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Write the ground state electron configuration for (a) \(\mathrm{Mg}, \mathrm{Mg}^{2+}\) (b) \(\mathrm{N}, \mathrm{N}^{3-}\) (c) \(\mathrm{Ti}, \mathrm{Ti}^{4+}\) (d) \(\mathrm{Sn}^{2+}, \mathrm{Sn}^{4+}\)

Short Answer

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Question: Write the ground state electron configurations for the following elements and their ions: (a) Mg, Mg虏鈦 (b) N, N鲁鈦 (c) Ti, Ti鈦粹伜 (d) Sn虏鈦, Sn鈦粹伜 Answer: (a) Mg: 1s虏 2s虏 2p鈦 3s虏; Mg虏鈦: 1s虏 2s虏 2p鈦 (b) N: 1s虏 2s虏 2p鲁; N鲁鈦: 1s虏 2s虏 2p鈦 (c) Ti: 1s虏 2s虏 2p鈦 3s虏 3p鈦 4s虏 3d虏; Ti鈦粹伜: 1s虏 2s虏 2p鈦 3s虏 3p鈦 (d) Sn虏鈦: 1s虏 2s虏 2p鈦 3s虏 3p鈦 4s虏 3d鹿鈦 4p鈦 5s虏 4d鹿鈦; Sn鈦粹伜: 1s虏 2s虏 2p鈦 3s虏 3p鈦 4s虏 3d鹿鈦 4p鈦 4d鹿鈦

Step by step solution

01

(a) Mg, Mg虏鈦 Electron Configuration

For Mg, we find its atomic number (12) on the periodic table. Its electron configuration is: 1s虏 2s虏 2p鈦 3s虏 For Mg虏鈦, remove 2 electrons since it has lost 2 electrons to become positively charged. Thus, its electron configuration is: 1s虏 2s虏 2p鈦
02

(b) N, N鲁鈦 Electron Configuration

For N, we find its atomic number (7) on the periodic table. Its electron configuration is: 1s虏 2s虏 2p鲁 For N鲁鈦, add 3 electrons since it has gained 3 electrons to become negatively charged. Thus, its electron configuration is: 1s虏 2s虏 2p鈦
03

(c) Ti, Ti鈦粹伜 Electron Configuration

For Ti, we find its atomic number (22) on the periodic table. Its electron configuration is: 1s虏 2s虏 2p鈦 3s虏 3p鈦 4s虏 3d虏 For Ti鈦粹伜, remove 4 electrons since it has lost 4 electrons to become positively charged. Thus, its electron configuration is: 1s虏 2s虏 2p鈦 3s虏 3p鈦
04

(d) Sn虏鈦, Sn鈦粹伜 Electron Configuration

For Sn, we find its atomic number (50) on the periodic table. Its electron configuration is: 1s虏 2s虏 2p鈦 3s虏 3p鈦 4s虏 3d鹿鈦 4p鈦 5s虏 4d鹿鈦 5p虏 For Sn虏鈦, remove 2 electrons since it has lost 2 electrons to become positively charged. Thus, its electron configuration is: 1s虏 2s虏 2p鈦 3s虏 3p鈦 4s虏 3d鹿鈦 4p鈦 5s虏 4d鹿鈦 For Sn鈦粹伜, remove 4 electrons since it has lost 4 electrons to become positively charged. Thus, its electron configuration is: 1s虏 2s虏 2p鈦 3s虏 3p鈦 4s虏 3d鹿鈦 4p鈦 4d鹿鈦

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ground State Electron Configuration
Understanding the ground state electron configuration is fundamental in chemistry and physics, as it describes the arrangement of electrons in an atom's orbitals at its most energetically stable. Electrons fill subshells (s, p, d, f and so on) in a way that minimizes the energy of the atom. This filling order is dictated by the principles of quantum mechanics.

For example, the ground state configuration for a neutral magnesium (Mg) atom, which has an atomic number of 12, is written as 1s虏 2s虏 2p鈦 3s虏. This notation shows that the 1s subshell is filled with two electrons, the 2s subshell is also filled with two electrons, the 2p subshell is filled with six electrons, and the 3s subshell contains the remaining two electrons to make up a total of 12 electrons. As atoms increase in atomic number, the electron configurations become more complex, but the 'building-up' (or Aufbau) principle helps to determine the sequence in which orbitals are filled.

We must include the Pauli Exclusion Principle, which states that no two electrons can have the same set of four quantum numbers, leading to the orderly fill of electrons within subshells and orbitals. Moreover, Hund's Rule indicates that electrons will fill an unoccupied orbital before they pair up in an already occupied one, which affects the electron configuration when dealing with subshells that have more than one orbital, such as p, d, or f subshells.
Periodic Table and Electron Configuration
The Periodic Table is not just a simple chart but a powerful tool for predicting the properties of elements, including their electron configurations. Each column, known as a group, contains elements with similar properties and the same number of electrons in their outermost shell, or valence shell.

When writing electron configurations, the periodic table outlines the order in which subshells are filled: elements in the first two groups fill the s subshell, while elements in groups 13 to 18 fill the p subshell. Transition metals, found in the middle section, are involved in filling the d subshell, and the lanthanides and actinides at the bottom fill the f subshell. The row, or period, indicates the number of electron shells.

Memorizing the order of subshell filling can be challenging, but there's a mnemonic tool: the n + l rule, where n is the principal quantum number and l is the azimuthal quantum number for the subshell (s=0, p=1, d=2, f=3). Electrons enter the available subshell with the lowest sum of n + l, and if two subshells have the same sum, the one with the lower n value fills first. This can be visualized by a diagonal rule on the periodic table, which leads through the s, p, d, and f blocks in the correct order for electron configuration.
Cation and Anion Electron Configuration
Cations are positively charged ions that are formed when an atom loses one or more electrons; anions are negatively charged ions, created when an atom gains electrons. The electron configurations of these ions are essential for understanding chemical bonding and reactions.

For cations, since they lose electrons, their configuration is determined by removing electrons from the outermost shell. For magnesium, after it loses two electrons to become Mg虏鈦, the electron configuration ends at 2p鈦 because the 3s electrons are lost. This removal typically happens from the highest energy level, or the outermost shell first. In transition metals like titanium (Ti), electrons are removed from the s orbital before the d orbitals, following the (n+1)s > nd rule.

Anions, on the other hand, gain electrons and their configuration is found by adding electrons to the outer shell. Nitrogen, upon gaining three electrons to become N鲁鈦, achieves a noble gas configuration by filling its 2p subshell to achieve the stable arrangement of 2p鈦. When elements form anions, the added electrons occupy the lowest-energy orbital available.

It's important to remember that changes in electron configuration affect the chemical properties of the ions. Cations typically become smaller than their neutral atoms due to a decrease in electron-electron repulsion, while anions become larger due to increased electron-electron repulsion. These size differences, along with changes in electron configuration, can greatly influence the behavior of ions in chemical reactions and in the formation of compounds.

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Most popular questions from this chapter

Indicate whether each of the following is true or false. (a) Effective nuclear charge stays about the same when one goes down a group. (b) Group 17 elements have seven electrons in their outer level. (c) Energy is given off when an electron is removed from an atom.

For the Pfund series, \(\mathbf{n}_{\mathrm{lo}}=5\). (a) Calculate the wavelength in nanometers of a transition from \(\mathbf{n}=7\) to \(\mathrm{n}=5 .\) (b) In what region of the spectrum are these lines formed?

Name and give the symbol for the element with the characteristic given below: (a) Its electron configuration is \(1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{5}\). (b) Lowest ionization energy in Group 14. (c) Its \(+2\) ion has the configuration \(\left[{ }_{18} \mathrm{Ar}\right] 3 \mathrm{~d}^{5}\). (d) It is the alkali metal with the smallest atomic radius. (e) Largest ionization energy in the fourth period.

Which of the following electron configurations (a-e) are for atoms in the ground state? In the excited state? Which are impossible? (a) \(1 s^{2} 2 p^{1}\) (b) \(1 s^{2} 2 s^{2} 2 p^{4}\) (c) \(1 s^{2} 2 s^{2} 2 p^{5} 3 d^{1}\) (d) \(1 s^{2} 2 s^{2} 2 p^{7} 3 s^{2}\) (e) \(1 s^{2} 2 s^{2} 2 p^{6} 4 s^{1} 3 d^{11}\)

An argon-ion laser is used in some laser light shows. The argon ion has strong emissions at \(485 \mathrm{~nm}\) and \(512 \mathrm{~nm}\). (a) What is the color of these emissions? (b) What is the energy associated with these emissions in kilojoules per mole? (c) Write the ground state electron configuration and orbital diagram of \(\mathrm{Ar}^{+}\).

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