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In a "dead" battery, the chemical reaction has come to equilibrium. What are the values of \(\Delta G\) and \(E\) for a dead battery?

Short Answer

Expert verified
Both \(\Delta G\) and \(E\) are zero for a dead battery at equilibrium.

Step by step solution

01

Understanding Equilibrium

In a dead battery, the reaction has reached equilibrium. This means there is no net change in the reactants and products because the forward and reverse rates of the reaction are equal.
02

Characteristics of Equilibrium in Terms of Gibbs Free Energy

At equilibrium, the change in Gibbs Free Energy (\(\Delta G\)) is zero. This is because \(\Delta G = 0\) signifies that the process is at equilibrium and there is no drive for the reaction to proceed in either direction spontaneously.
03

Characteristics of Equilibrium in Terms of Cell Potential

For an electrochemical cell at equilibrium, the cell potential (\(E\)) is zero. This is because the cell can no longer produce electrical work.
04

Relating Gibbs Free Energy to Cell Potential

The relationship between \(\Delta G\) and \(E\) is given by the equation \(\Delta G = -nFE\), where \(n\) is the number of moles of electrons transferred, and \(F\) is Faraday's constant. When \(\Delta G = 0\), \(E\) must also be 0 to satisfy this equation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gibbs Free Energy
Gibbs Free Energy is a thermodynamic quantity that indicates the amount of usable energy in a system that can perform work at constant temperature and pressure. It is a crucial parameter in determining whether a reaction will occur spontaneously. If the Gibbs Free Energy change (\(\Delta G\)) is negative, the reaction proceeds spontaneously. At equilibrium, \(\Delta G = 0\), which means the system is in a state of balance, with no net change in reactants and products.
Understanding \(\Delta G\) is key to many chemical processes, including those in electrochemical cells such as batteries. During a discharge process in a battery, electrical energy is harnessed to do work. When the battery reaches equilibrium, indicating it is "dead," there is no more Gibbs Free Energy available to do work.
In the context of the battery, when \(\Delta G = 0\), it signals not only that the reaction is at equilibrium, but also that the battery can no longer provide power for external use.
Equilibrium Reaction
In chemistry, an equilibrium reaction refers to a state where the forward and reverse reactions occur at equal rates, meaning the concentrations of reactants and products remain constant over time. Although it appears static, this equilibrium is dynamic. Molecules continually convert between reactants and products.
For electrochemical cells, such as a battery, achieving equilibrium means the cell reaction is no longer progressing in a net forward direction. In a rechargeable battery, this can indicate a full charge. In a disposable one, it's when the battery is "dead."
Achieving equilibrium in a battery indicates there's no longer energy being released or consumed in the process of electron transfer, marking the end of its useful life unless recharged (in the case of rechargeable batteries). This is why dead batteries no longer have any practical use until recharged, if applicable.
Cell Potential
Cell potential, also known as electromotive force (EMF), is a measure of the electric potential energy generated by the charge separation in an electrochemical cell. It reflects the ability of a cell to drive an electric current through an external circuit.
For a functioning battery, the cell potential is a positive value, indicating it can do electrical work. As the battery discharges and the reaction moves towards equilibrium, the cell potential drops. Once equilibrium is reached, the cell potential \(E\) becomes zero. At this point, the battery can no longer perform electrical work, effectively rendering it useless until recharged (if possible).
This concept of cell potential is fundamental in understanding why "dead" batteries cannot power devices until they are given a chance to either rest (in some cases) or be replenished by an external energy source.
Electrochemical Cells
Electrochemical cells are devices that convert chemical energy into electrical energy through redox reactions. They are found in various applications, including batteries. These cells consist of two half-cells: the anode, where oxidation occurs, and the cathode, where reduction takes place.
In a typical battery, the electrochemical cells undergo a series of charge-transfer reactions during operation, allowing them to provide power. This power is harnessed as electricity, which can be used to operate electronic devices.
The efficiency of electrochemical cells relies on the continuous balance of these reactions until, eventually, equilibrium is reached. Once equilibrium is achieved, the cell potential becomes zero, and no more net reaction occurs, thereby stopping electricity production.
The design and composition of electrochemical cells directly influence their efficiency, lifespan, and applicability in different technologies and power solutions.

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Sphalerite is the naturally occurring mineral zinc sulfide, from which zinc metal is extracted. The ore is heated in oxygen to form zinc oxide and sulfur dioxide, followed by the reaction of metal oxide with elemental carbon to form CO. (a) Write a balanced equation for each of these reactions. (b) For each reaction, identify the element that is oxidized and the one that is reduced.

A Consider the standard reduction potentials of cesium and lithium. $$ \begin{array}{ll} \mathrm{Cs}^{+}(\mathrm{aq})+\mathrm{e}^{-} \rightarrow \mathrm{Cs}(\mathrm{s}) & E^{\circ}=-3.026 \mathrm{~V} \\\ \mathrm{Li}^{+}(\mathrm{aq})+\mathrm{e}^{-} \rightarrow \mathrm{Li}(\mathrm{s}) & E^{\circ}=-3.095 \mathrm{~V} \end{array} $$ The periodic trends in the properties of the element indicate that fluorine is the most chemically reactive nonmetal, so perhaps it is not surprising that the standard reduction potential of fluorine has the highest positive value for a nonmetallic element. However, periodic properties of the elements also indicate that cesium should be the most reactive metal. Comparison of the voltage of the cesium half-reaction with that of lithium shows that the standard reduction potential of lithium is less negative than that of cesium, indicating that lithium is a better oxidizer than is cesium. (a) Calculate the standard cell voltages of the voltaic cells based on the reaction $$ 2 \mathrm{M}(\mathrm{s})+\mathrm{F}_{2}(\mathrm{~g}) \rightarrow 2 \mathrm{M}^{+}(\mathrm{aq})+2 \mathrm{~F}^{-}(\mathrm{aq}) $$ where \(\mathrm{M}\) is \(\mathrm{Cs}\) and \(\mathrm{Li}\). (b) Assuming that the pressure of \(\mathrm{F}_{2}(\mathrm{~g})\) stays at \(1.00 \mathrm{~atm}\), what concentration does \(\mathrm{Li}^{+}(\mathrm{aq})\) have to be for the voltage of the \(\mathrm{Li} / \mathrm{F}_{2}\) voltaic cell to equal the standard voltage of the \(\mathrm{Cs} / \mathrm{F}_{2}\) voltaic cell? (c) Can you suggest a reason why the standard reduction potential of lithium is lower than that of cesium, even though periodic trends indicate that cesium is the more reactive metal? (d) Calculate \(\Delta G^{o}\) for both the \(\mathrm{Li} / \mathrm{F}_{2}\) and the \(\mathrm{Cs} / \mathrm{F}_{2}\) voltaic cells from their \(E^{\circ} \mathrm{s}\). Compare this with the Gibbs' free energies of formation of \(2 \mathrm{~mol} \mathrm{LiF}\) and CsF. Can you explain the difference? (e) Given the fact that alkali metals react rather violently with water, it would be unlikely that any voltaic cell can be constructed using Li(s) or \(\mathrm{Cs}(\mathrm{s})\) in the presence of water. A more likely scenario is that the voltaic cell would have no solvent, so that the voltaic cell reaction would be $$ 2 \mathrm{M}(\mathrm{s})+\mathrm{F}_{2}(\mathrm{~g}) \rightarrow 2 \mathrm{MF}(\mathrm{xtal}) $$ where \(\mathrm{M}\) is \(\mathrm{Cs}\) or \(\mathrm{Li}\). What would be the \(E^{\circ}\) s of the two different voltaic cells if this were the reaction? (Hint: See your answer to part d.)

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