Chapter 11: Problem 13
Calculate the \(\mathrm{pH}\) of \(0.10 \mathrm{M}\) solutions of \(\mathrm{H}_{3} \mathrm{PO}_{4},\) \(\mathrm{NaH}_{2} \mathrm{PO}_{4}, \mathrm{Na}_{2} \mathrm{HPO}_{4},\) and \(\mathrm{Na}_{3} \mathrm{PO}_{4} .\) (For \(\mathrm{H}_{3} \mathrm{PO}_{4}, K_{\mathrm{a} 1}=\) \(7.1 \times 10^{-3}, K_{\mathrm{a} 2}=6.3 \times 10^{-8},\) and \(\left.K_{\mathrm{a} 3}=4.2 \times 10^{-13} \mathrm{.}\right)\)
Short Answer
Step by step solution
Calculate pH for H3PO4
Calculate pH for NaH2PO4
Calculate pH for Na2HPO4
Calculate pH for Na3PO4
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Triprotic Acid
- The first stage dissociates to form H_2PO_4^- and a hydrogen ion. This is usually the dominant reaction in determining pH.
- The second stage involves H_2PO_4^- losing another hydrogen ion to form HPO_4^{2-} .
- In the third and final step, HPO_4^{2-} loses a hydrogen ion, resulting in PO_4^{3-} .
Ionization Equilibrium
In the case of H_3PO_4, the first ionization is the most significant in pH calculation due to its highest concentration. The equilibrium expression for this step is given by:\[K_{a1} = \frac{[H^+][H_2PO_4^-]}{[H_3PO_4]}\]This equation helps in determining the pH by translating how much H^+ is present in the solution when equilibrium is reached. Depending on the strength of the equilibrium constant (K_a), we can identify how readily an acid dissociates into hydrogen ions.
Acid-Base Chemistry
In this particular exercise:
- When a strong acid like H_3PO_4 ionizes, it increases the concentration of H^+ ions significantly, lowering the pH.
- The NaH_2PO_4 and Na_2HPO_4 can either act as acids or bases, affecting the solution's pH based on their equilibrium states.
- For bases like Na_3PO_4 , they produce hydroxide ions ( OH^- ), increasing the solution's pH.
Chemical Equilibrium Constants
For a triprotic acid like H_3PO_4 , different K_a values are provided for its multiple ionizations:
- K_{a1} , the highest, implies the greatest level of dissociation at the first stage, strongly impacting pH.
- K_{a2} and K_{a3} are progressively smaller, showing lesser degrees of ionization further down the stages.