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Predict which member of each pair produces the more acidic aqueous solution: (a) \(\mathrm{K}^{+}\)or \(\mathrm{Cu}^{2+}\), (b) \(\mathrm{Fe}^{2+}\) or \(\mathrm{Fe}^{3+}\), (c) \(\mathrm{Al}^{3+}\) or \(\mathrm{Ga}^{3+}\).

Short Answer

Expert verified
In summary, the more acidic members of each pair are: (a) Cu虏鈦 produces a more acidic aqueous solution than K鈦 due to its higher charge and charge density. (b) Fe鲁鈦 is more acidic than Fe虏鈦 because it has a higher charge and stronger electrostatic attraction for water molecules. (c) Al鲁鈦 creates a more acidic aqueous solution than Ga鲁鈦 due to its smaller size and higher charge density.

Step by step solution

01

Understand acidity of ions

An aqueous solution of a cation (a positively charged ion) can be acidic if the cation can attract an electron pair from water and create a hydronium (H鈧僌鈦) ion. This process is called hydrolysis. Meanwhile, small and highly charged cations have a greater tendency to undergo hydrolysis since they have a higher charge density and stronger electrostatic attractions for water molecules. Thus, they produce more acidic solutions.
02

Comparing K鈦 and Cu虏鈦 acidity

From the periodic table, potassium (K) is from group 1 (alkali metals) and has a charge of +1 (K鈦). Copper (Cu) is from group 11 (transition metals) and has a charge of +2 (Cu虏鈦). Since Cu虏鈦 has a higher charge than K鈦, it has a higher charge density and a stronger electrostatic attraction for water molecules. The result is that Cu虏鈦 has a higher tendency for hydrolysis than K鈦. Therefore, Cu虏鈦 produces a more acidic aqueous solution.
03

Comparing Fe虏鈦 and Fe鲁鈦 acidity

In this case, we're comparing two different oxidation states of the same element (iron). Fe虏鈦 has a charge of +2, while Fe鲁鈦 has a charge of +3. Comparing their charges, Fe鲁鈦 has a higher charge, more charge density, and stronger electrostatic attraction for water molecules. Thus, Fe鲁鈦 has a higher tendency for hydrolysis and will produce a more acidic solution than Fe虏鈦.
04

Comparing Al鲁鈦 and Ga鲁鈦 acidity

Both aluminum (Al) and gallium (Ga) are in group 13 and have a charge of +3. Therefore, both Al鲁鈦 and Ga鲁鈦 have the same charge, and we need to compare their sizes to determine their charge density. Aluminum has a smaller atomic radius than gallium since it is above gallium in the periodic table. Smaller size means higher charge density, so Al鲁鈦 has a stronger electrostatic attraction for water molecules and a higher tendency to undergo hydrolysis. Therefore, Al鲁鈦 produces a more acidic aqueous solution than Ga鲁鈦. In summary, the more acidic members of each pair are: (a) Cu虏鈦 (b) Fe鲁鈦 (c) Al鲁鈦

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hydrolysis
Hydrolysis is a chemical process where a molecule interacts with water, often resulting in the breaking of chemical bonds and the formation of new molecules. In the context of metal ions, hydrolysis occurs when positively charged ions (cations) can attract electrons from water molecules. This interaction typically leads to the formation of hydronium ions \( \text{(H}_3\text{O}^+\text{)}\), thus increasing the acidity of the solution.
Cations that undergo hydrolysis tend to be smaller and have higher charges. These properties allow them to polarize surrounding water molecules more effectively, breaking the \( \text{H鈥揙} \) bonds and improving hydronium formation.
When ions such as \( \text{Cu}^{2+} \) or \( \text{Fe}^{3+} \) hydrolyze, they do so because their charge density and size promote interactions that favor water molecule dissociation. Consequently, understanding hydrolysis in metal ions involves recognizing how these ions manipulate water molecules to transition the solution towards acidity.
In summary:
  • Hydrolysis involves the interaction of water with metal ions.
  • Leads to the formation of \( \text{H}_3\text{O}^+ \) ions, increasing acidity.
  • Influenced by the ion's size and charge.
Charge Density
Charge density is a crucial concept to understand the acidity of metal ions. It describes how much electric charge is distributed over the space occupied by an ion. Higher charge density means that the charge is concentrated in a smaller area, which can lead to strong interactions with other charged or polar molecules, like water.
In essence, charge density is determined by two factors:
  • The magnitude of the charge: Ions with higher charges, such as \( \text{Fe}^{3+} \) compared to \( \text{Fe}^{2+} \), have higher charge densities.
  • The size of the ion: Smaller ions, such as \( \text{Al}^{3+} \) compared to \( \text{Ga}^{3+} \), have greater charge densities due to their compactness.
High charge density cations exert stronger force on the surrounding water molecules, enhancing the hydrolysis process. By polarizing the \( \text{H--O} \) bonds in water, the ions facilitate proton donation to solutions, increasing acidity. This concept is pivotal in comparing ions like \( \text{Cu}^{2+} \) and \( \text{K}^{+} \), where charge density differences explain varying acidities in solutions.
Electrostatic Attraction
Electrostatic attraction is the force that brings oppositely charged ions or polar molecules together. In the context of metal ion acidity, this attraction is vital as it underlies the ion's ability to influence water molecules.
Cations with higher charges, such as \( \text{Cu}^{2+} \) and \( \text{Fe}^{3+} \), exhibit stronger electrostatic attractions towards the partially negatively charged oxygen atoms in water. This attraction encourages the distortion of water molecule structures, facilitating hydrolysis.
Through electrostatic attraction:
  • Larger ion charges lead to greater attraction, promoting more substantial interactions with water.
  • This can result in a higher tendency for water molecules to dissociate into \( \text{H}_3\text{O}^+ \) ions, increasing the solution's acidity.
Overall, electrostatic attraction provides the driving force for the ion-water interactions that explain why certain metal ions lead to more acidic solutions. Understanding these attractions helps us predict acidity differences, such as more acidic solutions formed by \( \text{Cu}^{2+} \) over \( \text{K}^{+} \).

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Most popular questions from this chapter

Indicate whether each of the following statements is true or false. For each statement that is false, correct the statement to make it true. (a) In general, the acidity of binary acids increases from left to right in a given row of the periodic table. (b) In a series of acids that have the same central atom, acid strength increases with the number of hydrogen atoms bonded to the central atom. (c) Hydrotelluric acid ( \(\left.\mathrm{H}_{2} \mathrm{Te}\right)\) is a stronger acid than \(\mathrm{H}_{2} \mathrm{~S}\) because Te is more electronegative than \(\mathrm{S}\).

(a) Which of the following is the stronger Brensted-Lowry acid, HBrO or HBr? (b) Which is the stronger BrenstedLowry base, \(\mathrm{F}^{-}\)or \(\mathrm{Cl}^{-}\)?

The volume of an adult's stomach ranges from about \(50 \mathrm{~mL}\) when empty to \(1 \mathrm{~L}\) when full. If the stomach volume is \(400 \mathrm{~mL}\) and its contents have a pH of 2 , how many moles of \(\mathrm{H}^{+}\)does the stomach contain? Assuming that all the \(\mathrm{H}^{+}\)comes from \(\mathrm{HCl}\), how many grams of sodium hydrogen carbonate will totally neutralize the stomach acid?

Pyridinium bromide \(\left(\mathrm{C}_{5} \mathrm{H}_{5} \mathrm{NHBr}\right)\) is a strong electrolyte that dissociates completely into $\mathrm{C}_{5} \mathrm{H}_{5} \mathrm{NH}^{+}\( and \)\mathrm{Br}^{-}$. An aqueous solution of pyridinium bromide has a pH of \(2.95 .\) (a) Write out the reaction that leads to this acidic pH. (b) Using Appendix D, calculate the \(K_{a}\) for pyridinium bromide. (c) A solution of pyridinium bromide has a pH of 2.95 . What is the concentration of the pyridinium cation at equilibrium, in units of molarity?

Which member of each pair produces the more acidic aqueous solution: (a) \(\mathrm{ZnBr}_{2}\) or \(\mathrm{CdCl}_{2}\), (b) \(\mathrm{CuCl}\) or \(\mathrm{Cu}\left(\mathrm{NO}_{3}\right)_{2}\), (c) \(\mathrm{Ca}\left(\mathrm{NO}_{3}\right)_{2}\) or \(\mathrm{NiBr}_{2}\) ?

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