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(a) Calculate the mass, in grams, of \(3.50 \mathrm{~mol} \mathrm{NO}_{2}\). (b) Calculate the number of molecules in this sample. (c) Calculate the number of nitrogen and oxygen atoms in the sample.

Short Answer

Expert verified
The mass of 3.50 mol NOâ‚‚ is 161.035 g. There are approximately \(2.1077 \times 10^{24}\) molecules, with \(2.1077 \times 10^{24}\) nitrogen atoms and \(4.2154 \times 10^{24}\) oxygen atoms.

Step by step solution

01

Determine the molar mass of NOâ‚‚

The molar mass of a compound is the sum of the atomic masses of its elements. First, we find the atomic masses: nitrogen (N) has an atomic mass of 14.01 g/mol and oxygen (O) has an atomic mass of 16.00 g/mol. NOâ‚‚ contains one nitrogen and two oxygen atoms, so its molar mass is \(14.01 + 2 \times 16.00 = 46.01\) g/mol.
02

Calculate the mass of 3.50 mol of NOâ‚‚

To calculate the mass, multiply the molar mass of NOâ‚‚ by the number of moles: \[ \text{Mass} = 3.50 \text{ mol} \times 46.01 \text{ g/mol} = 161.035 \text{ g}. \]
03

Calculate the number of molecules

To find the number of molecules, use Avogadro's number \(6.022 \times 10^{23}\) molecules/mol: \[ \text{Number of molecules} = 3.50 \text{ mol} \times 6.022 \times 10^{23} \text{ molecules/mol} = 2.1077 \times 10^{24} \text{ molecules}. \]
04

Calculate the number of nitrogen atoms

Each molecule of NOâ‚‚ contains 1 nitrogen atom. Therefore, the number of nitrogen atoms is equal to the number of molecules: \[ \text{Number of nitrogen atoms} = 2.1077 \times 10^{24}. \]
05

Calculate the number of oxygen atoms

Each molecule of NOâ‚‚ contains 2 oxygen atoms. Thus, the total number of oxygen atoms is twice the number of molecules: \[ \text{Number of oxygen atoms} = 2 \times 2.1077 \times 10^{24} = 4.2154 \times 10^{24}. \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Molar Mass
Molar mass is an essential concept in chemistry that relates directly to the mass of a substance per mole of its entities. It's particularly useful when converting between grams and moles.
To calculate the molar mass of a compound, sum the atomic masses of all the atoms within a single molecule of the compound. Atomic masses for each element can be found on the periodic table and are usually given in units of grams per mole (g/mol).

For example, in the compound nitrogen dioxide ( ext{NO}_2), the molar mass is determined by adding the atomic masses of nitrogen and oxygen. Since the atomic mass of nitrogen (N) is 14.01 g/mol and oxygen (O) is 16.00 g/mol, the molar mass is calculated as follows:
- 1 nitrogen atom: 14.01 g/mol
- 2 oxygen atoms: 2 × 16.00 g/mol = 32.00 g/mol
Therefore, the molar mass of ext{NO}_2 is 46.01 g/mol.
Knowing the molar mass allows us to convert between the mass and the number of moles of a substance, making it easier to conduct further calculations such as determining the number of molecules.
Avogadro's Number
Avogadro's number is a key concept when exploring the microscopic quantities of substances. Named after Amedeo Avogadro, this number allows us to link the macroscopic and microscopic worlds, converting moles to particles such as atoms and molecules.
Avogadro's number is defined as precisely 6.022 × 10^{23} molecules per mole. This constant indicates how many discrete entities, such as molecules or atoms, are present in one mole of a substance.

When faced with a sample quantity expressed in moles, multiplying the number of moles by Avogadro's number will yield the total number of entities in that sample. For instance, with a sample of 3.50 moles of ext{NO}_2, the number of molecules can be calculated as:
- ext{Number of molecules} = 3.50 moles × 6.022 × 10^{23} molecules/mole = 2.1077 × 10^{24} molecules.
This profound relationship helps us understand the scale of chemical substances at an atomic level and conduct quantitative analyses in chemistry.
Molecule Count
The count of molecules in a given quantity of chemical substance is essential for understanding reactions and stoichiometry. By knowing the number of molecules, one can ascertain how a substance will interact during a chemical reaction.
As previously calculated, using Avogadro's number, the number of molecules in a given amount of moles can be determined. For example, given 3.50 moles of ext{NO}_2, the number is calculated to be 2.1077 × 10^{24} molecules.

Counting molecules is particularly useful for:
  • Understanding the extent of reactions.
  • Calculating yields in chemical reactions.
  • Relating the macroscopic observable quantities to the underlying chemical changes.
Thus, molecule counting forms a critical part of analytical and preparative chemistry practices.
Atom Count
Counting atoms in a molecular sample enables chemists to balance equations and predict products and reactants effectively. Understanding how many atoms of each element are present helps clarify the structure and composition of a compound.
In a compound like ext{NO}_2, each molecule consists of one nitrogen atom and two oxygen atoms. Thus, to find the total number of nitrogen and oxygen atoms, we first need to calculate the number of molecules, and then consider the atomic composition of each molecule.

For the nitrogen dioxide sample calculated previously:
- ext{Number of nitrogen atoms} = 2.1077 × 10^{24} nitrogen atoms (since there's one nitrogen atom per molecule).
- ext{Number of oxygen atoms} = 2 × 2.1077 × 10^{24} = 4.2154 × 10^{24} oxygen atoms (as there are two oxygen atoms per molecule).
Knowing the count of atoms is crucial for chemical analyses, as it guides how much of a reactant is needed and what products may form in a reaction.

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Most popular questions from this chapter

Acetic acid gives vinegar its sour taste. Analysis of acetic acid shows it is \(40.0 \%\) carbon, \(6.71 \%\) hydrogen, and \(53.3 \%\) oxygen. Its molar mass is \(60 \mathrm{~g} / \mathrm{mol}\). What is its molecular formula?

Give the molar mass of the following substances. (a) \(\mathrm{Na} \mathrm{OH}\) (b) \(\mathrm{C}_{2} \mathrm{H}_{4}\) (c) \(\mathrm{Mg}(\mathrm{OH})_{2}\)

A The reaction of hydrazine, \(\mathrm{N}_{2} \mathrm{H}_{4}\), with molecular oxygen is violent because it rapidly produces large quantities of gases and heat. For this reason, hydrazine has been used as a rocket fuel. The products of the reaction are \(\mathrm{NO}_{2}\) and water. Write the balanced equation for this reaction. Assign oxidation numbers to each element in the reactants and products, and indicate which element is oxidized and which is reduced.

\(\mathrm{In}_{2} \mathrm{~S}_{3}\) can be converted into metallic indium by a twostep process. First, it is converted into \(\mathrm{In}_{2} \mathrm{O}_{3}\) by reaction with oxygen. The other product of the reaction is \(\mathrm{SO}_{2}\). Indium metal is obtained by reaction of \(\mathrm{In}_{2} \mathrm{O}_{3}\) with carbon. Assume that the other product of the second reaction is carbon dioxide. (a) Write the two equations for this process. (b) Calculate the mass, in kilograms, of indium produced from \(35.7 \mathrm{~kg} \operatorname{In}_{2} \mathrm{~S}_{3}\), assuming excesses of the other reactants.

Carvone is an oil isolated from caraway seeds that is used in perfumes and soaps. This compound contains \(79.95 \%\) carbon, \(9.40 \%\) hydrogen, and \(10.65 \%\) oxygen. What is its empirical formula?

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