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Given the following condensed formulas, write the molecular formulas for the following molecules. (a) dimethylamine \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{NH}\) (b) propyl alcohol \(\mathrm{CH}_{3}\left(\mathrm{CH}_{2}\right)_{2} \mathrm{OH}\) 26\. Write the condensed structural formulas and molecular formulas

Short Answer

Expert verified
Answer: The molecular formula of dimethylamine is C₂H₇N, and the molecular formula of propyl alcohol is C₃H₈O.

Step by step solution

01

Identify the atoms and the number of each atom present in the condensed formula.

For dimethylamine, the condensed formula is \((\mathrm{CH}_{3})_{2}\mathrm{NH}\). We can identify that there are carbon (C), hydrogen (H), and nitrogen (N) atoms present in the condensed formula.
02

Determine the number of each atom present from the condensed formula.

In the condensed formula, there are two "CH3" groups. Each CH3 group has 1 carbon atom and 3 hydrogen atoms. Also, there is one NH group, consisting of 1 nitrogen atom and 1 hydrogen atom.
03

Add the number of each atom to find the molecular formula.

We have two CH3 groups, so the total number of carbons is \(2\times 1=2\) and the total number of hydrogens from these two groups is \(2\times 3=6\). Then, we have 1 nitrogen atom and 1 hydrogen atom from the NH group. Finally, we can get the molecular formula by combining the total number of each atom: \(\mathrm{C}_2\mathrm{H}_7\mathrm{N}\). The molecular formula of dimethylamine is \(\mathrm{C}_2\mathrm{H}_7\mathrm{N}\). #b) Propyl Alcohol#
04

Identify the atoms and the number of each atom present in the condensed formula.

For propyl alcohol, the condensed formula is \(\mathrm{CH}_{3}(\mathrm{CH}_{2})_{2}\mathrm{OH}\). We can identify that there are carbon (C), hydrogen (H), and oxygen (O) atoms present in the condensed formula.
05

Determine the number of each atom present from the condensed formula.

In the condensed formula, we have one CH3 group with 1 carbon atom and 3 hydrogen atoms, two CH2 groups with 1 carbon atom and 2 hydrogen atoms each, and one OH group with 1 oxygen atom and 1 hydrogen atom.
06

Add the number of each atom to find the molecular formula.

We have 1 carbon atom and 3 hydrogen atoms from the CH3 group, and 2\(\times\)1=2 carbon atoms and 2\(\times\)2=4 hydrogen atoms from the two CH2 groups. Also, we have 1 oxygen atom and 1 hydrogen atom from the OH group. Adding these together, we have C(1+2)=C3, H(3+4+1)=H8, and O1. Thus, the molecular formula is \(\mathrm{C}_3\mathrm{H}_8\mathrm{O}\). The molecular formula of propyl alcohol is \(\mathrm{C}_3\mathrm{H}_8\mathrm{O}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Dimethylamine
Dimethylamine is an organic compound known by its condensed formula \((\mathrm{CH}_{3})_{2}\mathrm{NH}\). This compound belongs to the amine family, which features nitrogen atoms bonded to carbon-containing groups. Let's delve into its molecular structure:

  • **Carbon Atoms:** There are 2 carbon atoms. Each is part of a methyl group (CH3).
  • **Hydrogen Atoms:** There are 7 hydrogen atoms. Six come from the two methyl groups and one is bonded to the nitrogen atom.
  • **Nitrogen Atom:** One nitrogen atom connects to both methyl groups and the single hydrogen atom.
The molecular formula of dimethylamine, therefore, is determined by summing all these atoms to give \(\mathrm{C}_2\mathrm{H}_7\mathrm{N}\). Understanding this composition is key when exploring amines and their derivatives in chemistry.
Propyl Alcohol
Propyl alcohol, often referred to as 1-propanol, is a primary alcohol with the condensed formula \(\mathrm{CH}_{3}(\mathrm{CH}_{2})_{2}\mathrm{OH}\). Primary alcohols have the hydroxyl group attached to the end carbon of a carbon chain. Here's how to interpret its structure:

  • **Carbon Atoms:** Three carbon atoms form the backbone of this molecule. One is in the methyl group (CH3), and the other two are in the methylene groups (CH2).
  • **Hydrogen Atoms:** There are 8 hydrogen atoms in total — 3 from the methyl group, 4 from the methylene groups, and 1 from the hydroxyl group (OH).
  • **Oxygen Atom:** The single oxygen atom forms part of the alcohol group, creating the characteristic -OH group.
The combination of these atoms results in the molecular formula \(\mathrm{C}_3\mathrm{H}_8\mathrm{O}\). Recognizing the structure of propyl alcohol is essential for understanding its properties and its role in organic reactions.
Chemical Structure Interpretation
Chemical structure interpretation is a skillful process of understanding molecular geometry based on condensed formulas. These formulas provide a shorthand representation of a molecule's structure. Here's how to break it down:

- **Identify Types of Atoms:** Look for symbols (C, H, N, O, etc.) to recognize the elements involved. - **Count the Atoms:** Evaluate subscripts and parentheses to determine how many of each atom are in the molecule. - **Visualize Bonding:** Consider how these atoms connect to form the entire molecule. This mental map helps in predicting molecular behavior and the effects of reactions.

This ability to transform a condensed formula into its corresponding molecular formula is fundamental in chemical analysis and synthesis. It bridges the gap between theoretical chemistry and practical application, essential for fields ranging from pharmaceuticals to materials science.

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Most popular questions from this chapter

Mercury(II) oxide, a red powder, can be decomposed by heating to produce liquid mercury and oxygen gas. When a sample of this compound is decomposed, \(3.87 \mathrm{~g}\) of oxygen and \(48.43 \mathrm{~g}\) of mercury are produced. \(\operatorname{In}\) a second experiment, \(15.68 \mathrm{~g}\) of mercury is allowed to react with an excess of oxygen and \(16.93 \mathrm{~g}\) of red mercury(II) oxide is produced. Show that these results are consistent with the law of constant composition.

A molecule of ethylamine is made up of two carbon atoms, seven hydrogen atoms, and one nitrogen atom. (a) Write its molecular formula. (b) The reactive group in ethylamine is \(\mathrm{NH}_{2}\). Write its condensed structural formula.

Which statements are true? (a) Neutrons have neither mass nor charge. (b) Isotopes of an element have an identical number of protons. (c) C-14 and N-14 have identical neutron/proton (n/p \(^{+}\) ) ratios. (d) The vertical columns in a periodic table are referred to as "groups." (e) When an atom loses an electron, it becomes positively charged.

State in your own words the law of conservation of mass. State the law in its modern form.

Hydrogen- 1 can take the form of a molecule, an anion \(\left(\mathrm{H}^{-}\right)\), or a cation \(\left(\mathrm{H}^{+}\right)\). (a) How many protons, electrons, and neutrons are in each possible species? (b) Write the name and formula for the compound formed between hydrogen and a metal in Group 2 with 12 protons. (c) What is the general name of the aqueous compounds in which hydrogen is a cation?

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