/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 73 A quantity of \(\mathrm{N}_{2}\)... [FREE SOLUTION] | 91影视

91影视

A quantity of \(\mathrm{N}_{2}\) gas originally held at \(5.25 \mathrm{~atm}\) pressure in a \(1.00\) - \(\mathrm{L}\) container at \(26^{\circ} \mathrm{C}\) is transferred to a \(12.5\) - \(\mathrm{L}\) container at \(20^{\circ} \mathrm{C}\). A quantity of \(\mathrm{O}_{2}\) gas originally at \(5.25\) atm and \(26^{\circ} \mathrm{C}\) in a \(5.00\)-L container is transferred to this same container. What is the total pressure in the new container?

Short Answer

Expert verified
The total pressure in the new container after transferring both N鈧 and O鈧 gases is \(2.53\,\mathrm{atm}\).

Step by step solution

01

Write down given information and the ideal gas law

Write down the information given in the problem and the ideal gas law, which is \(PV = nRT\). We have the initial conditions for N鈧 gas (V鈧(N鈧), T鈧(N鈧), and P鈧(N鈧)) and O鈧 gas (V鈧(O鈧), T鈧(O鈧), and P鈧(O鈧)). We also have the final volume (V鈧) and final temperature (T鈧) for both gases after they have been transferred to the new container.
02

Convert temperature to Kelvin

Convert the given temperatures from degrees Celsius to Kelvin by adding 273.15 to the given values. This is important because the ideal gas law uses Kelvin as the unit for temperature. T鈧(N鈧) = \(26 + 273.15 = 299.15\,\mathrm{K}\) T鈧 = \(20 + 273.15 = 293.15\,\mathrm{K}\)
03

Calculate moles of N鈧 and O鈧 using the ideal gas law

Use the ideal gas law to calculate the number of moles for N鈧 and O鈧. We can rearrange the equation to find moles (n): n = \(\frac{PV}{RT}\) n(N鈧) = \(\frac{P鈧(N鈧) V鈧(N鈧)}{R T鈧(N鈧)} = \frac{5.25\,\mathrm{atm} \times 1.00\,\mathrm{L}}{0.0821\,\mathrm{L\,atm/mol\,K} \times 299.15\,\mathrm{K}} = 0.217\,\mathrm{mol}\) n(O鈧) = \(\frac{P鈧(O鈧) V鈧(O鈧)}{R T鈧(O鈧)} = \frac{5.25\,\mathrm{atm} \times 5.00\,\mathrm{L}}{0.0821\,\mathrm{L\,atm/mol\,K} \times 299.15\,\mathrm{K}} = 1.086\,\mathrm{mol}\)
04

Calculate total moles, nTotal

Sum the moles of the two gases to get the total number of moles: nTotal = n(N鈧) + n(O鈧) = 0.217 + 1.086 = 1.303\,\mathrm{mol}
05

Calculate total pressure in the new container using the ideal gas law

We have the total moles (nTotal), final volume (V鈧), and final temperature (T鈧), so we can plug these values into the ideal gas law and solve for the new pressure (P鈧): \(P鈧俈鈧 = n_\text{Total} R T鈧俓) Rearrange the equation to find the new pressure (P鈧): \(P鈧 = \frac{n_\text{Total} R T鈧倉{V鈧倉 = \frac{1.303\,\mathrm{mol} \times 0.0821\,\mathrm{L\,atm/mol\,K} \times 293.15\,\mathrm{K}}{12.5\,\mathrm{L}} = 2.53\,\mathrm{atm}\) The total pressure in the new container is 2.53 atm.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Gas Pressure
Gas pressure is a fundamental concept in the study of gases. It is the force that the gas exerts on the walls of its container, and it is a result of gas particles colliding with the container's surfaces. The more frequent and forceful these collisions, the higher the pressure. When solving problems involving gas pressure, it's important to understand that pressure can be affected by factors such as volume, temperature, and the amount of gas present.

In the given exercise, we dealt with two gases, \(\mathrm{N}_{2}\) and \(\mathrm{O}_{2}\), each at an initial pressure of 5.25 atm, which later combined in a new container, leading to a change in the total pressure. The Ideal Gas Law was used to determine this change and find the final pressure in the new container. It is crucial to convert the given temperatures to Kelvin since the Ideal Gas Law requires temperature in absolute units (Kelvin) and defines zero volume at zero Kelvin.
The Process of Moles Calculation
Calculating moles of a gas is crucial when working with chemical reactions and gas laws. The mole is a unit of measurement for the amount of substance. In chemistry, it represents Avogadro's number (approximately \(6.022 \times 10^{23}\)) of molecules or atoms. When you know the pressure, volume, and temperature of a gas, you can use the Ideal Gas Law \(PV = nRT\) to calculate the number of moles (n).

In the exercise, the number of moles for \(\mathrm{N}_{2}\) and \(\mathrm{O}_{2}\) were calculated using the initial conditions before the gases were combined. These calculations are essential because they help us understand how much of each gas is present, which in turn determines the final gas pressure after combining them in a new volume. This mole calculation is a key step in solving many problems in chemistry and provides the link between the macroscopic properties we can measure and the microscopic events happening with individual gas particles.
Applying Gas Laws
Gas laws explain how gases behave under different conditions of temperature, pressure, and volume. The Ideal Gas Law is one of the most important equations in this field as it combines several individual gas laws, including Boyle's Law, Charles's Law, and Avogadro's Law. It is represented as \(PV = nRT\), where P is pressure, V is volume, n is the amount of substance in moles, R is the universal gas constant, and T is temperature in Kelvin.

To tackle problems involving changes in gas conditions, a clear comprehension of these laws and proper application of the Ideal Gas Law is essential. In the exercise, the total pressure in a new container after transferring \(\mathrm{N}_{2}\) and \(\mathrm{O}_{2}\) gases was found by first applying the Ideal Gas Law to each gas to find the number of moles, then adding these moles to find the total. Finally, the gas law was used again with the total moles, new volume, and temperature to find the total pressure. It demonstrates the utility of grasping these gas laws to predict the behavior of gases in a variety of situations.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In the Dumas-bulb technique for determining the molar mass of an unknown liquid, you vaporize the sample of a liquid that boils below \(100^{\circ} \mathrm{C}\) in a boiling-water bath and determine the mass of vapor required to fill the bulb. From the following data, calculate the molar mass of the unknown liquid: mass of unknown vapor, \(1.012 \mathrm{~g}\); volume of bulb, \(354 \mathrm{~cm}^{3}\); pressure, 742 torr; temperature, \(99^{\circ} \mathrm{C}\).

A piece of dry ice (solid carbon dioxide) with a mass of \(5.50 \mathrm{~g}\) is placed in a \(10.0\) - \(L\) vessel that already contains air at 705 torr and \(24^{\circ} \mathrm{C}\). After the carbon dioxide has totally sublimed, what is the partial pressure of the resultant \(\mathrm{CO}_{2}\) gas, and the total pressure in the container at \(24^{\circ} \mathrm{C}\) ?

A scuba diver's tank contains \(0.29 \mathrm{~kg}\) of \(\mathrm{O}_{2}\) compressed into a volume of \(2.3 \mathrm{~L}\) (a) Calculate the gas pressure inside the tank at \(9^{\circ} \mathrm{C}\). (b) What volume would this oxygen occupy at \(26^{\circ} \mathrm{C}\) and \(0.95 \mathrm{~atm}\) ?

A plasma-screen TV contains thousands of tiny cells filled with a mixture of Xe, Ne, and He gases that emits light of specific wavelengths when a voltage is applied. A particular plasma cell, \(0.900 \mathrm{~mm} \times 0.300 \mathrm{~mm} \times 10.0 \mathrm{~mm}\), contains \(4 \%\) Xe in a 1:1 Ne:He mixture at a total pressure of 500 torr. Calculate the number of Xe, Ne, and He atoms in the cell and state the assumptions you need to make in your calculation.

An aerosol spray can with a volume of \(250 \mathrm{~mL}\) contains \(2.30 \mathrm{~g}\) of propane gas \(\left(\mathrm{C}_{3} \mathrm{H}_{8}\right)\) as a propellant. (a) If the can is at \(23{ }^{\circ} \mathrm{C}\), what is the pressure in the can? (b) What volume would the propane occupy at STP? (c) The can's label says that exposure to temperatures above \(130^{\circ} \mathrm{F}\) may cause the can to burst. What is the pressure in the can at this temperature?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.