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If \(K_{c}=1\) for the equilibrium \(2 \mathrm{~A}(g) \rightleftharpoons \mathrm{B}(\mathrm{g})\), what is the relationship between \([A]\) and \([B]\) at equilibrium?

Short Answer

Expert verified
At equilibrium, the relationship between the concentrations of A and B in the given reaction is \([B] = [A]^2\).

Step by step solution

01

Write down the balanced chemical equation

For the given reaction, we have: \(2A(g) \rightleftharpoons B(g)\)
02

Write the expression for the equilibrium constant (K)

For a reversible reaction with the form \(aA(g) + bB(g) \rightleftharpoons cC(g) + dD(g)\), the equilibrium constant expression is: \[K = \frac{[C]^c [D]^d}{[A]^a [B]^b}\] In our case, the reaction is \(2A(g) \rightleftharpoons B(g)\), so the equilibrium constant expression becomes: \[K_c = \frac{[B]}{[A]^2}\]
03

Substitute the given value of the equilibrium constant

It is given that \(K_c = 1\), so we can substitute this value in our equilibrium constant expression: \[1 = \frac{[B]}{[A]^2}\]
04

Rearrange the equation to find the relationship between [A] and [B]

To find the relationship, we need to rearrange the equation to solve for one variable in terms of the other. Here, we will leave [B] on the left side and solve for [A] on the right side: \[[B] = [A]^2\]
05

Conclusion

At equilibrium, the relationship between the concentrations of A and B in the given reaction is \([B] = [A]^2\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Equilibrium Constant
The equilibrium constant, often denoted as \( K_c \), is a crucial concept in understanding chemical reactions that have reached equilibrium. It provides a quantitative measure of the ratio of concentrations of products to reactants for a given reaction at a set temperature. For a general reversible reaction of the form:\[ aA + bB \rightleftharpoons cC + dD \]The equilibrium constant expression is represented mathematically as:\[ K_c = \frac{[C]^c [D]^d}{[A]^a [B]^b} \]Knowing the value of \( K_c \) helps chemists predict how the concentration of different species in a reaction will relate to each other when the system reaches equilibrium.

A \( K_c \) value of 1, as seen in the example exercise, implies a balanced relationship where neither reactants nor products are favored at equilibrium. This means that the "forward" reaction from reactants to products, and the "reverse" reaction from products back to reactants, happen at comparable rates.
Concentration Relationship
Understanding the relationship between concentrations at equilibrium is key to mastering chemical equilibria. When given an equilibrium constant expression, such as:\[ K_c = \frac{[B]}{[A]^2} \]You can determine how the concentrations of the reactants and products interrelate. Substituting a known value for \( K_c \), such as 1, allows you to establish explicit concentration relationships. In this case:\[ 1 = \frac{[B]}{[A]^2} \]From rearranging this equation, it becomes apparent that:\[ [B] = [A]^2 \]This equation tells us that, at equilibrium, the concentration of \( B \) is the square of the concentration of \( A \).

In practical terms, for every unit increase in \([A]\), \([B]\) increases quadratically, emphasizing the power of balancing chemical equations and recognizing patterns.
Reversible Reactions
Reversible reactions are a central theme in chemical equilibrium, where both the forward and reverse processes occur. This duality leads to the establishment of a dynamic equilibrium where reaction rates, rather than concentrations, equalize. For example, in a reversible equation like\[ 2A \rightleftharpoons B \],both the formation of \( B \) from \( A \) and the reformation of \( A \) from \( B \) proceed simultaneously.

Characteristics of reversible reactions include:
  • Reaching a state where the concentrations of reactants and products remain constant over time.
  • Dependence on temperature, pressure, and concentration, which can shift the equilibrium position.
  • Reduction of observable changes, despite ongoing molecular interaction.
Understanding these processes is essential for predicting how changes to system conditions (such as pressure or concentration) might affect the position of equilibrium in a reversible reaction.

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Most popular questions from this chapter

Which of the following reactions lies to the right, favoring the formation of products, and which lies to the left, favoring formation of reactants? (a) \(2 \mathrm{NO}(g)+\mathrm{O}_{2}(g) \rightleftharpoons 2 \mathrm{NO}_{2}(g) ; K_{p}=5.0 \times 10^{12}\) (b) \(2 \mathrm{HBr}(g) \rightleftharpoons \mathrm{H}_{2}(g)+\mathrm{Br}_{2}(g) ; K_{c}=5.8 \times 10^{-18}\)

Which of the following statements are true and which are false? (a) The equilibrium constant can never be a negative number. (b) In reactions that we draw with a single-headed arrow, the equilibrium constant has a value that is very close to zero. (c) As the value of the equilibrium constant increases the speed at which a reaction reaches equilibrium increases.

As shown in Table 15.2, \(K_{p}\) for the equilibrium $$ \mathrm{N}_{2}(g)+3 \mathrm{H}_{2}(g) \rightleftharpoons 2 \mathrm{NH}_{3}(g) $$ is \(4.51 \times 10^{-5}\) at \(450^{\circ} \mathrm{C}\). For each of the mixtures listed here, indicate whether the mixture is at equilibrium at \(450^{\circ} \mathrm{C}\). If it is not at equilibrium, indicate the direction (toward product or toward reactants) in which the mixture must shift to achieve equilibrium. (a) \(98 \mathrm{~atm} \mathrm{} \mathrm{NH}_{3}, 45 \mathrm{~atm} \mathrm{~N}_{2}, 55 \mathrm{~atm} \mathrm{} \mathrm{H}_{2}\) (b) \(57 \mathrm{~atm} \mathrm{} \mathrm{NH}_{3}, 143 \mathrm{~atm} \mathrm{} \mathrm{N}_{2}\), no \(\mathrm{H}_{2}\) (c) \(13 \mathrm{~atm} \mathrm{NH}_{3}, 27\) atm \(\mathrm{N}_{2}, 82\) atm \(\mathrm{H}_{2}\)

Silver chloride, \(\mathrm{AgCl}(\mathrm{s})\), is an "insoluble" strong electrolyte. (a) Write the equation for the dissolution of \(\mathrm{AgCl}(s)\) in \(\mathrm{H}_{2} \mathrm{O}(l)\). (b) Write the expression for \(K_{c}\) for the reaction in part (a). (c) Based on the thermochemical data in Appendix \(C\) and Le Châtelier's principle, predict whether the solubility of \(\mathrm{AgCl}\) in \(\mathrm{H}_{2} \mathrm{O}\) increases or decreases with increasing temperature. (d) The equilibrium constant for the dissolution of \(\mathrm{AgCl}\) in water is \(1.6 \times 10^{-10}\) at \(25^{\circ} \mathrm{C}\). In addition, \(\mathrm{Ag}^{+}(a q)\) can react with \(\mathrm{Cl}^{-}(a q)\) according to the reaction $$ \mathrm{Ag}^{+}(a q)+2 \mathrm{Cl}^{-}(a q) \rightleftharpoons \mathrm{AgCl}_{2}^{-}(a q) $$ where \(K_{c}=1.8 \times 10^{5}\) at \(25^{\circ} \mathrm{C}\). Although \(\mathrm{AgCl}\) is "not soluble" in water, the complex \(\mathrm{AgCl}_{2}{ }^{\prime}\) is soluble. At \(25^{\circ} \mathrm{C}\), is the solubility of \(\mathrm{AgCl}\) in a \(0.100 \mathrm{M} \mathrm{NaCl}\) solution greater than the solubility of \(\mathrm{AgCl}\) in pure water, due to the formation of soluble \(\mathrm{AgCl}_{2}^{-}\)ions? Or is the \(\mathrm{AgCl}\) solubility in \(0.100 \mathrm{M} \mathrm{NaCl}\) less than in pure water because of a Le Châtelier-type argument? Justify your answer with calculations. (Hint: Any form in which silver is in solution counts as "solubility.")

How do the following changes affect the value of the equilibrium constant for a gas-phase exothermic reaction: (a) removal of a reactant, (b) removal of a product, (c) decrease in the volume, (d) decrease in the temperature, (e) addition of a catalyst?

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