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Use the aufbau procedure to obtain the electron configuration and orbital diagram for atoms of the following elements. (a) Be (b) \(\underline{B}\) (c) \(\mathrm{Ne}\) (d) \(\mathrm{Rb}\)

Short Answer

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(a) Be: 1s虏 2s虏, (b) B: 1s虏 2s虏 2p鹿, (c) Ne: 1s虏 2s虏 2p鈦, (d) Rb: [Kr]5s鹿.

Step by step solution

01

Understanding the Aufbau Principle

The aufbau principle states that electrons fill atomic orbitals of the lowest available energy levels before occupying higher levels. It follows the sequence defined by the increasing energy order of orbitals: 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, and so on.
02

Finding Electron Configuration for Be

Beryllium (Be) has an atomic number of 4, meaning it has 4 electrons. According to the aufbau principle, these electrons will fill the 1s and 2s orbitals: 1. Fill the 1s orbital with 2 electrons: 1s虏 2. Fill the 2s orbital with the remaining 2 electrons: 2s虏 The electron configuration for Be is 1s虏 2s虏.
03

Drawing Orbital Diagram for Be

To draw the orbital diagram, represent each orbital with a box and each electron with an arrow: - 1s: 鈫戔啌 - 2s: 鈫戔啌 This shows that both the 1s and 2s orbitals are fully occupied by 2 electrons each.
04

Finding Electron Configuration for B

Boron (B) has an atomic number of 5, so it has 5 electrons. Filling the orbitals: 1. Fill the 1s orbital with 2 electrons: 1s虏 2. Fill the 2s orbital with 2 electrons: 2s虏 3. Place the remaining 1 electron in the 2p orbital: 2p鹿 The electron configuration for B is 1s虏 2s虏 2p鹿.
05

Drawing Orbital Diagram for B

Draw the orbital diagram where each orbital is a box and electrons are arrows: - 1s: 鈫戔啌 - 2s: 鈫戔啌 - 2p: 鈫 This shows that the 1s and 2s orbitals are fully occupied, and the 2p orbital has 1 electron.
06

Finding Electron Configuration for Ne

Neon (Ne) has an atomic number of 10, providing 10 electrons to distribute: 1. Fill the 1s orbital: 1s虏 2. Fill the 2s orbital: 2s虏 3. Fill the 2p orbital with the remaining 6 electrons: 2p鈦 The electron configuration for Ne is 1s虏 2s虏 2p鈦.
07

Drawing Orbital Diagram for Ne

For the orbital diagram of Ne: - 1s: 鈫戔啌 - 2s: 鈫戔啌 - 2p: 鈫戔啌 鈫戔啌 鈫戔啌 This shows that the 1s, 2s, and 2p orbitals are fully filled.
08

Finding Electron Configuration for Rb

Rubidium (Rb) has an atomic number of 37 and follows the same filling order: 1. Proceed to fill from 1s up to 4p as for a full Ar [Argon] configuration: 1s虏 2s虏 2p鈦 3s虏 3p鈦 4s虏 3d鹿鈦 4p鈦 2. Fill the next lowest energy orbital, 5s, with the 1 electron: 5s鹿 The electron configuration for Rb is [Kr]5s鹿, using the noble gas shorthand.
09

Drawing Orbital Diagram for Rb

Represent the orbitals: - Include all orbitals up to 4p as completely filled, similar to [Kr]. - 5s: 鈫 This shows that all preceding orbitals are filled, and the 5s orbital has 1 electron.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electron Configuration
Electron configurations describe the distribution of electrons in an atom's orbitals. Understanding electron configuration is crucial because it helps predict the chemical behavior of elements. This concept is rooted in the quantum mechanical model of the atom. The rules for filling electrons are:
  • Electrons occupy the lowest energy orbitals first. Known as the aufbau principle, which means "building up" in German.
  • Each orbital can hold a maximum of two electrons. This is based on the Pauli exclusion principle, which states that no two electrons can have the same set of quantum numbers within an atom.
  • Electrons fill orbitals in a way that maximizes the number of unpaired electrons, known as Hund's rule. This rule helps in reducing electron-electron repulsions.

For example, for Beryllium (Be), the electron configuration is 1s虏 2s虏. This means the first shell's s orbital is filled with 2 electrons, and the second shell's s orbital is also filled with 2, using up all four electrons available since Be's atomic number is 4.
Orbital Diagram
The orbital diagram provides a visual representation of electron configuration. It shows how electrons are distributed within an atom's orbitals. Each orbital is shown as a box, and each electron is represented by an arrow. Arrows pointing up or down indicate the electron's spin.

Here鈥檚 how to understand orbital diagrams step by step:
  • A single box represents one orbital, capable of holding two electrons at most.
  • Arrows are drawn inside the box, representing electrons. A single arrow indicates a single electron, while two arrows (opposite directions: 鈫戔啌) indicate electron pairs.
  • Electrons should first fill each orbital singly in parallel spins, in line with Hund鈥檚 rule, before doubling up.

In the orbital diagram for Boron (B), you'll see:
  • 1s: 鈫戔啌 (Two paired electrons)
  • 2s: 鈫戔啌 (Two paired electrons)
  • 2p: 鈫 (One unpaired electron)
This diagram helps us visualize the unpaired electron in Boron, showing us its potential for bonding and chemical reactivity.
Atomic Orbitals
Atomic orbitals are regions around the nucleus where electrons are most likely to be found. They are defined by the quantum numbers that describe the energy, shape, and orientation of these regions. Understanding atomic orbitals is vital for grasping how atoms interact in chemical reactions.

Atomic orbitals include s, p, d, and f orbitals, each with a distinct shape:
  • s Orbitals: Spherically shaped, with only one s orbital per energy level.
  • p Orbitals: Dumbbell-shaped, consisting of three orbitals at each energy level, oriented along the x, y, and z axes.
  • d Orbitals: More complex in shape, each energy level above n=3 contains five d orbitals.
  • f Orbitals: Even more complex, each with seven orbitals at energy levels n=4 and higher.

By understanding these orbitals, we can predict and explain the behavior of electrons in various elements. For instance, Rubidium (Rb) uses the 5s orbital as its valence orbital, filled with only one electron. This results in its unique chemical properties, such as high reactivity and being part of the alkali metals group.

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Most popular questions from this chapter

The red color of neon signs is due to electromagnetic radiation with a wavelength of \(640 \mathrm{nm}\). What is the change in the energy of a neon atom when it emits a photon of this wavelength?

In each part, a set of quantum numbers is given. If the set is an allowed combination of \(n, \ell, m_{\ell}\), and \(m_{s}\), give the subshell to which this wave function belongs \((1 s, 2 s, 2 p\), and so on). If the combination of quantum numbers is not allowed, state why. (a) \(n=2, \ell=1, m_{\ell}=0, m_{s}=-\frac{1}{2}\) (b) \(n=2, \ell=2, m_{\ell}=-2, m_{s}=+\frac{1}{2}\) (c) \(n=3, \ell=0, m_{\ell}=0, m_{s}=+\frac{1}{2}\) (d) \(n=1, \ell=0, m_{\ell}=1, m_{s}=-\frac{1}{2}\) (e) \(n=3, \ell=2, m_{\ell}=2, m_{s}=+\frac{1}{2}\) (f) \(n=5, \ell=0, m_{\ell}=0, m_{s}=+\frac{1}{2}\)

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