Chapter 2: Problem 14
Calculate the number of atoms in 16 grams of \(\mathrm{O}_{2}, 31\) grams of \(\mathrm{P}_{4}\), and 32 grams of \(\mathrm{S}_{2}\).
Short Answer
Expert verified
Each element contains \(6.022 \times 10^{23}\) atoms.
Step by step solution
01
Understand the Problem
We need to calculate the number of atoms in given masses of molecules: \(\mathrm{O}_2\), \(\mathrm{P}_4\), and \(\mathrm{S}_2\). This involves converting grams into moles and then using Avogadro's number to find the number of atoms.
02
Calculate Molar Mass of Each Molecule
Determine the molar mass of \(\mathrm{O}_2\), \(\mathrm{P}_4\), and \(\mathrm{S}_2\).- Molar mass of \(\mathrm{O}_2\) is \(2 \times 16 = 32 \ \text{g/mol}\).- Molar mass of \(\mathrm{P}_4\) is \(4 \times 31 = 124 \ \text{g/mol}\).- Molar mass of \(\mathrm{S}_2\) is \(2 \times 32 = 64 \ \text{g/mol}\).
03
Convert Grams to Moles
Use the molar mass to convert grams into moles for each substance.- For \(\mathrm{O}_2\), \(\frac{16}{32} = 0.5\ \text{moles}\).- For \(\mathrm{P}_4\), \(\frac{31}{124} = 0.25\ \text{moles}\).- For \(\mathrm{S}_2\), \(\frac{32}{64} = 0.5\ \text{moles}\).
04
Calculate Number of Molecules
Use Avogadro's number \(6.022 \times 10^{23}\) to find the number of molecules from the moles calculated.- \(\mathrm{O}_2\): \(0.5 \times 6.022 \times 10^{23} = 3.011 \times 10^{23}\ \text{molecules}\).- \(\mathrm{P}_4\): \(0.25 \times 6.022 \times 10^{23} = 1.5055 \times 10^{23}\ \text{molecules}\).- \(\mathrm{S}_2\): \(0.5 \times 6.022 \times 10^{23} = 3.011 \times 10^{23}\ \text{molecules}\).
05
Calculate Number of Atoms
Finally, use the molecular formula to calculate the number of atoms.- \(\mathrm{O}_2\): \(3.011 \times 10^{23}\) molecules \(\times 2 = 6.022 \times 10^{23}\ \text{atoms}\).- \(\mathrm{P}_4\): \(1.5055 \times 10^{23}\) molecules \(\times 4 = 6.022 \times 10^{23}\ \text{atoms}\).- \(\mathrm{S}_2\): \(3.011 \times 10^{23}\) molecules \(\times 2 = 6.022 \times 10^{23}\ \text{atoms}\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Molar Mass
Molar mass is a crucial concept in chemistry that helps us determine the amount of a substance. It is defined as the mass of one mole of a substance expressed in grams per mole (g/mol). To find the molar mass, you add up the atomic masses of each element in a molecule based on the periodic table.
For example, in the molecule of oxygen
For example, in the molecule of oxygen
- Oxygen ( \( \text{O}_2 \)) consists of two oxygen atoms. Since the atomic mass of oxygen is approximately 16 g/mol, the molar mass of \( \text{O}_2 \) is calculated as \( 2 \times 16 = 32 \, \text{g/mol} \).
- For phosphorus ( \( \text{P}_4 \)), the atomic mass is 31 g/mol, so the molar mass for \( \text{P}_4 \) is \( 4 \times 31 = 124 \, \text{g/mol} \).
- Finally, sulfur ( \( \text{S}_2 \)), with an atomic mass also around 32 g/mol, results in a molar mass of \( 2 \times 32 = 64 \, \text{g/mol} \).
Conversion of grams to moles
To perform chemical calculations, converting grams to moles is often essential. Moles are a unit for counting atoms, molecules, or ions, effectively reducing large numbers to a manageable size using Avogadro's number, which is \( 6.022 \times 10^{23} \). Here's how you do it:
You divide the given mass of your substance by its molar mass.
You divide the given mass of your substance by its molar mass.
- For \( \text{O}_2 \), we have 16 grams. Using its molar mass of 32 g/mol, you would calculate the moles as \( \frac{16}{32} = 0.5 \) moles.
- For \( \text{P}_4 \), with a mass of 31 grams and a molar mass of 124 g/mol, the conversion is \( \frac{31}{124} = 0.25 \) moles.
- For \( \text{S}_2 \), 32 grams converts into \( \frac{32}{64} = 0.5 \) moles.
Molecular Formula calculations
Once you've determined the number of moles, you can calculate the number of atoms within a sample by using the molecular formula. The molecular formula tells you how many atoms of each element are in a molecule of a compound. This is done in a few steps:
First, calculate the number of molecules by multiplying moles by Avogadro's number ( \( 6.022 \times 10^{23} \)).
First, calculate the number of molecules by multiplying moles by Avogadro's number ( \( 6.022 \times 10^{23} \)).
- For \( \text{O}_2 \), with 0.5 moles, the number of molecules is \( 0.5 \times 6.022 \times 10^{23} = 3.011 \times 10^{23} \) molecules.
- \( \text{P}_4 \) with 0.25 moles yields \( 0.25 \times 6.022 \times 10^{23} = 1.5055 \times 10^{23} \) molecules.
- \( \text{S}_2 \) also results in \( 3.011 \times 10^{23} \) molecules for 0.5 moles.
- For \( \text{O}_2 \), multiply the number of molecules by 2 (since each \( \text{O}_2 \) contains 2 oxygen atoms) to get \( 6.022 \times 10^{23} \) atoms.
- \( \text{P}_4 \) yields the same because there are four phosphorus atoms in each molecule: \( 1.5055 \times 10^{23} \times 4 = 6.022 \times 10^{23} \) atoms.
- Finally, \( \text{S}_2 \) follows the same pattern as oxygen, leading to \( 6.022 \times 10^{23} \) atoms.