Chapter 1: Problem 82
Naturally occurring zinc is \(48.6 \%{ }^{64} \mathrm{Zn}\) atoms (63.9291 amu) \(, 27.9 \%^{66} \mathrm{Zn}\) atoms \((65.9260 \mathrm{amu}), 4.1 \%^{67} \mathrm{Zn}\) atoms \((66.9721\) amu \(), 18.8 \%^{68} \mathrm{Zn}\) atoms (67.9249 \(\mathrm{amu}\) ), and \(0.6 \%{ }^{70} \mathrm{Zn}\) atoms \((69.9253 \mathrm{amu}) .\) Calculate the atomic weight of zinc.
Short Answer
Step by step solution
Understand Isotopic Contribution
Convert Percentage to Decimal
Calculate weighted mass for each Isotope
Sum Weighted Masses
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Isotopic Contribution
- \(^{64}\text{Zn}\)
- \(^{66}\text{Zn}\)
- \(^{67}\text{Zn}\)
- \(^{68}\text{Zn}\)
- \(^{70}\text{Zn}\)
Weighted Average
- Multiply the mass of each isotope by its natural abundance (converted to a decimal).
- Sum all these products to get the atomic weight.
Natural Abundances
- Divide the percentage by 100 to get the decimal form.