathrm{Te}(g)\) are \(-241.8,-20.17,+29.7\), and \(+99.6 \mathrm{~kJ} /\) mol, respectively. The enthalpies necessary to convert the elements in their standard states to one mole of gaseous atoms are \(248,277,227\), and \(197 \mathrm{~kJ} / \mathrm{mol}\) of atoms for \(\mathrm{O}, \mathrm{S}, \mathrm{Se}\), and Te, respectively. The enthalpy for dissociation of \(\mathrm{H}_{2}\) is \(436 \mathrm{~kJ} / \mathrm{mol}\). Calculate the average \(\mathrm{H}-\mathrm{O}, \mathrm{H}-\mathrm{S}, \mathrm{H}-\mathrm{Se}\), and \(\mathrm{H}\) - Te bond enthalpies, and comment on their trend.

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