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Chlorine is widely used to purify municipal water supplies and to treat swimming pool waters. Suppose that the volume of a particular sample of \(\mathrm{Cl}_{2}\) gas is \(8.70 \mathrm{~L}\) at 895 torr and \(24^{\circ} \mathrm{C}\). (a) How many grams of \(\mathrm{Cl}_{2}\) are in the sample? (b) What volume will the \(\mathrm{Cl}_{2}\) occupy at STP? (c) At what temperature will the volume be \(15.00 \mathrm{~L}\) if the pressure is \(8.76 \times 10^{2}\) torr? (d) At what pressure will the volume equal \(5.00 \mathrm{~L}\) if the temperature is \(58^{\circ} \mathrm{C}\) ?

Short Answer

Expert verified
In summary, (a) there are about 20.22 grams of Cl₂ in the sample, (b) the volume of Cl₂ at STP is approximately 6.378 L, (c) the required temperature when the volume is 15.00 L is about 496.48°C, and (d) the required pressure when the volume is 5.00 L and the temperature is 58°C is approximately 3900 torr.

Step by step solution

01

Write the Ideal Gas Law equation

In order to find the mass of Clâ‚‚ gas, we need to find the number of moles first, then multiply it by the molar mass of Clâ‚‚. We will be using the Ideal Gas Law to find the number of moles: \(PV = nRT\)
02

Plug the known values into the equation

We have the values of the pressure, volume, and temperature in the exercise: Pressure (P) = 895 torr Volume (V) = 8.70 L Temperature (T) = 24°C We need the temperature in Kelvin and the pressure in atm. Convert them as follows: \(T_{K} = T_{C} + 273.15 = 24 + 273.15 = 297.15 K\) \(P_{atm} = P_{torr} \times \frac{1}{760} = 895 \times \frac{1}{760} = 1.17763 atm\) The constant R is given as \(0.0821 \frac{L \cdot atm}{K \cdot mol}\). Now, plug all the values into the Ideal Gas Law: \(PV = nRT \Rightarrow 1.17763 \times 8.70 = n \times 0.0821 \times 297.15\)
03

Calculate the number of moles

Solve for 'n' (moles of Clâ‚‚) in the equation: \(n = \frac{1.17763 \times 8.70}{0.0821 \times 297.15} = 0.28515 mol\)
04

Calculate the mass of Clâ‚‚

Use the molar mass of Cl₂ (≈ 70.9 g/mol) to find the mass of the Cl₂ gas sample: Mass = moles x molar mass Mass = 0.28515 mol x 70.9 g/mol = 20.22 g So, there are approximately 20.22 g of Cl₂ in the sample. #b) Find the volume of Cl₂ at STP#
05

Calculate volume at STP

At STP (Standard Temperature and Pressure), the temperature is 273.15 K and the pressure is 1 atm. Using the Ideal Gas Law, solve for V with the values of n from step 3: \(PV = nRT \Rightarrow V = \frac{nRT}{P} = \frac{0.28515 \times 0.0821 \times 273.15}{1} = 6.378~L\) The volume of Clâ‚‚ at STP is approximately 6.378 L. #c) Find the temperature when the volume is 15.00 L#
06

Calculate temperature when volume is 15.00 L

Pressure given = \(8.76 \times 10^{2}\) torr. Convert to atm. \(P =8.76 \times 10^{2}torr \times \frac{1}{760} = 11.54 atm\) Now, use the Ideal Gas Law with the given pressure, volume, and moles from Step 3: \(PV = nRT \Rightarrow T = \frac{PV}{nR} = \frac{11.54 \times 15.00}{0.28515 \times 0.0821} = 769.628 K\) Convert the result to Celsius: \( T_{C} = T_{K} - 273.15 = 769.63 - 273.15 = 496.48 °C \) The required temperature when the volume is 15.00 L is approximately 496.48°C. #d) Find the pressure when the volume is 5.00 L and the temperature is 58°C#
07

Calculate pressure when volume is 5.00 L

Convert the given temperature to Kelvin: \(T_{K} = T_{C} + 273.15 = 58 + 273.15 = 331.15 K\) Use the Ideal Gas Law with the given temperature, volume, and moles from Step 3: \(PV = nRT \Rightarrow P = \frac{nRT}{V} = \frac{0.28515 \times 0.0821 \times 331.15}{5.00} = 5.1316 atm\) Finally, convert the pressure to torr: \(P_{torr} = P_{atm} \times 760 = 5.1316 \times 760 = 3899.99 torr\) The required pressure when the volume is 5.00 L, and the temperature is 58°C is approximately 3900 torr.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Moles of Gas
Understanding the quantity of a gas in a chemical equation or a physical process is often represented in terms of 'moles of gas'. A mole reflects Avogadro's number, which is approximately 6.022 x 1023 molecules or atoms, and is a central concept in chemistry that allows chemists to count particles by weighing them. When dealing with gases, knowing the moles allows us to relate volume, pressure, and temperature with one another through the Ideal Gas Law.

For instance, in our example problem, to find the mass of the Cl2 gas, you must first calculate the number of moles using the Ideal Gas Law. Once we have the moles, it becomes feasible to convert this information into a mass by multiplying it by the molar mass, which is the next concept we'll discuss.
Molar Mass
Molar mass is essentially the weight of one mole of a substance, typically expressed in grams per mole (g/mol). Scientifically, molar mass allows us to convert moles to grams, a useful metric for quantitative analysis in the lab or industry. The molar mass of Cl2, for example, is about 70.9 g/mol, which means every mole of Cl2 weighs 70.9 grams.

In our problem scenario, after calculating the moles of Cl2, we used its molar mass to find the total mass of chlorine in the sample. This simple multiplication bridges the microscopic world of atoms and molecules with the macroscopic world we can measure and observe.
Standard Temperature and Pressure (STP)
Standard Temperature and Pressure (STP) is a common reference point in chemistry to report the properties of gases. At STP, the temperature is set at 0°C (273.15 K) and the pressure at 1 atm. Conditions at STP are used to simplify calculations and experiments because, under these conditions, one mole of an ideal gas occupies 22.4 liters.

Stated in our exercise, the volume of Cl2 at STP could be found by rearranging the Ideal Gas Law. Since the number of moles remains the same, we are able to predict how the volume of a gas sample will change when brought to these standard conditions.
Gas Law Conversions
Converting between different units for pressure, temperature, and volume is critical in solving gas law problems. In our exercise, we converted temperature from Celsius to Kelvin because the Ideal Gas Law requires absolute temperature. Similarly, pressure needed to be converted from torr to atmospheres (atm), as the universal gas constant R value we used (0.0821 L*atm/K*mol) is based on atm.

Understanding how to properly perform these conversions is essential because incorrect unit usage could lead to inaccurate results. Furthermore, these conversions echo one of chemistry's most fundamental truths: conditions matter. Change the conditions (pressure, volume, temperature), and you change the behavior of the gas.
Gas Volume and Temperature Relationship
Gas volume and temperature share a direct relationship, described by Charles's Law, which states that at constant pressure, the volume of a given mass of an ideal gas is directly proportional to its temperature (in Kelvin). This principle was applied in our problem to find the unknown temperature when the gas volume increased to 15.00 L.

Understanding this relationship, we can predict that as the temperature of a gas increases, the volume will also increase if the pressure remains constant. Conversely, lowering the temperature of a gas will decrease its volume. This relationship is important for applications that involve gas heating or cooling – like automotive engines or refrigeration systems – and helps us to further comprehend the dynamic behavior of gases under varying temperatures.

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Most popular questions from this chapter

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