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Like heavy water (D2O), so-called 鈥渟emi-heavy water鈥 (HDO) undergoes H/D exchange. The scenes below depict an initial mixture of HDO and H2reaching equilibrium.


a) Write the balanced equation for the reaction. (b) Is the value of K greater or less than? (c) If each molecule depicted represents0.10M, calculate K.

Short Answer

Expert verified

a) The balanced equation for the reaction is: 5HDO + 5H23HD + 3HDO + 2H2O.

b) The value of K is:110-3<k<1103 .

c) The value of K is obtained as: K = 1.194脳10- 3.

Step by step solution

01

Define Elements

An element is a pure material made up entirely of atoms with the same number of protons in their nuclei, as defined by chemistry. Chemical elements, unlike chemical compounds, cannot be broken down into smaller substances by chemical reactions.

02

Write the balanced equation

a) We can see five H2molecules and five HDO molecules on the left image. We can see three H2molecules, two HD molecules, three HDO molecules, and two H2Omolecules on the right. The following equation may be used to describe that reaction:

5HDO + 5H23HD + 3HDO + 2H2O

Therefore, the balanced equation is: 5HDO + 5H23HD + 3HDO + 2H2O.

03

Is the value of K greater or less than one?

b) We have 10 reactant molecules and product molecules. Because not all reactants have changed into products, we have both R and P species in equilibrium. In situations like these, we can't be certain of the K value, but we can estimate it to be between 1脳103 and 1脳10-3. If just reactant species were present, the K value would be less than 1脳103. Also, if just product species were present, we would argue that K is greater than 103.


Therefore, the value is greater than one or else 1脳103&濒迟;办&濒迟;1脳10-3

04

Calculate the value of K

c) The value of K is obtained as:

[HDO]left= 0.5MH2left= 0.5MH2right= 0.3M[HDO]right= 0.3M[HD] = 0.2MH2O= 0.2MK =H22[HD]2[HDO]3H2O2[HDO]5H25K =(0.3M)3(0.2M)2(0.3M)3(0.2M)2(0.5M)5(0.5)5K = 1.194脳10-3

Therefore, the value of K is:K = 1.194脳10-3 .

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