/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 19 Explain why the electron affinit... [FREE SOLUTION] | 91Ó°ÊÓ

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Explain why the electron affinity of lithium is slightly favorable (exothermic), whereas the electron affinity of beryllium is unfavorable (endothermic). Contrast these trends with the ionization energy trends of these two elements.

Short Answer

Expert verified
Lithium's electron affinity is exothermic due to added electron stabilizing a shell, whereas beryllium's is endothermic, disrupting stability. Ionization energy trends contrast due to configuration stability.

Step by step solution

01

Understanding Electron Affinity

Electron affinity refers to the change in energy when an electron is added to a neutral atom in the gaseous state. A more negative electron affinity value indicates that the process releases more energy and is exothermic (favorable), whereas a positive or less negative value indicates the process is endothermic (unfavorable).
02

Analyzing Lithium Electron Affinity

Lithium, with an atomic structure of 1s² 2s¹, will release energy when accepting an additional electron to partially fill its 2s shell. This makes gaining an electron slightly favorable (exothermic) as it moves toward a more filled shell.
03

Analyzing Beryllium Electron Affinity

Beryllium has a filled 2s subshell (1s² 2s²) and would require adding an electron to the higher energy 2p orbital. As this disrupts the stable electronic configuration without completing a shell, it is unfavorable (endothermic).
04

Comparing with Ionization Energy Trends

Ionization energy is the energy required to remove an electron from an atom in its gaseous state. For lithium, it removes one electron from the 2s subshell, while for beryllium, removal still affects the stable 2s subshell. Thus, beryllium has a significantly higher ionization energy due to its stable electron configuration compared to lithium.
05

Conclusion on Trends

Lithium's slight exothermic electron affinity contrasts with beryllium's endothermic affinity due to electron configuration. The trends in ionization energy are opposite, as beryllium requires more energy to remove an electron due to its filled 2s shell.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ionization Energy
Ionization energy is a crucial concept in understanding atomic properties. It refers to the amount of energy required to remove an electron from an atom or ion in its gaseous state. This process generally becomes more difficult as you move from left to right across a period in the periodic table, due to increasing nuclear charge attracting the electrons more strongly. However, as you descend a group, ionization energy tends to decrease because the added inner shells of electrons cause increased electron shielding, thus reducing the effective nuclear charge felt by the outer electrons. When we compare the ionization energies of lithium (Li) and beryllium (Be), we see the influence of their electron configurations. Lithium, with its 1s² 2s¹ configuration, requires less energy to remove the outer electron from its partially filled 2s subshell. On the other hand, beryllium, with a filled 1s² 2s² configuration, exhibits a higher ionization energy due to the stable filled subshell. Removing an electron from beryllium means breaking this stability, requiring significantly more energy. Therefore, despite being consecutive elements, lithium and beryllium exhibit notable differences in their ionization energies based on their atomic structures.
Atomic Structure
The concept of atomic structure is foundational in chemistry, dictating how elements behave in various chemical contexts. Atoms consist of a nucleus surrounded by electrons. These electrons are arranged in various orbitals, which are defined by quantum numbers that specify their position and energy. In particular, for lithium and beryllium, the arrangement of these electrons helps explain differences in their chemical reactivity. Lithium (atomic number 3) has an electron configuration of 1s² 2s¹, with one electron in its outermost shell, making it relatively reactive. Beryllium (atomic number 4), on the other hand, has a configuration of 1s² 2s², with its outer 2s subshell completely filled, thus exhibiting less reactivity under standard conditions. Understanding atomic structure not only helps explain elements' reactivity but also their affinity for electrons and energy requirements for electron removal, highlighting the interplay of electron configuration and chemical properties.
Electron Configuration
Electron configuration describes the distribution of electrons in an atom's orbitals, which is crucial for predicting chemical behavior. The configuration is notated by designating energy levels and the number of electrons within each subshell. For example, lithium is represented as 1s² 2s¹, while beryllium is 1s² 2s². This pattern of electron distribution explains many of the differences in elements' properties, like their electron affinity and ionization energy. In lithium's case, accepting an additional electron to partially fill its 2s subshell results in a slightly exothermic process, meaning it releases energy, whereas beryllium, having to accommodate an extra electron in the higher energy 2p orbital, undergoes an unfavorable endothermic change. Appreciating electron configurations is vital for understanding why adding electrons to different elements can result in either favorable (exothermic) or unfavorable (endothermic) reactions, and why energy requirements for ionization can vary so significantly among seemingly similar elements.

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Most popular questions from this chapter

Aluminum atoms are larger than silicon atoms, and the first ionization energy of silicon is greater than that of aluminum. Explain these trends, using differences in the effective nuclear charges.

The Case Study in this chapter introduced cesium fluoride, \(\mathrm{CsF}\). (a) A \(10.76-\mathrm{g}\) sample of impure \(\mathrm{CsF}\) was dissolved in \(100 \mathrm{~mL}\) water. The sample was mixed with excess aqueous calcium nitrate solution to precipitate insoluble calcium fluoride. The precipitate was filtered, dried, and weighed. A total of \(2.35 \mathrm{~g}\) calcium fluoride was collected. What was the percentage of \(\mathrm{CsF}\) in the original sample? (b) Given the reaction $$ \mathrm{CsF}(\mathrm{s})+\mathrm{HNO}_{3}(\mathrm{aq}) \rightarrow \mathrm{HF}(\mathrm{g})+\mathrm{CsNO}_{3}(\mathrm{aq}) $$ what volume of \(\mathrm{HF}(\mathrm{g})\) is produced at standard temperature and pressure (STP) if 100.0 g CsF reacts? (c) CsF is not only colorless but transparent to infrared light up to a wavelength limit of \(15.0 \mu \mathrm{m}\). What is the energy of a photon of light having that wavelength? What is the energy of a mole of photons of that wavelength? How many moles of photons are needed to supply the same amount of energy as produced in the reaction given in the Case Study?

Graph ionization energy versus atomic number for the second-period elements. Explain the trends and any discontinuities in the graph.

Using only a periodic table as a guide, arrange each of the following series of species in order of increasing first ionization energy. (a) \(\mathrm{O}, \mathrm{O}^{2-}, \mathrm{F}\) (b) \(\mathrm{C}, \mathrm{Si}, \mathrm{N}\) (c) \(\mathrm{Te}, \mathrm{Ru}, \mathrm{Sr}\)

Write the electron configurations of the following elements after finding their locations in the periodic table. (a) \(\mathrm{P}\) (b) \(\mathrm{Sr}\) (c) \(\mathrm{Sm}\) (d) \(\mathrm{Ra}\)

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