/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 92 A solution contains 8.92 g of KB... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A solution contains 8.92 g of KBr in 500.0 \(\mathrm{mL}\) of solution and has an osmotic pressure of 6.97 atm at \(25^{\circ} \mathrm{C}\) . Calculate the vant Hoff factor \((i)\) for \(\mathrm{KBr}\) at this concentration.

Short Answer

Expert verified
The vant Hoff factor \(i\) for KBr at this concentration is calculated to be approximately 1.99.

Step by step solution

01

Convert Temperature to Kelvin

To use the osmotic pressure equation, the temperature must be in Kelvin. Convert the temperature from Celsius to Kelvin by adding 273.15 to the Celsius temperature.
02

Calculate the Molarity of the Solution

Use the formula molarity (M) = moles of solute / liters of solution to find the molarity of the KBr solution. First, calculate the moles of solute (KBr) using its molar mass.
03

Use the Osmotic Pressure Formula

Apply the formula for osmotic pressure, \( \Pi = iMRT \), where \( \Pi \) is the osmotic pressure, \( i \) is the van 't Hoff factor, \( M \) is the molarity, \( R \) is the gas constant (0.0821 L atm/mol K), and \( T \) is the temperature in Kelvin.
04

Solve for the Van 't Hoff Factor (\(i\(i\) \(i\) \(i\) \(i\) \(i\) \(i\) \(i\) (i\(i\) factor)

Rearrange the osmotic pressure formula to solve for the van 't Hoff factor: \( i = \Pi / (MRT) \). Substitute the values of osmotic pressure, molarity, gas constant, and temperature into the equation to find \( i \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Osmotic Pressure Calculation
Understanding osmotic pressure is key for many scientific disciplines, especially in chemistry and biological sciences. Osmotic pressure is a fundamental concept that describes the force exerted by a solvent as it passes through a semipermeable membrane to equalize solute concentrations on both sides. In simpler terms, it's how a solvent, like water, moves to balance out the solute, like salt, in solution.

In a practical scenario, if you have a sugar solution separated from pure water by a semiperipheral membrane, water will move into the sugar solution to dilute it, generating a pressure known as osmotic pressure. It's an essential process in living cells and also in industrial applications like water purification.

Calculating osmotic pressure can be done with the formula:
\(\Pi = iMRT\)
where \(\Pi\) is the osmotic pressure, \(i\) is the van 't Hoff factor (which indicates the number of particles a solute breaks into or forms in solution), \(M\) is the molarity of the solution, \(R\) is the ideal gas constant (0.0821 L atm/mol K), and \(T\) is the temperature in Kelvin. This formula assumes that the solute behaves ideally, meaning its particles don't interact in any way that significantly changes the pressure.

When solving problems dealing with osmotic pressure, always ensure that the temperature is converted to Kelvin, and the molarity is accurately calculated to ensure correctness of the resulting osmotic pressure.
Molarity
Molarity, often represented by the letter \(M\), is a unit of concentration in chemistry that specifies the number of moles of a solute in one liter of solution. It's quite a significant measure when preparing solutions in the lab or analyzing chemical reactions.

Calculating molarity is straightforward—divide the number of moles of the solute by the volume of the solution in liters. The formula looks like this:
\[M = \frac{{\text{{number of moles of solute}}}}{{\text{{volume of solution in liters}}}}\]
In the context of osmotic pressure calculations, knowing the molarity is critical since it directly affects the osmotic pressure. A higher molarity means more solute particles in the solution, which can lead to higher osmotic pressure. It's the quantitative relationship between the amount of solute and the osmotic pressure it can generate that makes molarity indispensable in these calculations.

To find the molarity in our textbook problem, you would weigh the solute (\(KBr\)) used, compute the number of moles based on its molar mass, and then divide by the volume of the solution (which must be in liters). Accuracy in these steps is crucial for an accurate molarity value and correct osmotic pressure calculation.
Temperature Conversion to Kelvin
Many chemical calculations, such as those involving osmotic pressure, require temperatures to be in the Kelvin scale. Kelvin is the base unit for temperature in the International System of Units (SI) and is pivotal in the scientific community because unlike Celsius or Fahrenheit, it starts at absolute zero—the theoretical point where particles have minimum thermal motion.

Converting Celsius to Kelvin is quite straightforward: add 273.15 to the Celsius temperature. Never forget this step in your calculations, as it can significantly impact the results. The Kelvin scale guarantees that the temperature variable in our calculations is absolute and ensures compatibility with the gas constant \(R\) in the osmotic pressure equation.

An important thing to note is that temperature changes can affect the movement of molecules and thus influence osmotic pressure. When the temperature increases, molecules move faster, potentially increasing osmotic pressure. Therefore, it's essential to work with accurate temperature values to correctly determine osmotic pressure.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The small bubbles that form on the bottom of a water pot that is being heated (before boiling) are due to dissolved air coming out of solution. Use Henry's law and the solubilities given to calculate the total volume of nitrogen and oxygen gas that should bubble out of 1.5 \(\mathrm{L}\) of water upon warming from \(25^{\circ} \mathrm{C}\) to \(50^{\circ} \mathrm{C}\) . Assume that the water is initially saturated with nitrogen and oxygen gas at \(25^{\circ} \mathrm{C}\) and a total pressure of 1.0 atm. Assume that the gas bubbles out at a tem- perature of \(50^{\circ} \mathrm{C}\) . The solubility of oxygen gas at \(50^{\circ} \mathrm{C}\) is 27.8 \(\mathrm{mg} / \mathrm{L}\) at an oxygen pressure of 1.00 atm. The solubility of nitrogen gas at \(50^{\circ} \mathrm{C}\) is 14.6 \(\mathrm{mg} / \mathrm{L}\) at a nitrogen pressure of 1.00 atm. Assume that the air above the water contains an oxygen partial pressure of 0.21 \(\mathrm{atm}\) and a nitrogen partial pressure of 0.78 \(\mathrm{atm.}\)

A solution contains 4.08 g of chloroform \(\left(\mathrm{CHCl}_{3}\right)\) and 9.29 g of acetone \(\left(\mathrm{CH}_{3} \mathrm{COCH}_{3}\right) .\) The vapor pressures at \(35^{\circ} \mathrm{C}\) of pure chloroform and pure acetone are 295 torr and 332 torr, respectively. Assuming ideal behavior, calculate the vapor pressures of each of the components and the total vapor pressure above the solution. The experimentally measured total vapor pressure of the solution at \(35^{\circ} \mathrm{C}\) is 312 torr. Is the solution ideal? If not, what can you say about the relative strength of chloroformactone interactions compared to the acetone-acetone and chloroform-chloroform interactions?

A solution contains a mixture of pentane and hexane at room temperature. The solution has a vapor pressure of 258 torr. Pure pentane and hexane have vapor pressures of 425 torr and 151 torr, respectively, at room temperature. What is the mole fraction composition of the mixture? (Assume ideal behavior.)

What is the effect of a nonvolatile solute on the vapor pressure of a liquid? Why is the vapor pressure of a solution different from the vapor pressure of the pure liquid solvent?

Lead is a toxic metal that affects the central nervous system. A Pb- contaminated water sample contains 0.001196 Pb by mass. How much of the water (in mL) contains 150 \(\mathrm{mg}\) of Pb? (Assume a density of 1.0 \(\mathrm{g} / \mathrm{mL}\) .

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.