Chapter 3: Problem 100
What is the empirical formula of a substance containing only selenium and chlorine, and is \(52.7 \%\) selenium by mass?
Short Answer
Expert verified
The empirical formula is SeCl\(_2\).
Step by step solution
01
Determine Moles of Selenium
The given percentage by mass of selenium in the compound is 52.7%. Since the total mass percentage must equal 100%, the mass percentage of chlorine is 100% - 52.7% = 47.3%. For simplicity, assume a 100 g sample, which means there are 52.7 g of selenium. The molar mass of selenium is approximately 78.96 g/mol. Thus, the number of moles of selenium is calculated by dividing the mass by the molar mass: \[ \text{Moles of Se} = \frac{52.7 \text{ g}}{78.96 \text{ g/mol}} \approx 0.668 \text{ mol} \]
02
Determine Moles of Chlorine
Using the same 100 g sample, the mass of chlorine is 47.3 g. The molar mass of chlorine is approximately 35.45 g/mol. Calculate the moles of chlorine as follows: \[ \text{Moles of Cl} = \frac{47.3 \text{ g}}{35.45 \text{ g/mol}} \approx 1.334 \text{ mol} \]
03
Calculate Simplest Mole Ratio
To find the simplest whole number ratio of moles of selenium to chlorine, divide each by the smallest number of moles calculated: \[ \text{Ratio of Se} = \frac{0.668}{0.668} = 1 \] \[ \text{Ratio of Cl} = \frac{1.334}{0.668} \approx 2 \] Thus, the ratio of selenium to chlorine is roughly 1:2.
04
Determine Empirical Formula
Based on the mole ratio, the simplest empirical formula is one selenium atom for every two chlorine atoms. Therefore, the empirical formula of the compound is SeCl\(_2\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Mole Calculation
Mole calculation is a fundamental concept in chemistry. It helps us understand the relationships between the mass of a chemical substance and the amount of substance in terms of particles, represented in moles. To determine the number of moles in a sample, you divide the sample's mass by the molar mass of the substance.
For example, if you have a sample containing selenium and chlorine as described in the problem, you use the masses from your assumed 100 g sample.
For example, if you have a sample containing selenium and chlorine as described in the problem, you use the masses from your assumed 100 g sample.
- The mass of selenium: 52.7 g
- The molar mass of selenium: 78.96 g/mol
Mass Percentage
Mass percentage is a way of expressing the concentration of an element in a compound. It tells what fraction of the compound's total mass is made up by a particular element.
In our example, selenium makes up 52.7% of the compound's mass.
In our example, selenium makes up 52.7% of the compound's mass.
- This means that in every 100 g of the compound, 52.7 g is selenium.
- The remainder, 47.3%, is chlorine.
Molar Mass
Molar mass is the total mass of one mole of a substance, usually expressed in grams per mole (g/mol). It is calculated by summing up the atomic masses of all the atoms in the substance's molecular formula.
Understanding molar mass is essential for converting between the mass of a sample and the amount of substance in moles. Each element's atomic mass can be found on the periodic table.
Understanding molar mass is essential for converting between the mass of a sample and the amount of substance in moles. Each element's atomic mass can be found on the periodic table.
- Selenium has a molar mass of approximately 78.96 g/mol.
- Chlorine has a molar mass of approximately 35.45 g/mol.