91Ó°ÊÓ

The given redox reaction is a combustion reaction.

Combustion of pentane takes place in presence of oxygen and forms carbon dioxide and water.

The balanced reaction is:

$C_5{H}_{12}\left(I\right)+8O_2\left(g\right)→5C{O}_2\left(g\right)+6H_{2}O\left(I\right)$

The given redox reaction is a combination reaction.

Phosphorous trichloride combines with chlorine and forms phosphorous pentachloride.

The balanced reaction is:

$P{C}_3\left(I\right)+C{I}_2\left(g\right)→PC{I}_5\left(s\right)$

The given redox reaction is a displacement reaction.

Zinc displaces two hydrogen atoms and forms zinc bromide.

The balanced reaction is:

$Zn\left(s\right)+2HBr\left(aq\right)→ZnB{r}_{}\left(aq\right)+H_2\left(g\right)$

The given redox reaction is a displacement reaction.

Bromine displaces iodide from potassium iodide molecule and forms potassium bromide.

The balanced reaction is:

$2KI\left(aq\right)+B{r}_2\left(I\right)→2KBr\left(aq\right)+I_2\left(s\right)$

The balanced equation is:

$2KI\left(aq\right)+B{r}_2\left(I\right)→2KBr\left(aq\right)+I_2\left(s\right)$

Now, the total ionic equation is:

role="math" localid="1656687207948" $2K^{+}\left(aq\right)+2I^{-}\left(aq\right)+B{r}_2\left(I\right)→2B{r}^{-}\left(aq\right)+I_2\left(s\right)$

K⁺is the spectator ion in the total ionic equation and it will not be present in net ionic equation. Hence the net ionic equation is

$2I^{-}\left(aq\right)+B{r}_2\left(I\right)→2B{r}^{-}\left(aq\right)+I_2\left(s\right)$