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(a) Write the equation for hydrochloric acid dissolving in water. (b) Write the equation for barium nitrate dissolving in water.

Short Answer

Expert verified
(a) HCl (aq) \rightarrow H^+ (aq) + Cl^- (aq) (b) Ba(NO_3)_2 (aq) \rightarrow Ba^{2+} (aq) + 2 NO_3^- (aq)

Step by step solution

01

Dissociation of Hydrochloric Acid

When hydrochloric acid (HCl) is added to water, it dissociates completely to form hydrogen ions (H^+) and chloride ions (Cl^-). The chemical equation for this process is:\[ \text{HCl} (aq) \rightarrow \text{H}^+ (aq) + \text{Cl}^- (aq) \]
02

Dissociation of Barium Nitrate

Barium nitrate (Ba(NO_3)_2) is a salt that dissociates into its ions when dissolved in water. It dissociates to form barium ions (Ba^{2+}) and nitrate ions (NO_3^-). The balanced chemical equation is:\[ \text{Ba(NO}_3\text{)_2} (aq) \rightarrow \text{Ba}^{2+} (aq) + 2\,\text{NO}_3^- (aq) \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Dissociation
When substances dissolve in water, particularly ionic compounds, a process called dissociation occurs. Dissociation is an essential concept in chemistry and plays a crucial role in understanding how ionic compounds interact in aqueous solutions.

Let’s take the example of hydrochloric acid (HCl). When it is added to water, it dissociates into hydrogen ions (H+) and chloride ions (Cl-). This implies that the entire HCl molecule breaks up (or dissociates) into these smaller, charged particles. In equations, this process is represented as follows:
  • HCl (aq) → H+ (aq) + Cl- (aq)
Hydrochloric acid shows complete dissociation, indicating all of its molecules separate into ions in water. This is typical of strong acids, which completely dissociate in a solution.

Barium nitrate, another example, dissociates into barium ions (Ba2+) and nitrate ions (NO3-) when dissolved in water:
  • Ba(NO3)2 (aq) → Ba2+ (aq) + 2 NO3- (aq)
In this instance, one formula unit of barium nitrate produces one barium ion and two nitrate ions, fully demonstrating dissociation of a salt in water.
Ionic Equations
Ionic equations are used to represent the dissociation of ionic compounds in solutions. These equations depict how compounds break apart into their constituent ions. There are two types of ionic equations: complete ionic equations and net ionic equations.

For example, when HCl dissolves in water and dissociates, the complete ionic equation reveals every ion present in the solution:
  • HCl (aq) → H+ (aq) + Cl- (aq)
In cases involving reactions between ions, a net ionic equation may be used to highlight the reacting species by canceling out the spectator ions. Spectator ions are ions that do not participate in the actual chemical reaction.

Consider a reaction between barium nitrate and sodium sulfate (not given in the original exercise), where an insoluble precipitate forms:
  • Complete Equation: Ba2+ (aq) + 2 NO3- (aq) + 2 Na+ (aq) + SO42- (aq) → BaSO4 (s) + 2 Na+ (aq) + 2 NO3- (aq)
  • Net Ionic Equation: Ba2+ (aq) + SO42- (aq) → BaSO4 (s)
This simplification aids in focusing on the actual chemical changes happening in the solution, providing clarity on how ions react.
Aqueous Solutions
An aqueous solution is formed when a substance is dissolved in water. It is part of many everyday processes and is prevalent in numerous chemical reactions. The term "aqueous" refers to something that is water-based; this is indicated by the symbol (aq) in chemical equations.

Water is a versatile solvent because of its polar nature and ability to dissolve a wide range of substances, especially ionic compounds and acids. When compounds like hydrochloric acid or barium nitrate dissolve in water, they dissociate into ions. These ions remain dispersed throughout the water, making the solution conductive to electricity.

Key characteristics of aqueous solutions include:
  • Conductivity: Due to the presence of free ions, aqueous solutions can conduct an electric current.
  • Reactivity: The ions in aqueous solution can undergo various chemical reactions, such as precipitation, acid-base reactions, and redox reactions.
  • Solubility: The solubility of a substance in water determines how much of it can dissolve to form an aqueous solution.
Understanding these properties is crucial, especially when predicting the outcomes of chemical reactions or analyzing the composition of solutions in experiments. Aqueous solutions serve as essential mediums in both industrial processes and biological systems.

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Most popular questions from this chapter

A \(3.11-\mathrm{g}\) sample containing only carbon, hydrogen, and nitrogen burns in excess \(\mathrm{O}_{2}\) to produce \(5.06 \mathrm{~g} \mathrm{CO}_{2}\) and \(2.07 \mathrm{~g} \mathrm{H}_{2} \mathrm{O} .\) Calculate the mass of each element in the sample and the mass percentage of each element in the compound.

The compound dinitrogen monoxide, \(\mathrm{N}_{2} \mathrm{O}\), is a nontoxic gas that is used as the propellant in cans of whipped cream. How many nitrogen atoms are in a 34.7-g sample of \(\mathrm{N}_{2} \mathrm{O}\) ?

Some ionic compounds exist in crystalline form with a certain number of water molecules associated with the ions. Such compounds are called bydrates. For example, calcium sulfate can exist with either one-half water molecule per formula unit, written as \(\mathrm{CaSO}_{4} \cdot 1 / 2 \mathrm{H}_{2} \mathrm{O}\) or two water molecules per formula unit, written as \(\mathrm{CaSO}_{4} \cdot 2 \mathrm{H}_{2} \mathrm{O} .\) What is the percentage water (by mass) for each compound?

A \(2.770-\mathrm{g}\) sample containing only carbon, hydrogen, and oxygen burns in excess \(\mathrm{O}_{2}\) to produce \(4.06 \mathrm{~g} \mathrm{CO}_{2}\) and \(1.66 \mathrm{~g} \mathrm{H}_{2} \mathrm{O} .\) Calculate the mass of each element in the sample and the mass percentage of each element in the compound.

(a) Calculate the number of moles in \(33.1 \mathrm{~g} \mathrm{SO}_{3}\). (b) Calculate the number of molecules in this sample. (c) Calculate the number of sulfur and oxygen atoms in the sample.

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