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Write formulas for two salts that (a) contain \(\mathrm{Ni}^{3+}\) and are acidic. (b) contain \(\mathrm{Na}^{+}\) and are basic. (c) contain \(\mathrm{ClO}_{4}^{-}\) and are neutral. (d) contain \(\mathrm{NH}_{4}{ }^{+}\) and are acidic.

Short Answer

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Question: Provide examples of salts that meet the following criteria: a) Contain Ni鲁鈦 and are acidic. b) Contain Na鈦 and are basic. c) Contain ClO鈧勨伝 and are neutral. d) Contain NH鈧勨伜 and are acidic. Answer: a) NiCl鈧 and Ni(NO鈧)鈧 b) NaCH鈧僀OO (sodium acetate) and NaF (sodium fluoride) c) KClO鈧 (potassium perchlorate) and Ca(ClO鈧)鈧 (calcium perchlorate) d) NH鈧凜l (ammonium chloride) and NH鈧凬O鈧 (ammonium nitrate)

Step by step solution

01

Select appropriate anions

Since \(\mathrm{Ni}^{3+}\) comes from a transition metal, we need to choose anions that originate from strong acids to create acidic salts. Examples of such anions include \(\mathrm{Cl}^{-}\) (from \(\mathrm{HCl}\)) and \(\mathrm{NO}_{3}^{-}\) (from \(\mathrm{HNO}_{3}\)).
02

Combine ions to form salts

Combining the cation \(\mathrm{Ni}^{3+}\) with the selected anions, we obtain the acidic salts: \(\mathrm{NiCl}_{3}\) and \(\mathrm{Ni(NO}_{3})_{3}\). (b) contain \(\mathrm{Na}^{+}\) and are basic.
03

Select appropriate anions

Since \(\mathrm{Na}^{+}\) comes from a strong base (\(\mathrm{NaOH}\)), we need to choose anions that originate from weak acids, such as \(\mathrm{CH}_{3}\mathrm{COO}^{-}\) (from \(\mathrm{CH}_{3}\mathrm{COOH}\)) and \(\mathrm{F}^{-}\) (from \(\mathrm{HF}\)).
04

Combine ions to form salts

Combining the cation \(\mathrm{Na}^{+}\) with the selected anions, we obtain the basic salts: \(\mathrm{NaCH}_{3}\mathrm{COO}\) (sodium acetate) and \(\mathrm{NaF}\) (sodium fluoride). (c) contain \(\mathrm{ClO}_{4}^{-}\) and are neutral.
05

Select appropriate cations

Since \(\mathrm{ClO}_{4}^{-}\) comes from a strong acid (\(\mathrm{HClO}_{4}\)), we need to choose cations that originate from strong bases to form neutral salts. Examples of such cations include \(\mathrm{K}^{+}\) (from \(\mathrm{KOH}\)) and \(\mathrm{Ca}^{2+}\) (from \(\mathrm{Ca(OH)}_{2}\)).
06

Combine ions to form salts

Combining the anion \(\mathrm{ClO}_{4}^{-}\) with the selected cations, we obtain the neutral salts: \(\mathrm{KClO}_{4}\) (potassium perchlorate) and \(\mathrm{Ca(ClO}_{4})_{2}\) (calcium perchlorate). (d) contain \(\mathrm{NH}_{4}{ }^{+}\) and are acidic.
07

Select appropriate anions

Since \(\mathrm{NH}_{4}{ }^{+}\) comes from a weak base (\(\mathrm{NH}_{4}\mathrm{OH}\)), we need to choose anions that originate from strong acids, such as \(\mathrm{Cl}^{-}\) (from \(\mathrm{HCl}\)) and \(\mathrm{NO}_{3}^{-}\) (from \(\mathrm{HNO}_{3}\)).
08

Combine ions to form salts

Combining the cation \(\mathrm{NH}_{4}{ }^{+}\) with the selected anions, we obtain the acidic salts: \(\mathrm{NH}_{4}\mathrm{Cl}\) (ammonium chloride) and \(\mathrm{NH}_{4}\mathrm{NO}_{3}\) (ammonium nitrate).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Salts Chemistry
When learning about salts in chemistry, understanding their nature and properties is crucial. Salts are compounds composed of anions (negatively charged ions) and cations (positively charged ions) that typically form during the chemical reaction between an acid and a base. This reaction is known as neutralization.

Salts have a wide range of characteristics and functions, depending on the acid and base from which they originate. A quintessential property of salts is their ability to dissolve in water, where they disassociate into their constituent anions and cations. There are various types of salts, including acidic, basic, and neutral.

An acidic salt results when a strong acid reacts with a weak base, leaving the salt with a surplus of hydrogen ions (H+), giving it an acidic character. On the other hand, a basic salt comes about when a weak acid reacts with a strong base, leading to a final product that has an excess of hydroxide ions (OH-), making it basic. Lastly, neutral salts are formed when a strong acid and a strong base react, striking a balance with no excess of hydrogen or hydroxide ions.
Anions and Cations
To comprehend the role of anions and cations in salts chemistry, it is imperative to understand these charged particles. Anions are atoms or molecules that have gained one or more electrons, thus acquiring a negative charge, while cations have lost one or more electrons and as a result, possess a positive charge. These charged ions are crucial components in the structure of salts and dictate much of their resulting properties.

In the context of an acid-base reaction, the anions typically originate from the acid (as the remainder after an H+ ion is donated), and the cations come from the base (as the remainder after an OH- ion is accepted). The choice of anion and cation directly impacts whether a salt will be acidic, basic, or neutral. For example, combining a cation like \(\mathrm{Ni}^{3+}\) with a weaker conjugate base of a strong acid, such as \(\mathrm{Cl}^{-}\) from hydrochloric acid (HCl), will result in an acidic salt like \(\mathrm{NiCl}_{3}\).
Acid-Base Reactions
Acid-base reactions are fundamental processes in acid-base chemistry where an acid donates a proton (H+) and a base accepts a proton. This exchange forms water and a salt as products. The strength of the acids and bases involved determines the properties of the resulting salt.

A strong acid completely dissociates in solution, releasing all its H+ ions, whereas a weak acid only partially dissociates. Similarly, a strong base dissociates fully in solution, giving off OH- ions, while a weak base partially dissociates.

The type of salt formed can be predicted by the rule that 'the salt of a strong acid and a strong base forms a neutral salt, the salt of a strong acid and a weak base forms an acidic salt, and the salt of a weak acid and a strong base forms a basic salt.' This tenet can help students determine the acidity or basicity of salts, as it explains substances like sodium fluoride (\(\mathrm{NaF}\)), which acts as a basic salt due to the weak acidity of hydrofluoric acid (\(\mathrm{HF}\)).

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Most popular questions from this chapter

Phthalic acid, \(\mathrm{H}_{2} \mathrm{C}_{8} \mathrm{H}_{4} \mathrm{O}_{4}\), is a diprotic acid. It is used to make phenolphthalein indicator. \(K_{\mathrm{al}}=0.0012\), and \(K_{\mathrm{a} 2}=3.9 \times 10^{-6} .\) Calculate the \(\mathrm{pH}\) of a \(2.9 \mathrm{M}\) solution of phthalic acid. Estimate \(\left[\mathrm{HC}_{3} \mathrm{H}_{4} \mathrm{O}_{4}^{-}\right]\) and \(\left[\mathrm{C}_{8} \mathrm{H}_{4} \mathrm{O}_{4}^{2-}\right]\)

WEB Give the formula of the conjugate base of (a) \(\mathrm{HCO}_{3}^{-}\) (b) \(\mathrm{Cu}\left(\mathrm{H}_{2} \mathrm{O}\right)(\mathrm{OH})_{3}^{-}\) (c) \(\mathrm{HNO}_{2}\) (d) \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{NH}_{2}\) (e) \(\mathrm{H}_{2} \mathrm{SO}_{3}\)

What is the \(\mathrm{pH}\) of a solution obtained by adding \(13.0 \mathrm{~g}\) of \(\mathrm{NaOH}\) to \(795 \mathrm{~mL}\) of a \(0.200 \mathrm{M}\) solution of \(\mathrm{Sr}(\mathrm{OH})_{2}\) ? Assume no volume change after \(\mathrm{NaOH}\) is added.

At \(25^{\circ} \mathrm{C}\), a \(0.20 \mathrm{M}\) solution of methylamine \(\left(\mathrm{CH}_{3} \mathrm{NH}_{2}\right)\) is \(5.0 \%\) ionized. What is \(K_{b}\) for methylamine?

Using the Tables in Appendix 1, calculate \(\Delta H\) for the reaction of the following. (a) \(1.00 \mathrm{~L}\) of \(0.100 \mathrm{M} \mathrm{NaOH}\) with \(1.00 \mathrm{~L}\) of \(0.100 \mathrm{M} \mathrm{HCl}\) (b) \(1.00 \mathrm{~L}\) of \(0.100 \mathrm{M} \mathrm{NaOH}\) with \(1.00 \mathrm{~L}\) of \(0.100 \mathrm{M}\) HF, taking the heat of formation of \(\mathrm{HF}(a q)\) to be \(-320.1 \mathrm{~kJ} / \mathrm{mol}\)

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