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Calculate the partial pressure of hydrogen gas, in atm, in a container that holds 0.220 mol hydrogen and \(0.432 \mathrm{~mol}\) nitrogen. The total pressure is 5.22 atm.

Short Answer

Expert verified
The partial pressure of hydrogen is approximately 1.76 atm.

Step by step solution

01

Understand Dalton's Law of Partial Pressures

According to Dalton's Law of Partial Pressures, the total pressure of a mixture of gases is equal to the sum of the partial pressures of each individual gas. Each gas in the mixture exerts a partial pressure which is proportional to its mole fraction.
02

Calculate Total Moles of Gas

Add the moles of hydrogen and nitrogen together to find the total moles of gas in the container. \[0.220 + 0.432 = 0.652 \, \text{mol}\]
03

Determine Mole Fraction of Hydrogen

To find the mole fraction of hydrogen (\(X_H\)), divide the moles of hydrogen by the total moles of gas.\[X_H = \frac{0.220}{0.652}\approx 0.337\]
04

Calculate Partial Pressure of Hydrogen

Use the mole fraction of hydrogen and the total pressure to find the partial pressure of hydrogen. Multiply the mole fraction by the total pressure.\[P_H = X_H \times P_{\text{total}}= 0.337 \times 5.22 \, \text{atm}\approx 1.76 \, \text{atm}\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Partial Pressure
In a gas mixture, each gas contributes to the total pressure of the system. This contribution is what we call the partial pressure of the gas. According to Dalton's Law of Partial Pressures, the total pressure exerted by a mixture of non-reactive gases is the sum of the partial pressures of all the gases present. This means that each gas behaves as if it is alone in the container, exerting its own pressure independently of others. For instance, if you have hydrogen and nitrogen in a container, each of these gases will exert its own pressure based on its quantity in the mixture. The sum of these individual pressures will give you the total pressure inside the container. To calculate the partial pressure of a specific gas, you'll need two things: the mole fraction of that gas and the total pressure of the gas mixture.
Mole Fraction
The mole fraction is a way of expressing the concentration of a component in a gas mixture. It is defined as the number of moles of one particular gas divided by the total number of moles of all gases in the mixture. In mathematical terms, it's expressed as:
  • The mole fraction of a gas (\(X\)) = \(\frac{\text{moles of the gas}}{\text{total moles of all gases}}\)
For example, if you have 0.220 mol of hydrogen gas and 0.432 mol of nitrogen gas, the total moles in the mixture will be 0.220 + 0.432 = 0.652 mol. To find the mole fraction of hydrogen, divide the moles of hydrogen by the total moles: \(X_H = \frac{0.220}{0.652} \approx 0.337\). The mole fraction tells us the proportion of the gas in the mixture.
Gas Mixture
A gas mixture consists of several different gases combined. In a container with a mixture of gases, each molecule of gas interacts independently and contributes to the overall properties of the gas mixture, like pressure and volume. The molecules of each type of gas will mix with the others without changing chemically. What makes gas mixtures such an interesting topic is the predictability offered by Dalton's Law and other gas laws. This allows chemists to predict how changing one aspect of the mixture, such as temperature or volume, can affect the pressure and behavior of the gases. Knowing the total moles, mole fraction, and individual components helps in various applications, including calculating partial pressures.
Chemical Calculations
Chemical calculations involve using mathematical equations to calculate the properties or quantities in a chemical reaction or mixture. When dealing with gases, these calculations often include using Dalton's Law, which helps to determine the partial pressures of individual gases within a mixture. Consider the example where you want to find the partial pressure of hydrogen in a mixture with nitrogen.
  • First, calculate the total moles of gases present.
  • Determine the mole fraction of hydrogen.
  • Finally, calculate the partial pressure using the formula: \(P_\text{partial} = X_\text{gas} \times P_\text{total}\).
In practice, chemical calculations are essential for predicting how gas mixtures will behave in different conditions, helping us better control and utilize them in industrial, laboratory, and everyday settings. They are fundamental in ensuring the safety and efficiency of different chemical processes.

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Most popular questions from this chapter

The pressure of a \(900-\mathrm{mL}\) sample of helium is increased from 2.11 to 4.33 atm, and the temperature is also increased from \(0^{\circ} \mathrm{C}\) to \(22^{\circ} \mathrm{C}\). What is the new volume (in mL) of the sample?

For each of the following pairs of gases at the given conditions, predict which one would more closely follow the ideal gas law. Explain your choice. (a) oxygen (boiling point \(=-183^{\circ} \mathrm{C}\) ) gas at \(-150^{\circ} \mathrm{C}\) or at \(30^{\circ} \mathrm{C}\), both measured at \(1.0 \mathrm{~atm}\) (b) nitrogen (boiling point \(=-196^{\circ} \mathrm{C}\) ) or xenon (boiling point \(=-107{ }^{\circ} \mathrm{C}\) ) gas at \(-100{ }^{\circ} \mathrm{C},\) both measured at \(1.0 \mathrm{~atm}\) (c) argon gas at 1 atm or at 50 atm of pressure, both measured at \(25^{\circ} \mathrm{C}\)

Why do \(1 \mathrm{~mol} \mathrm{~N}_{2}\) and \(1 \mathrm{~mol} \mathrm{O}_{2}\) both exert the same pressure if placed in the same 20 - \(\mathrm{L}\) container? Is the mass of the gas sample the same in both cases? Explain why it is the same or different, and if it is different, predict which gas sample weighs more.

A gas effuses 1.55 times faster than propane \(\left(\mathrm{C}_{3} \mathrm{H}_{8}\right)\) at the same temperature and pressure. (a) Is the gas heavier or lighter than propane? (b) What is the molar mass of the gas?

What volume of oxygen gas, in liters, at \(30^{\circ} \mathrm{C}\) and 0.993 atm reacts with excess hydrogen to produce \(4.22 \mathrm{~g}\) water?

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