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Which of the following nuclides are most likely to be neutron-poor? (a) \({ }^{3} \mathrm{H}\) (b) \({ }^{11} \mathrm{C}\) (c) \({ }^{14} \mathrm{~N}\) (d) \({ }^{40} \mathrm{~K}\) (e) \({ }^{61} \mathrm{Cu}\)

Short Answer

Expert verified
\({ }^{11} \text{C} \) is most likely to be neutron-poor.

Step by step solution

01

Understand Neutron-Poor Nuclides

A neutron-poor nuclide has more protons relative to neutrons, meaning it is likely to have a lower neutron-to-proton ( /p atio( /p atio compared to more stable isotopes. Most stable isotopes have a slightly higher number of neutrons than protons.
02

Determine Protons and Neutrons for Each Nuclide

Examine the given nuclides: - \({ }^{3} \text{H}\): 1 proton, 2 neutrons;- \({ }^{11} \text{C}\): 6 protons, 5 neutrons;- \({ }^{14} \text{N}\): 7 protons, 7 neutrons;- \({ }^{40} \text{K}\): 19 protons, 21 neutrons;- \({ }^{61} \text{Cu}\): 29 protons, 32 neutrons.
03

Calculate Neutron-to-Proton Ratio ( /p atio

Calculate the n/p ratio for each nuclide:- \( \text{For } { }^{3} \text{H}: \text{n/p} = \frac{2}{1} = 2.0 \)- \( \text{For } { }^{11} \text{C}: \text{n/p} = \frac{5}{6} \approx 0.83 \)- \( \text{For } { }^{14} \text{N}: \text{n/p} = \frac{7}{7} = 1.0 \)- \( \text{For } { }^{40} \text{K}: \text{n/p} = \frac{21}{19} \approx 1.11 \)- \( \text{For } { }^{61} \text{Cu}: \text{n/p} = \frac{32}{29} \approx 1.10 \)
04

Identify Neutron-Poor Nuclide

The nuclide with the smallest n/p ratio is neutron-poor. Compare the ratios:- \( { }^{11} \text{C} \) has the smallest n/p ratio of approximately 0.83Thus, \({ }^{11} \text{C} \) is neutron-poor.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Neutron-to-Proton Ratio
The neutron-to-proton ratio (n/p ratio) is a critical concept in understanding the composition of atomic nuclei. It refers to the relative number of neutrons compared to protons within a nuclide. To determine this ratio, you simply divide the number of neutrons by the number of protons.
Typically, the stability of a nuclide is influenced by its neutron-to-proton ratio. A balanced n/p ratio contributes to a stable nucleus, often with a slight excess of neutrons over protons. When the n/p ratio deviates from this balance, the nuclide can become unstable or neutron-poor.
For neutron-poor nuclides, the number of protons exceeds or is too close to the number of neutrons, leading to a lower n/p ratio compared to more stable isotopes. This imbalance raises the likelihood of radioactive decay, as the nuclide seeks a more stable state by shedding excess protons or undergoing nuclear transformations.
Nuclide Stability
Nuclide stability refers to the tendency of an isotope to remain intact rather than breaking down via radioactive decay. Stability is largely determined by the neutron-to-proton ratio as well as the binding energy of the nucleus. Stable nuclides have n/p ratios that allow for balance, resulting in fewer tendencies toward decay.
Factors affecting nuclide stability include:
  • Ideal n/p ratio: Approximately 1:1 for smaller atoms and gradually increasing for larger atoms due to increased repulsion among protons.
  • Magic numbers: Specific numbers of protons or neutrons that result in particularly stable nuclides, caused by filled nuclear shells.
  • Binding energy: The energy required to break a nucleus into its constituent protons and neutrons. High binding energy often correlates with stability.
A neutron-poor nuclide, like \( ^{11}C \), has a lower n/p ratio and generally reduced stability compared to its neutron-rich counterparts, making it prone to decay through mechanisms such as positron emission.
Isotope Composition
Isotope composition is the makeup of an element characterized by the number of protons and neutrons in its nucleus. Every element is composed of isotopes, which share the same atomic number but differ in their mass numbers.
To find the isotopes of an element, you look at their varying neutron numbers. For instance, carbon-11 (\( ^{11}C \)) is an isotope of carbon that has 6 protons and 5 neutrons. This slight difference in its neutron count from the typical carbon isotope affects its neutron-to-proton ratio, giving it distinctive properties like being neutron-poor.
When examining isotopes, the focus is on how this composition affects atomic behavior:
  • Neutron number: Impacts nuclear stability and reactivity.
  • Neutron-to-proton imbalance: Affects decay processes and can render the isotope radioactive.
  • Mass number: Total count of protons and neutrons, crucial for distinguishing isotopes.
Understanding an isotope's composition helps predict its stability, reactivity, and type of decay, crucial for fields like nuclear chemistry and medical imaging.

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Most popular questions from this chapter

Use Lewis structures to describe the difference between an \(\mathrm{H}_{2} \mathrm{O}^{+}\) ion and an \(\mathrm{H}_{3} \mathrm{O}^{+}\) ion. If a free radical is an ion or molecule that contains one or more unpaired electrons, which of these ions is a free radical?

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