/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 115 The previous exercise shows how ... [FREE SOLUTION] | 91Ó°ÊÓ

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The previous exercise shows how the first-order integrated rate law is derived from the first-order differential rate law. Begin with the second-order differential rate law and derive the second-order integrated rate law.

Short Answer

Expert verified
The second-order integrated rate law is \( \frac{1}{[A]} = kt + \frac{1}{[A]_0} \), obtained by rearranging and integrating the differential rate law \( \frac{d[A]}{dt} = -k[A]^2 \) and applying initial conditions.

Step by step solution

01

Start with the Second-Order Differential Rate Law

The second-order differential rate law for a reaction where a single reactant A decreases in concentration over time can be expressed as \( \frac{d[A]}{dt} = -k[A]^2 \), where \( [A] \) is the concentration of A, \( t \) is time, and \( k \) is the rate constant.
02

Separate Variables

To integrate this expression, we need to separate the variables. This means rearranging the equation to isolate \( [A] \) on one side and \( t \) on the other side: \( \frac{d[A]}{[A]^2} = -k dt \).
03

Integrate Both Sides

Now integrate both sides with respect to their variables. The left side with respect to \( [A] \) and the right side with respect to \( t \). The result is \( -\frac{1}{[A]} = -kt + C \) where C is the integration constant.
04

Determine the Integration Constant

To determine the integration constant \( C \) we use the initial concentration of A at time \( t=0 \), often denoted as \( [A]_0 \). Plugging in these initial conditions yields \( -\frac{1}{[A]_0} = C \).
05

Combine Constants and Solve for \( [A] \)

Substitute the value of \( C \) into the integrated equation to get \( -\frac{1}{[A]} = -kt - \frac{1}{[A]_0} \). Finally, we solve for \( [A] \) to obtain the second-order integrated rate law: \( \frac{1}{[A]} = kt + \frac{1}{[A]_0} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Kinetics
Chemical kinetics is the area of chemistry that concerns the rates at which chemical reactions occur. It's not simply about knowing that reactions happen, but how fast they go and what factors affect this speed.

For instance, consider how quickly an effervescent tablet dissolves in water compared to a sugar cube. This difference in rates is what chemical kinetics explores at a molecular level. Understanding kinetics can help chemists to design reactions that are more efficient, which is particularly important in industries such as pharmaceuticals where reaction speed can influence the production rate of a drug.

In the context of second-order reactions, kinetics becomes even more interesting. A second-order reaction depends on the concentration of one reactant squared or on the concentrations of two reactants, each raised to the first power. This means that the rate at which reactants are consumed and products are formed can change dramatically as the reaction progresses.
Rate Constant
The rate constant, denoted as 'k' in chemical equations, is a proportionality constant that links the rate of a reaction to the concentrations of the reactants. Different reactions have different rate constants, which are determined experimentally.

The value of 'k' provides a wealth of information. High values suggest that the reaction proceeds quickly, while low values indicate a slower process. However, it's not just about the numerical value; the units of 'k' also tell us the order of the reaction. For a second-order reaction, the units of 'k' will incorporate the inverse of both concentration and time, such as L/mol·s, reflecting the squared concentration term in the rate law.

The rate constant is unaffected by the concentration of the reactants but can be influenced by external factors such as temperature. This concept is encapsulated in the Arrhenius equation, which is beyond the scope of this article, but it’s essential to recognize that 'k' is a keystone in understanding the kinetics of a reaction.
Reactant Concentration
The concentration of reactants in a chemical reaction is a crucial factor that dictates the reaction rate. Particularly in second-order reactions, the rate is directly proportional to the square of the concentration of one reactant or to the product of the concentrations of two reactants.

Deciphering the concentration of a reactant at various points in time allows chemists to plot concentration graphs and determine the kinetics of the reaction. In the case of second-order reactions, a plot of the inverse of concentration (\( \frac{1}{[A]} \) vs. time) leads to a straight line. This linearity is a signature of second-order kinetics.

As the reaction proceeds, the concentration of reactants decreases, which in turn affects the rate. For a second-order reaction, as you halve the concentration of the reactant, you'd observe that the rate drops to a quarter of its original value, reflective of the squared relationship in the rate law. This sensitivity to concentration changes is why monitoring and understanding reactant concentration is so important in chemical kinetics.

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