Chapter 1: Problem 68
Why is the density of a regular soft drink higher than that of a diet soft drink?
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These are the key concepts you need to understand to accurately answer the question.
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Chapter 1: Problem 68
Why is the density of a regular soft drink higher than that of a diet soft drink?
These are the key concepts you need to understand to accurately answer the question.
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The dimensions of aluminum foil in a box for sale in supermarkets are \(662 / 3\) yards by 12 inches. The mass of the foil is \(0.83 \mathrm{~kg}\). If its density is \(2.70 \mathrm{~g} / \mathrm{cm}^{3}\), then what is the thickness of the foil in inches?
How would you separate into its different components (a) a mixture of the volatile gases propane, butane, and isopropane? (b) a solution of rubbing alcohol made up of isopropyl alcohol and water?
Ammonium bromide can be used as a wood preservative. Its solubility in water at \(20^{\circ} \mathrm{C}\) is \(75.5 \mathrm{~g} / 100 \mathrm{~g}\) water. At \(50^{\circ} \mathrm{C}\) its solubility is \(99.2 \mathrm{~g} / 100 \mathrm{~g}\) water. Calculate (a) the mass of ammonium bromide that dissolves in \(82.5 \mathrm{~g}\) of water at \(20^{\circ} \mathrm{C} .\) (b) the mass of water required to dissolve \(43.7 \mathrm{~g}\) of ammonium bromide at \(50^{\circ} \mathrm{C}\). (c) the mass of ammonium bromide that would not remain in solu- tion if a solution made up of \(29.0 \mathrm{~g}\) of ammonium bromide in \(35.0 \mathrm{~g}\) of water at \(50^{\circ} \mathrm{C}\) is cooled to \(20^{\circ} \mathrm{C}\).
A solid with an irregular shape and a mass of \(11.33 \mathrm{~g}\) is added to a graduated cylinder filled with water \((d=1.00 \mathrm{~g} / \mathrm{mL})\) to the \(35.0-\mathrm{mL}\) mark, After the solid sinks to the bottom, the water level is read to be at the 42.3-mL mark. What is the density of the solid?
Calculate the following to the correct number of significant figures. (a) \(x=128.5+2116.44-2244.47\) (b) \(x=0.004010 \times 2.0000 \times 50054\) (c) \(x=\frac{12.6+0.3+256.5}{1003.7}\) (d) \(x=\frac{12.20-\sqrt{1.60+4(0.36)}}{1.3409}\)
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