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Arrange the following gases, at the temperatures indicated, in order of increasing rms speed of the particles: helium at \(100^{\circ} \mathrm{C}\), neon at \(50^{\circ} \mathrm{C}\), argon at \(0{ }^{\circ} \mathrm{C}\).

Short Answer

Expert verified
Argon at 0°C < Neon at 50°C < Helium at 100°C

Step by step solution

01

Understand the Concept

The root mean square (rms) speed of gas particles can be calculated using the formula \( v_{rms} = \sqrt{\frac{3kT}{m}} \), where \( k \) is the Boltzmann constant, \( T \) is the absolute temperature in Kelvin, and \( m \) is the mass of a single particle. The key factors here are temperature and molar mass, which affects \( m \).
02

Convert Temperatures to Kelvin

Convert given temperatures to Kelvin by adding 273.15: \( T_{He} = 100 + 273.15 = 373.15 \, K \), \( T_{Ne} = 50 + 273.15 = 323.15 \, K \), \( T_{Ar} = 0 + 273.15 = 273.15 \, K \).
03

Find Molar Mass of Each Gas

Use the periodic table to find the molar masses: Helium (\(4 \, g/mol\)), Neon (\(20.18 \, g/mol\)), Argon (\(39.95 \, g/mol\)). In calculations, use grams/mole and convert to kilograms by dividing by 1000.
04

Calculate \( v_{rms} \) for Each Gas

Use \( v_{rms} = \sqrt{\frac{3RT}{M}} \), where \( R \) is the ideal gas constant (8.314 J/mol·K) and \( M \) is the molar mass. Calculate for each gas:- For Helium: \( v_{rms} = \sqrt{\frac{3 \cdot 8.314 \cdot 373.15}{0.004}} \).- For Neon: \( v_{rms} = \sqrt{\frac{3 \cdot 8.314 \cdot 323.15}{0.02018}} \).- For Argon: \( v_{rms} = \sqrt{\frac{3 \cdot 8.314 \cdot 273.15}{0.03995}} \).
05

Compare Results

After computing the square root, compare the rms speeds. Higher temperature and lighter gas (lower molar mass) result in higher speed.
06

Arrange in Increasing Order

Based on the calculations (helium > neon > argon), arrange the gases in increasing order of their calculated \( v_{rms} \) values.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Root Mean Square Speed
The root mean square speed (\( v_{rms} \)) is an important concept in the kinetic theory of gases. It provides a way to determine the average speed of gas particles at a given temperature. The formula used to calculate this speed is \( v_{rms} = \sqrt{\frac{3RT}{M}} \), where \( R \) represents the ideal gas constant, \( T \) is the temperature in Kelvin, and \( M \) is the molar mass of the gas.Understanding the root mean square speed is crucial, as it helps in comparing different gases at various temperatures. Since the rms speed depends on the molar mass and temperature, gases with lower molar masses and at higher temperatures move faster. This can be used to arrange or compare the speeds of different gases under particular conditions with ease.
Molar Mass
Molar mass, denoted as \( M \), is the mass of one mole of a substance, typically expressed in grams per mole (g/mol). It plays a vital role in determining the root mean square speed. To find the molar mass, one can refer to the periodic table, where the atomic or molecular masses are listed.For gases, lighter molecules, meaning those with lower molar masses, will generally have higher rms speeds if other conditions like temperature are constant. In the exercise, helium has the lowest molar mass, making it the fastest among the given gases. Converting the molar mass from grams per mole to kilograms per mole is necessary for calculations involving the ideal gas constant, thus making the results coherent and accurate.
Ideal Gas Constant
The ideal gas constant (\( R \)) is a key part of the ideal gas equation and is used in calculating the root mean square speed. This constant has a value of 8.314 J/mol·K. It relates the energy scale to the temperature scale, allowing for various calculations involving gas properties. In the calculation of rms speed, \( R \) helps connect temperature and molar mass to derive the speed. Having a clear grasp of this constant and its role in equations aids in understanding a variety of thermodynamic and kinetic expressions concerning gases.
Temperature Conversion
Temperature conversion is an essential step when dealing with gas calculations. Most scientific calculations, including those involving the root mean square speed, require temperatures to be in Kelvin. The Kelvin scale is an absolute temperature scale starting from absolute zero, making it suitable for use in physical equations. To convert Celsius to Kelvin, you simply add 273.15 to the Celsius temperature. For example, converting 100 °C to Kelvin would result in 373.15 K. This step is crucial because it ensures all variables are in the correct units, maintaining consistency and accuracy in further calculations. Understanding this conversion ensures that you can solve problems correctly and efficiently.

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Most popular questions from this chapter

Assuming the volumes of all gases in the reaction are measured at the same temperature and pressure, calculate the volume of water vapor obtainable by the explosive reaction of a mixture of \(725 \mathrm{~mL}\) of hydrogen gas and \(325 \mathrm{~mL}\) of oxygen gas.

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Calculate the molar mass of a gas if equal volumes of oxygen and the unknown gas take 5.2 and 8.3 minutes, respectively, to effuse into a vacuum through a small hole under the same conditions of constant pressure and temperature.

Hydrogen gas is frequently prepared in the laboratory by the reaction of zinc metal with sulfuric acid, \(\mathrm{H}_{2} \mathrm{SO}_{4}\). The other product of the reaction is zinc(II) sulfate. The hydrogen gas is generally collected over water. What volume of pure \(\mathrm{H}_{2}\) gas is produced by the reaction of \(0.113 \mathrm{~g}\) zinc metal and excess sulfuric acid if the temperature is 24 \({ }^{\circ} \mathrm{C}\) and the barometric pressure is 750 torr?

A sample of gas occupies \(135 \mathrm{~mL}\) at \(22.5^{\circ} \mathrm{C} ;\) the pressure is 165 torr. What is the pressure of the gas sample when it is placed in a \(252-\mathrm{mL}\) flask at a temperature of \(0.0^{\circ} \mathrm{C} ?\)

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