Chapter 10: Problem 108
Which of the following statements is true? (a) \(\mathrm{MgF}_{2}\) is more soluble in \(0.100 \mathrm{M} \mathrm{NaF}\) than in pure water. (b) \(\mathrm{MgF}_{2}\) is less soluble in \(0.100 \mathrm{M} \mathrm{NaF}\) than in pure water. (c) \(\mathrm{MgF}_{2}\) is just as soluble in \(0.100 \mathrm{M} \mathrm{NaF}\) as in pure water.
Short Answer
Step by step solution
Understand the question
Recall the Common Ion Effect
Analyze Solubility of \(\mathrm{MgF}_{2}\)
Determine Effect of \(\mathrm{NaF}\) Addition
Conclude Solubility Result
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Solubility Product
- For \( \mathrm{MgF}_{2} \), the equilibrium in water can be represented as:
- The solubility product expression is then:
Ionic Equilibrium
Solubility of Ionic Compounds
- Pure water generally provides a baseline measure of an ionic compound's solubility.
- In the presence of similar ions, solubility is often decreased due to the common ion effect.