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Chapter 2: Q4.67P (page 40)

Give the oxidation number of sulfur in the following:

aSOCl2bH2S2cH2SO3dNa2S

Short Answer

Expert verified

You need to provide the oxidation number of sulfur for the given compounds.

Step by step solution

01

Oxidation state of sulfur in SOCl2

The oxidation state of oxygen is -2.

The oxidation state of chlorine is -1.

Let, oxidation state of sulfur in SOCl2is x.

No, you can write,

x+-2+2-1=0x=+4

Hence, the oxidation state of sulfur in SOCl2is +4.

02

Oxidation state of sulfur in H2S2

Oxidation state of Hydrogen is +1.

Let, oxidation state of sulfur in H2S2is y.

No you can write,

2+1+2y=02y=-2y=-1

Hence, the oxidation state of sulfur in H2S2is -1.

03

Oxidation state of sulfur in H2SO3

Oxidation state of Hydrogen is +1.

Oxidation state of Oxygen is -2.

Let, oxidation state of sulfur in H2SO3is z.

No you can write,

2+1+z+3-2=0z=+4

Hence, oxidation state of sulfur in H2SO3is +4.

04

Oxidation state of sulfur in Na2S

Oxidation state of Sodium is +1.

Let, oxidation state of sulfur in Na2S is k.

No you can write,

2+1+k=0k=-2

Hence, oxidation state of sulfur in Na2S is -2.

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