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Chapter 2: Q63P (page 83)

Given that the ions in LiF and MgO are of similar size, which compound has stronger ionic bonding? Use Coulomb鈥檚 law in your explanation.

Short Answer

Expert verified

MgO the compound has stronger ionic bonding.

Step by step solution

01

Define Coulomb’s law

Coulomb鈥檚 law is defined as the interaction force between two ions (cation and anion) in an ionic bond is directly proportional to the product of charges of ions and inversely proportional to the distance between two ions.

F=伪q1q2r2

Here,

Fis the interaction between two ions.

q1is the charge of an ion (cation).

q2is the charge of an ion (anion).

r is the distance between two ions.

02

Apply the Coulomb’s law

In , MgO the charge of Mg2+cation is +2 while the charge of O2anion is -2. In the case of LiF , the charge of Li+cation is +1 while the charge of F anion is -1. So, the product of charges of two ions in MgO is greater than that of two ions in . Hence,MgOthe compound has stronger ionic bonding.

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