/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 2 Write the equilibrium equation a... [FREE SOLUTION] | 91影视

91影视

Write the equilibrium equation and the \(K_{s p}\) expression for each of the following. (a) \(\mathrm{AgCl}\) (b) \(\mathrm{Al}_{2}\left(\mathrm{CO}_{3}\right)_{3}\) (c) \(\mathrm{MnS}_{2}\) (d) \(\mathrm{Mg}(\mathrm{OH})_{2}\)

Short Answer

Expert verified
Question: Write the equilibrium equations and solubility product constant expressions for the following compounds: (a) AgCl (b) Al2(CO3)3 (c) MnS2 (d) Mg(OH)2 Answer: (a) Equilibrium Equation: AgCl(s) 鈬 Ag+(aq) + Cl-(aq) , Ksp = [Ag+][Cl-] (b) Equilibrium Equation: Al2(CO3)3(s) 鈬 2Al3+(aq) + 3CO32-(aq) , Ksp = [Al3+]^2[CO32-]^3 (c) Equilibrium Equation: MnS2(s) 鈬 Mn2+(aq) + 2S-(aq) , Ksp = [Mn2+][S-]^2 (d) Equilibrium Equation: Mg(OH)2(s) 鈬 Mg2+(aq) + 2OH-(aq) , Ksp = [Mg2+][OH-]^2

Step by step solution

01

(a) Equilibrium Equation for AgCl

To write the equilibrium equation for the dissolution of \(\mathrm{AgCl}\) in water, the solid dissociates into ions: $$\mathrm{AgCl(s)} \rightleftharpoons \mathrm{Ag^{+}(aq)} + \mathrm{Cl^{-}(aq)}$$
02

(a) Solubility Product Constant Expression for AgCl

For \(\mathrm{AgCl}\), the \(K_{sp}\) expression will be the product of the concentrations of the ions at equilibrium: $$K_{sp} = [\mathrm{Ag^{+}}][\mathrm{Cl^{-}}]$$
03

(b) Equilibrium Equation for Al2(CO3)3

To write the equilibrium equation for the dissolution of \(\mathrm{Al}_{2}\left(\mathrm{CO}_{3}\right)_{3}\) in water: $$ \mathrm{Al}_{2}(\mathrm{CO}_{3})_{3}(s) \rightleftharpoons 2\mathrm{Al^{3+}(aq)} + 3\mathrm{CO^{2-}_{3}(aq)} $$
04

(b) Solubility Product Constant Expression for Al2(CO3)3

For \(\mathrm{Al}_{2}\left(\mathrm{CO}_{3}\right)_{3}\), the \(K_{sp}\) expression will be the product of the concentrations of the ions raised to appropriate powers at equilibrium: $$K_{sp} = [\mathrm{Al^{3+}}]^{2}[\mathrm{CO^{2-}_{3}]^{3}$$
05

(c) Equilibrium Equation for MnS2

To write the equilibrium equation for the dissolution of \(\mathrm{MnS}_{2}\) in water: $$ \mathrm{MnS}_{2}(s) \rightleftharpoons \mathrm{Mn^{2+}(aq)} + 2\mathrm{S^{-}(aq)} $$
06

(c) Solubility Product Constant Expression for MnS2

For \(\mathrm{MnS}_{2}\), the \(K_{sp}\) expression will be the product of the concentrations of the ions raised to appropriate powers at equilibrium: $$K_{sp} = [\mathrm{Mn^{2+}}][\mathrm{S^{-}}]^{2}$$
07

(d) Equilibrium Equation for Mg(OH)2

To write the equilibrium equation for the dissolution of \(\mathrm{Mg}(\mathrm{OH})_{2}\) in water: $$ \mathrm{Mg}(\mathrm{OH})_{2}\mathrm{(s)} \rightleftharpoons \mathrm{Mg^{2+}(aq)} + 2\mathrm{OH^{-}(aq)} $$
08

(d) Solubility Product Constant Expression for Mg(OH)2

For \(\mathrm{Mg}(\mathrm{OH})_{2}\), the \(K_{sp}\) expression will be the product of the concentrations of the ions raised to appropriate powers at equilibrium: $$K_{sp} = [\mathrm{Mg^{2+}}][\mathrm{OH^{-}}]^{2}$$

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Equilibrium Equation
An equilibrium equation is essential when dealing with the solubility of ionic compounds in solution. It represents the dissolving process of a solid, denoting the balance when the solid goes into solution as it forms ions. Understanding this helps us predict how much of a substance can dissolve in water before it precipitates or crystallizes back. When
  • For AgCl, the equilibrium equation is: \[\mathrm{AgCl(s)} \rightleftharpoons \mathrm{Ag^{+}(aq)} + \mathrm{Cl^{-}(aq)}\]
  • For 础濒鈧(颁翱鈧)鈧: \[\mathrm{Al}_{2}(\mathrm{CO}_{3})_{3}(s) \rightleftharpoons 2\mathrm{Al^{3+}(aq)} + 3\mathrm{CO^{2-}_{3}(aq)}\]
  • For MnS鈧: \[\mathrm{MnS}_{2}(s) \rightleftharpoons \mathrm{Mn^{2+}(aq)} + 2\mathrm{S^{-}(aq)}\]
  • For 惭驳(翱贬)鈧: \[\mathrm{Mg(OH)}_{2}\mathrm{(s)} \rightleftharpoons \mathrm{Mg^{2+}(aq)} + 2\mathrm{OH^{-}(aq)}\]
Each equation provides insight into how a specific compound will interact when introduced to a solution. It's a vital first step in calculating the solubility product constant (Ksp).
Dissolution Process
The dissolution process involves a solid substance dissolving in a solvent, leading to the formation of ions in solution. It is the key event that sets the stage for establishing an equilibrium between the dissolved ions and undissolved solid. This process depends on various factors including temperature, pressure, and the nature of the solvent. Solubility increases when more of the solid is capable of dissolving, contributing to a higher concentration of ions.
  • In the dissolution of AgCl, the solid silver chloride dissociates into silver ions (Ag鈦) and chloride ions (Cl鈦).
  • Similarly, dissolving 惭驳(翱贬)鈧 will produce magnesium ions (Mg虏鈦) and hydroxide ions (OH鈦).
A balance is sought where the rate of dissolution equals the rate of precipitation, yielding a dynamic equilibrium. Understanding this process facilitates the calculation of Ksp values, allowing prediction of solubility under various conditions.
Ionic Concentrations
Ionic concentrations are crucial in determining the extent of a compound's solubility in a solution, as described by the solubility product constant, Ksp. This constant is a measure of the equilibrium between the insoluble solid and the ions it releases upon dissolving. For each dissolved ionic compound, the Ksp expression reflects the concentrations of the resulting ions raised to the power of their stoichiometric coefficients in the balanced equilibrium equation.
  • For AgCl, its Ksp formula is \(K_{sp} = [Ag^{+}][Cl^{-}]\)
  • For 础濒鈧(颁翱鈧)鈧, the expression expands to \(K_{sp} = [Al^{3+}]^2[CO鈧僞{2-}]^3\)
  • In the case of 惭驳(翱贬)鈧, it is \(K_{sp} = [Mg^{2+}][OH^{-}]^2\)
These expressions reveal how each compound dissociates and emphasizes the deep connection between solubility and ionic concentration. A higher Ksp indicates greater solubility, whereas a lower Ksp suggests limited ion dissolution.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

At \(25^{\circ} \mathrm{C}, 100.0 \mathrm{~mL}\) of a \(\mathrm{Ba}(\mathrm{OH})_{2}\) solution is prepared by dissolving \(\mathrm{Ba}(\mathrm{OH})_{2}\) in an alkaline solution. At equilibrium, the solution has \(2.37 \mathrm{~g}\) of \(\mathrm{Ba}(\mathrm{OH})_{2}\) and a \(\mathrm{pH}\) of \(13.28\). Estimate \(K_{s p}\) for \(\mathrm{Ba}(\mathrm{OH})_{2}\).

Calcium ions in blood trigger clotting. To prevent that in donated blood, sodium oxalate, \(\mathrm{Na}_{2} \mathrm{C}_{2} \mathrm{O}_{4}\), is added to remove calcium ions according to the following equation. $$ \mathrm{C}_{2} \mathrm{O}_{4}^{2-}(a q)+\mathrm{Ca}^{2+}(a q) \longrightarrow \mathrm{CaC}_{2} \mathrm{O}_{4}(s) $$ Blood contains about \(0.10 \mathrm{mg} \mathrm{Ca}^{2+} / \mathrm{mL}\). If a 250.0-mL sample of donated blood is treated with an equal volume of \(0.160 \mathrm{M} \mathrm{Na}_{2} \mathrm{C}_{2} \mathrm{O}_{4}\), estimate \(\left[\mathrm{Ca}^{2+}\right]\) after precipitation. \(\left(K_{s p} \mathrm{CaC}_{2} \mathrm{O}_{4}=4 \times 10^{-9}\right)\)

Water from a well is found to contain \(3.0 \mathrm{mg}\) of calcium ion per liter. If \(0.50 \mathrm{mg}\) of sodium sulfate is added to one liter of the well water without changing its volume, will a precipitate form? What should \(\left[\mathrm{SO}_{4}{ }^{2-}\right]\) be to just start precipitation?

Calculate the solubility (g/100 mL) of iron(II) hydroxide in buffered solutions with the following pH's. (a) 4 (b) 7 (c) 10

Predict what effect each of the following has on the position of the equilibrium $$ \mathrm{PbCl}_{2}(s) \rightleftharpoons \mathrm{Pb}^{2+}(a q)+2 \mathrm{Cl}^{-}(a q) \quad \Delta H=23.4 \mathrm{~kJ} $$ (a) addition of \(1 \mathrm{M} \mathrm{Pb}\left(\mathrm{NO}_{3}\right)_{2}\) solution (b) increase in temperature (c) addition of \(\mathrm{Ag}^{+}\), forming \(\mathrm{AgCl}\) (d) addition of \(1 M\) hydrochloric acid

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.