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Consider the apparatus shown in the following drawing. (a) When the valve between the two containers is opened and the gases allowed to mix, how does the volume occupied by the \(\mathrm{N}_{2}\) gas change? What is the partial pressure of \(\mathrm{N}_{2}\) after mixing? (b) How does the volume of the \(\mathrm{O}_{2}\) gas change when the gases mix? What is the partial pressure of \(\mathrm{O}_{2}\) in the mixture? (c) What is the total pressure in the container after the gases mix?

Short Answer

Expert verified
When the valve between the two containers is opened and the gases mix, the volume occupied by the N2 gas remains the same, as the total volume of the container is unchanged. The partial pressure of N2 after mixing is \(P_{N_2}' = x_{N_2} P\), where \(x_{N_2}\) is the mole fraction of N2 and P is the total pressure of the mixture. Similarly, the volume occupied by the O2 gas remains the same when the gases mix. The partial pressure of O2 after mixing is \(P_{O_2}' = x_{O_2}P\), where \(x_{O_2}\) is the mole fraction of O2. The total pressure in the container after the gases mix is given by the sum of the partial pressures of N2 and O2: \(P_{total} = P_{N_2}' + P_{O_2}'\).

Step by step solution

01

Analyze the initial conditions for both gases

Initially, both the gases are in separate containers. We'll need to find the volume occupied by each gas before mixing. Let's denote the initial volume of N2 gas as \(V_{N_2}\) and the initial volume of O2 gas as \(V_{O_2}\). The initial volume can be found using the ideal gas law: \[ PV = nRT \] where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.
02

Calculate the initial volumes of N2 and O2

Using the ideal gas law, we can find the initial volumes occupied by each gas: \(V_{N_2} = \frac{n_{N_2}RT}{P_{N_2}}\) \(V_{O_2} = \frac{n_{O_2}RT}{P_{O_2}}\)
03

Analyze the gas mixture

When the two gases are mixed, the total volume V of the container remains the same. So, the volume occupied by each gas remains the same. The partial pressures of the gases will change, based on the mole fractions of the gases in the mixture. We can use the following formula for partial pressures: \(P_i = x_iP\) where \(P_i\) is the partial pressure of the gas i, \(x_i\) is the mole fraction of the gas i, and P is the total pressure.
04

Calculate the partial pressure of N2 after mixing

The mole fraction of N2 gas, \(x_{N_2}\), is given by: \(x_{N_2} = \frac{n_{N_2}}{n_{N_2} + n_{O_2}}\) The total pressure of the mixture P can be found using the ideal gas law for the overall mixture: \(P = \frac{(n_{N_2} + n_{O_2})RT}{V}\) The partial pressure of N2 gas, \(P_{N_2}'\), is given by: \(P_{N_2}' = x_{N_2} P\)
05

Calculate the partial pressure of O2 after mixing

The mole fraction of O2 gas, \(x_{O_2}\), is given by: \(x_{O_2} = \frac{n_{O_2}}{n_{N_2} + n_{O_2}}\) The partial pressure of O2 gas, \(P_{O_2}'\), is given by: \(P_{O_2}' = x_{O_2}P\)
06

Calculate the total pressure in the container after the gases mix

The total pressure of the mixture after mixing can be found by summing the partial pressures of N2 and O2: \(P_{total} = P_{N_2}' + P_{O_2}'\) This is the final answer for the total pressure in the container after the gases mix.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Partial Pressure
When multiple gases are mixed in a container, each gas exerts its own pressure as if it were alone. This is what we call partial pressure.

For example, if you mix nitrogen (\(N_2\)) and oxygen (\(O_2\)) in a container, the gases don't change their volume, but each exerts individual pressure. We calculate this using the formula:

\[P_i = x_iP\]
where \\(P_i\)\ is the partial pressure of a specific gas, \\(x_i\)\ is the mole fraction, and \(P\)\ is the total pressure of the mixture.

This means each gas's pressure depends on its proportion in the mixture. Partial pressure is crucial for understanding how different gases contribute to the total pressure in a system.
Mole Fraction
The mole fraction is a way to express the concentration of a specific gas in a mixture. It's calculated by comparing the moles of one gas to the total moles in the mixture.
It's expressed as \[x_i = \frac{n_i}{n_{total}}\]
where \\(n_i\)\ is the moles of a particular gas, and \\(n_{total}\)\ is the total moles of all gases combined in the mixture.

The mole fraction has no units, making it a simple ratio.
Using mole fraction makes it easy to determine the partial pressure when combining gases, since it represents each gas's share of the total number of particles in the mixture.
  • Mole fraction allows us to focus on the relative quantities of gases.
  • This concept helps in further calculations, like partial pressures and reactions involving gases.
Gas Mixture
A gas mixture is created when different gases are combined in the same container, like our nitrogen and oxygen example. When mixed, each gas occupies the total container volume, but they do not influence each other’s behavior. This happens because gas particles are far apart, allowing free movement.

The gas mixture's behavior is predicted by combining the properties of the individual gases. When mixing gases:
  • The temperature remains constant.
  • Each gas acts as if it were alone.
  • The volume occupied by each gas is the volume of the container.

Mixing gases doesn't change their individual characteristics, such as volume or pressure exerted. Instead, it allows us to study their collective properties and impacts.
Dalton's Law of Partial Pressures
Dalton's Law of Partial Pressures helps explain how gas mixtures behave. It states that the total pressure of a gas mixture equals the sum of the partial pressures of each individual gas.
Expressed as \[P_{total} = P_1 + P_2 + P_3 + ... + P_n\]
where each \(P\)\ is the partial pressure of a gas.

Dalton’s Law is immensely helpful when calculating how different gases contribute to a mixture’s total pressure in a container. Each gas's pressure remains unaffected by the presence of other gases. This principle allows chemists to predict and balance how gases will interact in mixtures.

By understanding Dalton's Law, one can efficiently calculate the pressures in any gas system, which is crucial in both experimental and theoretical chemistry contexts.

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Most popular questions from this chapter

Arsenic(III) sulfide sublimes readily, even below its melting point of \(320^{\circ} \mathrm{C}\). The molecules of the vapor phase are found to effuse through a tiny hole at \(0.28\) times the rate of effusion of Ar atoms under the same conditions of temperature and pressure. What is the molecular formula of arsenic(III) sulfide in the gas phase?

Determine whether each of the following changes will increase, decrease, or not affect the rate with which gas molecules collide with the walls of their container: (a) increasing the volume of the container, (b) increasing the temperature, (c) increasing the molar mass of the gas.

Acetylene gas, \(\mathrm{C}_{2} \mathrm{H}_{2}(g)\), can be prepared by the reaction of calcium carbide with water: $$ \mathrm{CaC}_{2}(s)+2 \mathrm{H}_{2} \mathrm{O}(l) \longrightarrow \mathrm{Ca}(\mathrm{OH})_{2}(a q)+\mathrm{C}_{2} \mathrm{H}_{2}(g) $$ Calculate the volume of \(\mathrm{C}_{2} \mathrm{H}_{2}\) that is collected over water at \(23{ }^{\circ} \mathrm{C}\) by reaction of \(1.524 \mathrm{~g}\) of \(\mathrm{CaC}_{2}\) if the total pressure of the gas is 753 torr. (The vapor pressure of water is tabulated in Appendix B.)

The temperature of a \(5.00-\mathrm{L}\) container of \(\mathrm{N}_{2}\) gas is increased from \(20^{\circ} \mathrm{C}\) to \(250^{\circ} \mathrm{C}\). If the volume is held constant, predict qualitatively how this change affects the following: (a) the average kinetic energy of the molecules; (b) the root- meansquare speed of the molecules; (c) the strength of the impact of an average molecule with the container walls; (d) the total number of collisions of molecules with walls per second.

A fixed quantity of gas at \(21^{\circ} \mathrm{C}\) exhibits a pressure of 752 torr and occupies a volume of \(5.12 \mathrm{~L}\). (a) Calculate the volume the gas will occupy if the pressure is increased to \(1.88 \mathrm{~atm}\) while the temperature is held constant. (b) Calculate the volume the gas will occupy if the temperature is increased to \(175^{\circ} \mathrm{C}\) while the pressure is held constant.

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