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OBJECTIVE. Identify the reaction order from the rate law. What is the order in each reactant and the overall order for a reaction that has the following rate law? (a) rate \(=k\left[\mathrm{O}_{3}\right][\mathrm{NO}]^{2}\) (b) rate \(=k\left[\mathrm{NO}_{2}\right]^{1 / 2}\left[\mathrm{Cl}_{2}\right]^{2}\) (c) rate \(=k\left[\mathrm{CH}_{3} \mathrm{Br}\right]\left[\mathrm{OH}^{-}\right]^{0}\)

Short Answer

Expert verified
(a) O3: 1, NO: 2, Overall: 3; (b) NO2: 0.5, Cl2: 2, Overall: 2.5; (c) CH3Br: 1, OH鈦: 0, Overall: 1.

Step by step solution

01

Identify Exponents from Rate Law

For each rate law given, identify the exponent for each reactant in the rate law expression. For example, in the rate law rate \(= k[\mathrm{O}_{3}][\mathrm{NO}]^{2}\), the exponents are 1 for \([\mathrm{O}_{3}]\) and 2 for \([\mathrm{NO}]\).
02

Determine Order of Each Reactant

For each reactant, the exponent signifies its order in the reaction. For example, in the rate \(= k[\mathrm{O}_{3}][\mathrm{NO}]^{2}\), \(\mathrm{O}_{3}\) has an order of 1 and \(\mathrm{NO}\) has an order of 2. Repeat this for each rate law provided.
03

Calculate Overall Reaction Order

Sum the orders of all reactants to determine the overall order of the reaction. For instance, the overall reaction order for rate \(= k[\mathrm{O}_{3}][\mathrm{NO}]^{2}\) is calculated as \(1 + 2 = 3\). Repeat this process to find the overall order for each given rate law.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rate Law
The rate law of a chemical reaction gives us vital information about how the concentrations of reactants affect the speed of the reaction. In essence, it relates the rate of reaction to the concentration of the reactants, each raised to a power, often called the order of the reaction with respect to that reactant. The general form of a rate law can be expressed as:\[ \text{rate} = k[A]^m[B]^n \]Here, \(k\) is the rate constant, \([A]\) and \([B]\) are the concentrations of the reactants, and \(m\) and \(n\) are the exponents that indicate how the rate is affected by the concentration of each component. Understanding rate laws helps us determine how changes in conditions can affect the speed of a chemical process.
Reactant Order
The order of a reactant in a rate law refers to the exponent to which its concentration term is raised. Each reactant can affect the rate differently, and this influence is measured by the reactant order. For example, if a rate law is given by:\[ \text{rate} = k[\text{O}_3]^1[\text{NO}]^2 \]The reactant order for \([\text{O}_3]\) is 1, indicating a linear relationship between its concentration and the rate. Meanwhile, for \([\text{NO}]\), the reactant order is 2, suggesting that the rate quadruples as its concentration doubles. The reactant order helps deduce how sensitive the reaction is to changes in the concentration of each substance.
Exponents in Chemical Reactions
Exponents in chemical reactions, as seen in rate laws, are crucial as they define the relationship between reactant concentrations and reaction rate. They determine how changes in each reactant's concentration alter the reaction's speed. These exponents are experimentally determined and can be fractional, whole, or even zero. For example:- In the expression \(\text{rate} = k[\text{NO}_2]^{1/2}[\text{Cl}_2]^2\), the exponent for \([\text{NO}_2]\) is \(1/2\), suggesting a non-linear relationship between its concentration and reaction rate.- An exponent of 0, as seen in \([\text{OH}^-]^0\), implies that changes in that reactant鈥檚 concentration do not affect the rate at all.These exponents are essential in predicting how modifications in concentrations impact reaction rates.
Overall Reaction Order
The overall reaction order is a summary of the reaction's sensitivity to concentration changes. It is calculated by summing the orders of all reactants involved in the rate law. This simplifies understanding of the reaction description and behavior.For instance, with the rate law:- \( \text{rate} = k[\text{O}_3]^1[\text{NO}]^2 \), the overall order is \(1 + 2 = 3\).- In another case, \( \text{rate} = k[\text{NO}_2]^{1/2}[\text{Cl}_2]^2 \), the overall order is \(1/2 + 2 = 2.5\).- For \( \text{rate} = k[\text{CH}_3\text{Br}][\text{OH}^-]^0 \), the overall order results as \(1 + 0 = 1\).Knowing the overall reaction order is vital. It helps in the classification of reactions and assessing their response to concentration changes.

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Most popular questions from this chapter

OBJECTIVE. Describe a chemical reaction as a sequence of elementary processes. Sum the following elementary steps to determine the overall stoichiometry of the gas-phase reaction. $$ \begin{array}{l} \mathrm{NO}_{2}+\mathrm{NO}_{2} \rightarrow \mathrm{NO}_{3}+\mathrm{NO} \\ \mathrm{NO}_{3}+\mathrm{CO} \rightarrow \mathrm{NO}_{2}+\mathrm{CO}_{2} \end{array} $$

OBJECTIVE. Use stoichiometry to relate the rate of reaction to changes in the concentrations of reactants and products. For the reaction, $$ 2 \mathrm{NO}_{2}(\mathrm{~g})+\mathrm{O}_{3}(\mathrm{~g}) \rightarrow \mathrm{N}_{2} \mathrm{O}_{5}(\mathrm{~g})+\mathrm{O}_{2}(\mathrm{~g}) $$ the dinitrogen pentoxide appears at a rate of \(0.0055 \mathrm{M} / \mathrm{s}\). Calculate the rate at which the \(\mathrm{NO}_{2}\) disappears and the rate of the reaction.

OBJECTIVE. Relate half-life and rate constant, and calculate concentration- time behavior from the half-life of a first-order reaction. Calculate the half-life of a first-order reaction if the concentration of the reactant decreases from 0.012 to \(0.0082 \mathrm{M}\) in 66.2 seconds.

OBJECTIVE. Relate temperature, activation energy, and rate constant through the Arrhenius equation. A reaction rate doubles when the temperature increases from \(25^{\circ} \mathrm{C}\) to \(40^{\circ} \mathrm{C}\). What is the activation energy?

A The enzyme catalase reduces the activation energy for the decomposition of hydrogen peroxide from 72 to \(28 \mathrm{~kJ} /\) mol. Calculate the factor by which the rate of reaction increases at \(298 \mathrm{~K}\), assuming that everything else is unchanged. $$ \mathrm{H}_{2} \mathrm{O}_{2}(\mathrm{aq}) \rightarrow \mathrm{H}_{2} \mathrm{O}(\ell)+\frac{1}{2} \mathrm{O}_{2}(\mathrm{~g}) $$.

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