/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 22 A match is lit and held under a ... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 1: Problem 22

A match is lit and held under a cold piece of metal. The following observations are made: (a) The match burns. (b) The metal gets warmer. (c) Water condenses on the metal. (d) Soot (carbon) is deposited on the metal. Which of these occurrences are due to physical changes, and which are due to chemical changes?

Short Answer

Expert verified
Observations (a) and (d) are chemical changes as they involve the formation of new substances. In (a), the match burns, forming water vapor and carbon dioxide, and in (d), soot (carbon) is deposited on the metal. Observations (b) and (c) are physical changes, as the metal getting warmer and water condensing on the metal do not involve the formation of new substances.

Step by step solution

01

Observation (a): The match burns

Burning is a chemical change as it involves the formation of new substances. In this case, when the match burns, it reacts with oxygen in the air and forms water vapor and carbon dioxide, both of which are new substances with different properties from the original match.
02

Observation (b): The metal gets warmer

The metal getting warmer is a physical change. This is because no new substances are formed, and the changes in temperature are only temporary. The identity of the metal remains the same, it just has more energy in the form of heat.
03

Observation (c): Water condenses on the metal

Water condensation on the metal is a physical change. This is because the water is simply changing states (from gas to liquid) due to the temperature difference between the metal and the surrounding air. The identity of the water does not change in this process.
04

Observation (d): Soot (carbon) is deposited on the metal

Soot deposition is a chemical change. During the combustion of the match, carbon is produced as a byproduct, and this is deposited onto the metal. Carbon is a new substance with different properties from the original match and oxygen in the air, thus, it is a chemical change. In summary, Observations (a) and (d) are chemical changes, while Observations (b) and (c) are physical changes.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

You are hiking in the mountains and find a shiny gold nugget. It might be the element gold, or it might be "fool's gold," which is a nickname for iron pyrite, FeS \(_{2 .}\) Which of the fol- lowing physical properties do you think would help determine if the shiny nugget is really gold appearance, melting point, density, or physical state?

Using your knowledge of metric units, English units, and the information on the back inside cover, write down the conversion factors needed to convert (a) \(\mu \mathrm{m}\) to \(\mathrm{mm}\), (b) \(\mathrm{ms}\) to \(\mathrm{ns}\), (c) \(\mathrm{mi}\) to \(\mathrm{km},(\mathrm{d}) \mathrm{ft}^{3}\) to \(\mathrm{L}\)

A \(25.0-\mathrm{cm}\) long cylindrical glass tube, sealed at one end, is filled with ethanol. The mass of ethanol needed to fill the tube is found to be \(45.23 \mathrm{~g}\). The density of ethanol is \(0.789 \mathrm{~g} / \mathrm{mL}\). Calculate the inner diameter of the tube in centimeters.

By using estimation techniques, determine which of the following is the heaviest and which is the lightest: a 5-lb bag of potatoes, a 5-kg bag of sugar, or \(1 \mathrm{gal}\) of water (density \(=1.0 \mathrm{~g} / \mathrm{mL}\) ).

In the United States, water used for irrigation is measured in acre-feet. An acre-foot of water covers an acre to a depth of exactly \(1 \mathrm{ft}\). An acre is \(4840 \mathrm{yd}^{2}\). An acre-foot is enough water to supply two typical households for \(1.00 \mathrm{yr}\). (a) If desalinated water costs \(\$ 1950\) per acre-foot, how much does desalinated water cost per liter? (b) How much would it cost one household per day if it were the only source of water?
See all solutions

Recommended explanations on Chemistry Textbooks

Chemistry Branches

Read Explanation

Nuclear Chemistry

Read Explanation

Making Measurements

Read Explanation

Kinetics

Read Explanation

Physical Chemistry

Read Explanation

Ionic and Molecular Compounds

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.