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Chapter 23: Q83P (page 1022)

A metal ion uses d2sp3 orbitals when forming a complex. What is its coordination number and the shape of the complex?

Short Answer

Expert verified

The coordination number is 6 and the shape of the complex is octahedral.

Step by step solution

01

Valence bond theory will be used here

Valence bond theory explains to us that the ligand's orbital that is filled overlaps with the empty orbital of the metal ion; ligands donate their electron pairs, the metal ion accepts them and the coordination covalent bond is formed.

02

Coordination number and shape of the complex

When metal ion uses d2sp3 orbitals when forming a complex, it means that there are two 3d, one 4s, and three 4p orbitals mixed to form six d2sp3 hybrid orbitals. Thus, the coordination number of the metal ion would be 6 and the shape of the molecule is octahedral.

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Most popular questions from this chapter

Sketch the orientation of the orbitals relative to the ligands in an octahedral complex to explain the splitting and the relative energies of the dxyand the dx2-y2orbitals.

Criticize and correct the following statement: strong-field ligands always give rise to low-spin complexes.

(a) What is a coordinate covalent bond?

(b) Is it involved when FeCl3 dissolves in water? Explain.

(c) Is it involved when HCl gas dissolves in water? Explain.

Question: For the compound [Coen2Cl2]Cl, give:

(a) The coordination number of the metal ion

(b) The oxidation number of the central metal ion

(c) The number of individual ions per formula unit

(d) The moles of AgCl that precipitate immediately when 1 mol of compound is dissolved in water and treated withAgNO3

Question: Give the electron configuration and the number of unpaired electrons for (a)Sc+3(b)Cu+2(c)Fe+3(d)Nb+3
See all solutions

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