Chapter 4: Q4.7P (page 178)
Why are some ionic compounds soluble in water and others are not?
Short Answer
ANSWER:
Those ionic compounds which have a strong ionic bond, does not soluble in water.
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Chapter 4: Q4.7P (page 178)
Why are some ionic compounds soluble in water and others are not?
ANSWER:
Those ionic compounds which have a strong ionic bond, does not soluble in water.
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When each of the following pairs of aqueous solutions is mixed, does a precipitation reaction occur? If so, write balanced molecular, total ionic, and net ionic equations:
(a) Sodium sulfide + nickel (II) sulfate
(b) Lead (II) nitrate + potassium bromide
Question: How many moles ofions are present in the following aqueous solutions?
(a) 1.4 mL of 0.75 M hydrobromic acid
(b) 2.47 mL of 1.98 M hydriodic acid
(c) 395 mL of 0.270 M nitric acid
Calcium dihydrogen phosphate, Ca(H2PO4)2, and sodium hydrogen carbonate, NaHCO3, are ingredients of baking powder that react with each other to produce CO2, which causes dough or batter to rise:
[unbalanced]
If the baking powder contains 31% NaHCO3and 35% Ca(H2PO4)2 by mass:
(a) How many moles of CO2 are produced from 1.00 g of baking powder?
(b) If 1 mol of CO2 occupies 37.0 L at 350_F (a typical baking temperature), what volume of CO2is produced from 1.00 g of baking powder?
Question: State a general equation for a neutralization reaction.
On a lab exam, you have to find the concentrations of the monoprotic (one proton per molecule) acids HA and HB. You are given 43.5mL of HA solution in one flask. A second flask contains 37.2mL of HA, and you add enough HB solution to it to reach a final volume of 50.0mL. You titrate the first HA solution with 87.3mL of 0.0906M NaOH and the mixture of HA and HB in the second flask with 96.4mL of the NaOH solution. Calculate the molarity of the HA and HB solutions.
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