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Which third ionization energy is greater, that of aluminum or that of magnesium? Explain your answer.

Short Answer

Expert verified
Magnesium has a greater third ionization energy due to its stable electron configuration.

Step by step solution

01

Understanding Ionization Energy

Ionization energy refers to the energy required to remove an electron from an atom in its gaseous state. The third ionization energy involves removing the third electron, which means we need to consider the electron configuration and stability after the removal process.
02

Electron Configuration of Aluminum and Magnesium

Aluminum has the electron configuration of 1s虏 2s虏 2p鈦 3s虏 3p鹿, while magnesium has 1s虏 2s虏 2p鈦 3s虏. After removing two electrons, aluminum would have 1s虏 2s虏 2p鈦 3s鹿, and magnesium would have 1s虏 2s虏 2p鈦.
03

Examining the Third Ionization

For aluminum, removing the third electron means breaking into a new shell (the 3s subshell becomes empty and we take from the stable 2p subshell). In contrast, the third ionization of magnesium involves removing an electron from a full 2p subshell, which is more stable.
04

Comparing Ionization Energy based on Stability

The third ionization energy is higher if the electron being removed is part of a stable electron configuration. Magnesium in its 2+ state is already at a full octet (2p鈦), making it more stable than the aluminum's 2+ state (with a 3s鹿 electron). This increased stability in magnesium means greater energy is required to remove the third electron, hence higher third ionization energy.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electron Configuration
Electron configuration is key to understanding the properties of elements. In simple terms, it's the arrangement of electrons in an atom's shell. This configuration determines how an atom interacts with others and its overall stability. For instance, aluminum and magnesium have different electron configurations:
  • Aluminum: 1s虏 2s虏 2p鈦 3s虏 3p鹿
  • Magnesium: 1s虏 2s虏 2p鈦 3s虏
Each letter and number represents an energy level (shell) and the number of electrons. The numbers before the letters (e.g., 1s) indicate the shell number, while the superscript (e.g., 虏) shows the number of electrons in those shells. Understanding how electrons fill these shells helps predict an element鈥檚 reactivity and its energy requirements to remove electrons. For aluminum, the 3p鹿 electron is easier to lose, making it have different ionization characteristics than magnesium.
Periodic Trend
The periodic trend in ionization energy shows a pattern across the periodic table. As you move across a period from left to right, ionization energy tends to increase. This increase is due to the greater nuclear charge, which pulls electrons closer to the nucleus. For example, comparing aluminum and magnesium:
  • Both are in the same period, meaning they have the same number of electron shells.
  • However, aluminum has a higher nuclear charge than magnesium.
Despite this rule, when examining ionization energies beyond the first (such as the third ionization energy), electron stability plays a more significant role. While magnesium and aluminum both lose electrons to reach stability, magnesium maintains a more stable electron configuration after losing the first two electrons, influencing its third ionization energy.
Electron Stability
Electron stability relates to how electron configurations resist changes, such as when they lose electrons. Stability increases when an atom's electron configuration resembles that of a noble gas. When removing electrons, if you disturb a stable configuration, it requires more energy. Consider magnesium and aluminum:
  • Magnesium: After losing two electrons becomes 1s虏 2s虏 2p鈦, very stable (like neon).
  • Aluminum: After losing two electrons, becomes 1s虏 2s虏 2p鈦 3s鹿, less stable.
Therefore, removing a third electron from magnesium breaks into this stable setup, demanding high energy. In contrast, removing the third electron from aluminum does not significantly affect stability, as it's still trying to empty its outer shell. Thus, magnesium's third ionization energy is higher, reflecting these stability considerations.

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