/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 35 Complete and balance the followi... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Complete and balance the following nuclear equations by supplying the missing particle: (a) \({ }_{58}^{252} \mathrm{Cf}+{ }_{5}^{10} \mathrm{~B} \longrightarrow 3{ }_{0}^{1} \mathrm{n}+\) ? (b) \({ }_{1}^{2} \mathrm{H}+{ }_{2}^{3} \mathrm{He} \longrightarrow{ }_{2}^{4} \mathrm{He}+\) ? (c) \({ }_{1}^{1} \mathrm{H}+{ }_{5}^{11} \mathrm{~B} \longrightarrow 3\) ? (d) \({ }_{53}^{122} \mathrm{I} \longrightarrow{ }_{54}^{122} \mathrm{Xe}+\) ? (e) \({ }_{26}^{59} \mathrm{Fe} \longrightarrow{ }_{-1}^{0} \mathrm{e}+\) ?

Short Answer

Expert verified
(a) \({}_{58}^{252}\mathrm{Cf}+{}_{5}^{10}\mathrm{B} \longrightarrow 3{}_{0}^{1}\mathrm{n}+{}_{63}^{259}\mathrm{Eu}\) (b) \({}_{1}^{2}\mathrm{H}+{}_{2}^{3}\mathrm{He} \longrightarrow{}_{2}^{4}\mathrm{He}+{}_{1}^{1}\mathrm{H}\)

Step by step solution

01

Conservation of Mass Number and Atomic Number

Write down the conservation equations for both mass number (A) and atomic number (Z): A: 252 + 10 = 3(1) + A_missing Z: 58 + 5 = 0 + Z_missing
02

Solve for the Missing Values

Solve these conservation equations for the missing mass number and atomic number. A: A_missing = 252 + 10 - 3(1) = 259 Z: Z_missing = 58 + 5 = 63
03

Write the Complete Nuclear Equation

Now that we have the missing mass and atomic numbers, the completed and balanced equation is: \({}_{58}^{252}\mathrm{Cf}+{}_{5}^{10}\mathrm{B} \longrightarrow 3{}_{0}^{1}\mathrm{n}+{}_{63}^{259}\mathrm{?}\) (b) \({}_{1}^{2}\mathrm{H}+{}_{2}^{3}\mathrm{He} \longrightarrow{}_{2}^{4}\mathrm{He}+\) ?
04

Conservation of Mass Number and Atomic Number

Write down the conservation equations for both mass number (A) and atomic number (Z): A: 2 + 3 = 4 + A_missing Z: 1 + 2 = 2 + Z_missing
05

Solve for the Missing Values

Solve these conservation equations for the missing mass number and atomic number. A: A_missing = 2 + 3 - 4 = 1 Z: Z_missing = 1 + 2 - 2 = 1
06

Write the Complete Nuclear Equation

Now that we have the missing mass and atomic numbers, the completed and balanced equation is: \({}_{1}^{2}\mathrm{H}+{}_{2}^{3}\mathrm{He} \longrightarrow{}_{2}^{4}\mathrm{He}+{}_{1}^{1}\mathrm{?}\) Note: The '?' should be replaced with the appropriate chemical symbols, which can be found using the periodic table based on the atomic number. For example, \({}_{63}^{259}\mathrm{?}\) should be replaced by \({}_{63}^{259}\mathrm{Eu}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conservation of Mass Number
In nuclear reactions, one fundamental principle is the conservation of mass number, which states that the sum of mass numbers (the total number of protons and neutrons) in the reactants must equal the sum of the mass numbers in the products. The mass number is denoted as 'A'. To ensure a nuclear equation is balanced regarding mass number, we identify and sum the mass numbers on each side of the reaction and make any necessary adjustments to balance the equation.

For instance, in the example where Californium (Cf) and Boron (B) react to produce neutrons and an unknown element, we use the conservation of mass number to find the mass of the unknown product. The calculation would be as follows: the total mass on the left side is 262 (252 for Cf and 10 for B), and the total mass on the right side is the sum of the mass of the three neutrons (3) plus the mass of the unknown product. Solving for the unknown mass gives us a mass number of 259 for the new element.
Conservation of Atomic Number
Closely related to the conservation of mass number is the conservation of atomic number, which ensures that the number of protons, or the atomic number 'Z', remains constant before and after the reaction. To check for balance regarding atomic number, we follow similar steps as for the mass number, but focus on protons.

In our given example, the atomic number for Californium is 58 and for Boron is 5, giving us a total of 63 on the reactant side. Neutrons do not contribute to the atomic number because they lack a positive charge. Therefore, the atomic number of the unknown element must also be 63. With both mass and atomic numbers in hand, we can now deduce the identity of the unknown product from the periodic table, which, in this case, turns out to be Europium (Eu).
Nuclear Chemistry
Nuclear chemistry is the sub-discipline of chemistry that deals with changes in the nucleus of elements. These changes often involve the transformation of one element into another and the harnessing of the energy changes associated with these transformations. Nuclear chemistry is fundamental in many applications such as energy production in nuclear reactors, medical imaging and treatments, and in understanding cosmic phenomena.

The balancing of nuclear equations is an essential skill within the field of nuclear chemistry because it allows scientists and students to understand the details involved in nuclear reactions, including the types of particles involved, their interactions, and the products formed. This understanding is crucial both for predicting the outcomes of reactions and for ensuring the proper handling of materials, especially when dealing with radioactive substances.
Balancing Nuclear Reactions
Balancing nuclear reactions requires a meticulous approach to ensure that both mass and atomic numbers remain constant from reactants to products. This is crucial for accurately predicting reaction outcomes and adhering to the laws of conservation in nuclear chemistry. To balance nuclear reactions, one must go through a series of steps that involve identifying the starting materials, writing down the conservation equations for both mass number and atomic number, solving for any unknowns, and completing the reaction with appropriate elements or particles while ensuring that the mass and atomic numbers are balanced on both sides of the equation.

The exercises provided demonstrate the application of these principles to solve nuclear equations. The steps guide students to fill in missing particles or unknown elements, reinforcing their understanding of the process. When teaching or learning about balancing nuclear reactions, it is beneficial to refer to a periodic table to identify elements based on their atomic numbers and to practice with a variety of reaction types to gain proficiency in this essential area of nuclear chemistry.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Tests on human subjects in Boston in 1965 and 1966, following the era of atomic bomb testing, revealed average quantities of about \(2 \mathrm{pCi}\) of plutonium radioactivity in the average person. How many disintegrations per second does this level of activity imply? If each alpha particle deposits \(8 \times 10^{-13} \mathrm{~J}\) of energy and if the average person weighs \(75 \mathrm{~kg}\), calculate the number of rads and rems of radiation in 1 yr from such a level of plutonium.

In 1930 the American physicist Ernest Lawrence designed the first cyclotron in Berkeley, California. In 1937 Lawrence bombarded a molybdenum target with deuterium ions, producing for the first time an element not found in nature. What was this element? Starting with molybdenum- 96 as your reactant, write a nuclear equation to represent this process.

The cloth shroud from around a mummy is found to have \(a^{14} \mathrm{C}\) activity of \(9.7\) disintegrations per minute per gram of carbon as compared with living organisms that undergo \(16.3\) disintegrations per minute per gram of carbon. From the halflife for \({ }^{14} \mathrm{C}\) decay, \(5715 \mathrm{yr}\), calculate the age of the shroud.

One nuclide in each of these pairs is radioactive. Predict which is radioactive and which is stable: (a) \({ }_{20}^{40} \mathrm{Ca}\) and \({ }_{20}^{45} \mathrm{Ca}\), (b) \({ }^{12} \mathrm{C}\) and \({ }^{14} \mathrm{C}\), (c) lead-206 and thorium-230. Fxplain your choice in each case.

The Sun radiates energy into space at the rate of \(3.9 \times 10^{26} \mathrm{~J} / \mathrm{s}\). (a) Calculate the rate of mass loss from the Sun in \(\mathrm{kg} / \mathrm{s}\). (b) How does this mass loss arise? (c) It is estimated that the Sun contains \(9 \times 10^{56}\) free protons. How many protons per second are consumed in nuclear reactions in the Sun?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.