/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 61 Predict the chemical formula for... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Predict the chemical formula for the ionic compound formed by (a) \(\mathrm{Ca}^{2+}\) and \(\mathrm{Br}^{-}\), (b) \(\mathrm{K}^{+}\)and \(\mathrm{CO}_{3}^{2-}\), (c) \(\mathrm{Al}^{3+}\) and \(\mathrm{CH}_{3} \mathrm{COO}^{-}\), (d) \(\mathrm{NH}_{4}^{+}\)and \(\mathrm{SO}_{4}^{2-}\), (c) \(\mathrm{Mg}^{2+}\) and \(\mathrm{PO}_{4}{ }^{3-}\).

Short Answer

Expert verified
The chemical formulas for the ionic compounds formed by the given ions are: (a) CaBr₂, (b) K₂CO₃, (c) Al(CH₃COO)₃, (d) (NH₄)₂SO₄, and (e) Mg₃(PO₄)₂.

Step by step solution

01

(a) Ca^2+ and Br^(-1)

: In this case, we have a \( \mathrm{Ca}^{2+}\) ion with a +2 charge and a \( \mathrm{Br}^{-}\) ion with a -1 charge. In order to balance the charges, we need two \( \mathrm{Br}^{-}\) ions for each \( \mathrm{Ca}^{2+}\) ion. Thus, the resulting chemical formula for the ionic compound formed by these ions will be \( \mathrm{CaBr}_{2}\).
02

(b) K^+ and CO_3^(2-)

: For this compound, we have a \( \mathrm{K}^{+}\) ion with a +1 charge and a \( \mathrm{CO_{3}}^{2-}\) ion with a -2 charge. To balance the charges, we will need two \( \mathrm{K}^{+}\) ions for each \( \mathrm{CO_{3}}^{2-}\) ion. The chemical formula for this compound will be \( \mathrm{K}_{2}\mathrm{CO}_{3}\).
03

(c) Al^3+ and CH_3COO^-

: This time, we have an \( \mathrm{Al}^{3+}\) ion with a +3 charge and a \( \mathrm{CH}_{3} \mathrm{COO}^{-}\) ion with a -1 charge. To balance the charges, we will need three \( \mathrm{CH}_{3} \mathrm{COO}^{-}\) ions for each \( \mathrm{Al}^{3+}\) ion. The chemical formula for this compound will be \( \mathrm{Al(CH}_{3}\mathrm{COO})_{3}\).
04

(d) NH_4^+ and SO_4^(2-)

: For this compound, we have an \( \mathrm{NH}_{4}^{+}\) ion with a +1 charge and a \( \mathrm{SO}_{4}^{2-}\) ion with a -2 charge. We will need two \( \mathrm{NH}_{4}^{+}\) ions for each \( \mathrm{SO}_{4}^{2-}\) ion in order to balance the charges. The chemical formula for this compound will be \( \mathrm{(NH}_{4}\mathrm{)_{2}SO}_{4}\).
05

(e) Mg^2+ and PO_4^(3-)

: Lastly, we have a \( \mathrm{Mg}^{2+}\) ion with a +2 charge and a \( \mathrm{PO}_{4}^{3-}\) ion with a -3 charge. In this case, we will need three \( \mathrm{Mg}^{2+}\) ions and two \( \mathrm{PO}_{4}^{3-}\) ions to balance the charges. The chemical formula for this compound will be \( \mathrm{Mg}_{3}(\mathrm{PO}_{4})_{2}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Formula
Understanding the chemical formula of a substance is fundamental in the field of chemistry. It tells us the exact number and type of atoms that make up a molecule. In ionic compounds, the formula is determined by the ratio of cations (positively charged ions) to anions (negatively charged ions) required to achieve charge neutrality.

For example, calcium bromide, with its chemical formula \(\mathrm{CaBr}_2\), has one calcium ion (\(\mathrm{Ca}^{2+}\)) for every two bromide ions (\(\mathrm{Br}^{-}\)), ensuring that the total positive charge equals the total negative charge. Mastering the art of predicting these formulas is not just a matter of memorization but understanding the charge relationships between ions.
Ionic Bonding
Ionic bonding is the electrostatic force of attraction between oppositely charged ions. These ions are formed when atoms either lose or gain electrons to fulfill their need for a more stable electron configuration, typically resembling the nearest noble gas. Cations lose electrons and acquire a positive charge, while anions gain electrons, acquiring a negative charge.

For instance, in the compound \(\mathrm{K}_2\mathrm{CO}_3\), potassium (\(\mathrm{K}^+\)) donates an electron becoming a cation, while the carbonate ion (\(\mathrm{CO}_3^{2-}\)) accepts the electrons, thus becoming an anion. These oppositely charged ions are held together strongly in a lattice structure due to their electrostatic attraction.
Charge Balance in Ionic Compounds
Charge balance in ionic compounds is a principle that states the total positive charge must equal the total negative charge to create a neutral compound. This is why we often see ions combining in certain ratios.

  • The formula \(\mathrm{Al(CH}_3\mathrm{COO})_3\) shows the aluminum cation \(\mathrm{Al}^{3+}\) balanced by three acetate anions \(\mathrm{CH}_3\mathrm{COO}^{-}\), where the charges in total sum to zero.
  • In \(\mathrm{(NH}_4\mathrm{)_2SO}_4\), two ammonium cations each with a charge of +1 balance a sulfate anion with a charge of -2.

Through charge balance, students can predict the proper stoichiometric amounts of ions necessary to form a specific ionic compound.
Polyatomic Ions
Polyatomic ions are charged entities composed of two or more covalently bonded atoms that function as a single ion. They can have a positive or negative charge, and like monatomic ions, are essential in the formation of ionic compounds.

When predicting formulas of ionic compounds with polyatomic ions, such as \(\mathrm{Mg}_3(\mathrm{PO}_4)_2\), it is crucial to recognize that these ions stay together as a group. The magnesium ion \(\mathrm{Mg}^{2+}\) balances the charge of the phosphate ion \(\mathrm{PO}_4^{3-}\) with a 3:2 ratio. Understanding polyatomic ions helps students handle more complex compounds beyond those formed by individual metal and non-metal ions.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

There are two different isotopes of bromine atoms. Under normal conditions, elemental bromine consists of \(\mathrm{Br}_{2}\) molecules, and the mass of a Br molecule is the sum of the masses of the two atoms in the molecule. The mass spectrum of \(\mathrm{Br}_{2}\) consists of three peaks: (a) What is the origin of each peak (of what isotopes does each consist)? (b) What is the mass of each isotope? (c) Determine the average molecular mass of a \(\mathrm{Br}_{2}\) molecule. (d) Determine the average atomic mass of a bromine atom. (e) Calculate the abundances of the two isotopes.

Millikan determined the charge on the electron by studying the static charges on oil drops falling in an electric field (Figure 2.5). A student carried out this experiment using several oil drops for her measurements and calculated the charges on the drops. She obtained the following data: (a) What is the significance of the fact that the droplets carried different charges? (b) What conclusion can the student draw from these data regarding the charge of the electron? (c) What value (and to how many significant figures) should she report for the electronic charge?

Gallium (Ga) consists of two naturally occurring isotopes with masses of \(68.926\) and \(70.925\) amu. (a) How many protons and neutrons are in the nucleus of each isotope? Write the complete atomic symbol for each, showing the atomic number and mass number. (b) The average atomic mass of Ga is \(69.72\) amu. Calculate the abundance of each isotope.

The explosion of an atomic bomb releases many radioactive isotopes, including strontium- 90 . Considering the location of strontium in the periodic table, suggest a reason for the fact that this isotope is particularly dangerous for human health.

The oxides of nitrogen are very important components in urban air pollution. Name each of the following compounds: (a) \(\mathrm{N}_{2} \mathrm{O}\), (b) \(\mathrm{NO}\), (c) \(\mathrm{NO}_{2}\), (d) \(\mathrm{N}_{2} \mathrm{O}_{5}\), (e) \(\mathrm{N}_{2} \mathrm{O}_{4}\).

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.