Chapter 13: Problem 103
What is the \(\mathrm{pH}\) of a \(0.200 \mathrm{M}\) solution of \(\mathrm{H}_{2} \mathrm{SO}_{4}\) ? You may assume that the first ionization is complete. The second ionization constant is \(0.010\).
Short Answer
Expert verified
Answer: The pH of the 0.200 M H2SO4 solution is approximately 0.68.
Step by step solution
01
Determine the concentration of H+ from the first ionization of H2SO4
Since we're given that the first ionization is complete, we can directly calculate the concentration of H+ ions produced in this step. For every one mole of H2SO4, one mole of H+ ions and one mole of HSO4- ions are produced. Therefore, the concentration of H+ ions from the first ionization is equal to the concentration of H2SO4:
0.200 M.
02
Determine the concentration of H+ from the second ionization of HSO4-
Now, we need to determine the concentration of H+ ions produced from the second ionization of HSO4-. The second ionization constant (K2) is given as 0.010.
We can represent the second ionization as:
HSO4- (aq) <=> H+ (aq) + SO42- (aq)
Using the assumption that the initial concentration of H+ ions is entirely from the first ionization (as calculated in Step 1), we can set up the reaction quotient (Q) for the second ionization:
Q = [H+][SO42-] / [HSO4-]
Substituting K2 for Q and the initial concentrations into the equation, we get:
0.010 = ([0.200 + x] * x) / (0.200 - x)
Where x represents the increase in [H+] and the decrease in [HSO4-] (i.e., the amount of HSO4- ionized in the second step).
03
Solve for x
To solve for x, we can first assume that x is small compared to 0.200 (since K2 is small). This simplifies our equation to:
0.010 = (0.200 * x) / 0.200
Solving for x, we get:
x = 0.010 M
This value represents the additional concentration of H+ ions formed from the second ionization of HSO4-.
04
Calculate the total concentration of H+ ions
Now, we can find the total concentration of H+ ions in the solution by adding the concentrations from both ionizations:
[H+] = [H+ from first ionization] + [H+ from second ionization]
[H+] = 0.200 M + 0.010 M
[H+] = 0.210 M
05
Calculate the pH of the solution
Finally, we can calculate the pH of the solution using the formula:
pH = -log10([H+])
pH = -log10(0.210)
pH ≈ 0.68
So the pH of the 0.200 M H2SO4 solution is approximately 0.68.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Ionization of Sulfuric Acid
Sulfuric acid (H_2SO_4) is known for being a strong acid, meaning it dissociates readily in water. The ionization process involves step-by-step dissociation, releasing hydrogen ions (H^+). Sulfuric acid undergoes two distinct ionizations:
- The first ionization is complete in water. When sulfuric acid dissolves, it separates into H^+ ions and hydrogen sulfate ions (HSO_4^−):
\[ \text{H}_2\text{SO}_4 \rightarrow \text{H}^+ + \text{HSO}_4^- \] - The second ionization is partial. Here, HSO_4^− ions can further dissociate into H^+ and sulfate ions (SO_4^{2-}):
\[ \text{HSO}_4^- \leftrightharpoons \text{H}^+ + \text{SO}_4^{2-} \]The second ionization isn't complete due to a smaller equilibrium constant (0.010). This means HSO_4^− doesn't entirely transform into SO_4^{2-} and H^+.
Acid-Base Equilibrium
In chemistry, equilibrium describes the state of a reaction when both reactants and products exist in a stable balance. Although dynamically ongoing, the forward and backward reaction rates are equal. When talking about sulfuric acid, it is important to understand its place in the acid-base equilibrium.
The first ionization of sulfuric acid pushes more H^+ ions out due to complete dissociation. It shifts balance almost entirely to the products. However, the second ionization needs special attention, as it addresses the smaller equilibrium constant:
The first ionization of sulfuric acid pushes more H^+ ions out due to complete dissociation. It shifts balance almost entirely to the products. However, the second ionization needs special attention, as it addresses the smaller equilibrium constant:
- The second equation,\( \text{HSO}_4^- \leftrightharpoons \text{H}^+ + \text{SO}_4^{2-} \)avails only a fraction of HSO_4^− dissociating.
- The equilibrium constant, K_2 = 0.010, suggests sparse promotion of ionization in the forward direction.
pH Scale
The is a convenient tool for gauging how acidic or basic a solution is, ranging from 0 to 14. It reflects the hydrogen ion concentration and helps classify the nature of the solution:
- A low pH (below 7) signals an acidic solution with high H^+ concentration. In our problem, sulfuric acid's pH can be expected to be particularly low, reflecting its strong acidic nature.
- A neutral pH at 7 means balanced hydrogen and hydroxide ion concentrations present as in pure water.
- High pH values (above 7) denote a basic solution with elevated OH^− concentration.