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List the following aqueous solutions in order of decreasing freezing point: \(0.040 \mathrm{~m}\) glycerin \(\left(\mathrm{C}_{3} \mathrm{H}_{8} \mathrm{O}_{3}\right), 0.020 \mathrm{~m} \mathrm{KBr}\), \(0.030 \mathrm{~m}\) phenol \(\left(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{OH}\right)\).

Short Answer

Expert verified
The order of decreasing freezing point for the given aqueous solutions is: Phenol \(\left(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{OH}\right)\), Glycerin \(\left(\mathrm{C}_{3} \mathrm{H}_{8} \mathrm{O}_{3}\right)\), and Potassium Bromide \(\left(\mathrm{KBr}\right)\).

Step by step solution

01

Glycerin solution

Glycerin \(\left(\mathrm{C}_{3} \mathrm{H}_{8} \mathrm{O}_{3}\right)\) is a non-electrolyte, so it doesn't dissociate into ions in solution. Therefore, the effective number of particles for this solution is the given molality itself, which is \(0.040 \mathrm{~m}\).
02

Potassium Bromide solution

Potassium Bromide \(\left(\mathrm{KBr}\right)\) is an electrolyte and dissociates into one potassium ion \(\left(\mathrm{K}^+\right)\) and one bromide ion \(\left(\mathrm{Br}^-\right)\) when dissolved in water. Thus, the total effective number of particles would be twice the molality, which is \(0.020 \mathrm{~m} \times 2 = 0.040 \mathrm{~m}\).
03

Phenol solution

Phenol \(\left(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{OH}\right)\) is a weak electrolyte, which means it doesn't completely dissociate in solution. Since it's a weak acid, it's safe to assume that there is a negligible concentration of ions produced in the solution, so the total effective number of particles would be approximately equal to the given molality, which is \(0.030 \mathrm{~m}\). Step 2: Rank the solutions
04

Rank the solutions by decreasing freezing point

We find that the effective number of particles for the given solutions is as follows: - Glycerin: \|0.040 \mathrm{~m} \| - Potassium Bromide: \|0.040 \mathrm{~m} \| - Phenol: \|0.030 \mathrm{~m} \| As more particles in the solution cause a greater depression in the freezing point, we can compare the molalities of effective particles to rank the solutions by decreasing freezing point: 1. Phenol \(\left(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{OH}\right)\), \(0.030 \mathrm{~m}\) 2. Glycerin \(\left(\mathrm{C}_{3} \mathrm{H}_{8} \mathrm{O}_{3}\right)\), \(0.040 \mathrm{~m}\) 3. Potassium Bromide \(\left(\mathrm{KBr}\right)\), \(0.040 \mathrm{~m}\) So the order of decreasing freezing point is: phenol, glycerin, and then potassium bromide.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Colligative Properties
Colligative properties are characteristics of solutions that depend solely on the number of dissolved particles, not on their chemical identity. One common colligative property is freezing point depression, which is the lowering of a solvent's freezing point due to the presence of a solute.

In simple terms, when a substance like salt is dissolved in water, it disrupts the water's ability to form a solid lattice, which normally occurs when freezing. Therefore, it takes a colder temperature to cause the solvent molecules to enter the solid phase. The more particles you have in a solution (assuming ideal behavior), the more significant this effect becomes.

As seen in the textbook exercise, glycerin, potassium bromide, and phenol each have different effects on the freezing point of water due to their varying ability to release particles into the solution.
Molality
Molality is an important concentration measure in chemistry, defined as the number of moles of solute per kilogram of solvent. It's represented by the symbol 'm' and is particularly useful in colligative properties because it doesn't change with temperature.

The molality of a solution allows chemists to predict how much the presence of a solute will affect certain properties of the solvent, such as boiling point elevation and freezing point depression. It's different from molarity, which is the number of moles of solute per liter of solution, and can vary with temperature changes.

The exercise demonstrates how the molality is used to determine the extent of freezing point depression when it's applied to substances like glycerin, potassium bromide, and phenol in water.
Electrolyte and Non-Electrolyte Solutions
Solutions can be classified based on the ability of their solutes to conduct electricity when in a liquid state. Electrolytes are substances that dissolve in water to form solutions that conduct electricity, while non-electrolytes do not. Electrolyte solutions are crucial in many physiological processes and industrial applications.

Electrolytes, like potassium bromide in our exercise, dissociate into ions when dissolved, thus increasing the number of particles in the solution. In contrast, non-electrolytes, such as glycerin, do not dissociate and therefore do not increase the number of conductive particles. This distinction is vital for understanding not only chemical reactions but also colligative properties like freezing point depression.
Dissociation of Ions in Solution
The dissociation of ions in solution pertains to the breakdown of electrolytes into its constituent ions when dissolved. During this process, the solid crystal lattice of an ionic compound, such as potassium bromide, is overcome by the solvation power of the solvent molecules, leading to free-moving ions that can conduct electricity.

The extent of dissociation is governed by the nature of the electrolyte. Strong electrolytes, such as salts, acids, and bases, dissociate completely in solution, while weak electrolytes do not. In the given exercise, it was important to recognize the distinction between potassium bromide (a strong electrolyte) and phenol (a weak electrolyte). The former fully dissociates into potassium and bromide ions, thus having a profound effect on the freezing point of the solution.

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Most popular questions from this chapter

Indicate the type of solute-solvent interaction (Section 11.2) that should be most important in each of the following solutions: (a) \(\mathrm{CCl}_{4}\) in benzene \(\left(\mathrm{C}_{6} \mathrm{H}_{6}\right)\), (b) methanol \(\left(\mathrm{CH}_{3} \mathrm{OH}\right)\) in water, (c) \(\mathrm{KBr}\) in water, (d) \(\mathrm{HCl}\) in acetonitrile \(\left(\mathrm{CH}_{3} \mathrm{CN}\right)\).

(a) A sample of hydrogen gas is generated in a closed container by reacting \(2.050 \mathrm{~g}\) of zinc metal with \(15.0 \mathrm{~mL}\) of \(1.00 \mathrm{M}\) sulfuric acid. Write the balanced equation for the reaction, and calculate the number of moles of hydrogen formed, assuming that the reaction is complete. (b) The volume over the solution in the container is \(122 \mathrm{~mL}\). Calculate the partial pressure of the hydrogen gas in this volume at \(25^{\circ} \mathrm{C}\), ignoring any solubility of the gas in the solution. (c) The Henry's law constant for hydrogen in water at \(25^{\circ} \mathrm{C}\) is \(7.8 \times 10^{-4} \mathrm{~mol} / \mathrm{L}\)-atm. Estimate the number of moles of hydrogen gas that remain dissolved in the solution. What fraction of the gas molecules in the system is dissolved in the solution? Was it reasonable to ignore any dissolved hydrogen in part (b)? [13.111] The following table presents the solubilities of several gases in water at \(25^{\circ} \mathrm{C}\) under a total pressure of gas and water vapor of \(1 \mathrm{~atm}\). (a) What volume of \(\mathrm{CH}_{4}(\mathrm{~g})\) under standard conditions of temperature and pressure is contained in \(4.0 \mathrm{~L}\) of a saturated solution at \(25^{\circ} \mathrm{C}\) ? (b) Explain the variation in solubility among the hydrocarbons listed (the first three compounds), based on their molecular structures and intermolecular forces. (c) Compare the solubilities of \(\mathrm{O}_{2}, \mathrm{~N}_{2}\), and \(\mathrm{NO}\), and account for the variations based on molecular structures and intermolecular forces. (d) Account for the much larger values observed for \(\mathrm{H}_{2} \mathrm{~S}\) and \(\mathrm{SO}_{2}\) as compared with the other gases listed. (e) Find several pairs of substances with the same or nearly the same molecular masses (for example, \(\mathrm{C}_{2} \mathrm{H}_{4}\) and \(\mathrm{N}_{2}\) ), and use intermolecular interactions to explain the differences in their solubilities.

(a) Would you expect stearic acid, \(\mathrm{CH}_{3}\left(\mathrm{CH}_{2}\right)_{16} \mathrm{COOH}_{\text {, to be }}\) more soluble in water or in carbon tetrachloride? Explain. (b) Which would you expect to be more soluble in water, cyclohexane or dioxane? Explain.

What is the freezing point of an aqueous solution that boils at \(105.0^{\circ} \mathrm{C}\) ?

By referring to Figure 13.15, determine whether the addition of \(40.0 \mathrm{~g}\) of each of the following ionic solids to \(100 \mathrm{~g}\) of water at \(40^{\circ} \mathrm{C}\) will lead to a saturated solution: (a) \(\mathrm{NaNO}_{3}\), (b) \(\mathrm{KCl}_{\text {, }}\) (c) \(\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}\), (d) \(\mathrm{Pb}\left(\mathrm{NO}_{3}\right)_{2}\)

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