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Chapter 3: Q84P (page 134)

What is the percent yield of a reaction in which 200. g of phosphorus trichloride reacts with excess water to form 128 g of HCl and aqueous phosphorous acid(H3PO3) ?

Short Answer

Expert verified

Percent yield for the given process is 80.6%.

Step by step solution

01

Writing balanced equation

First of all, let us check the balanced equation to find the percent yield:

PCI3+3H2O鈫�H3PO3+3HCI

From the equation we can say that 1 mol of PCl3 gives three moles of HCl.

02

Calculating Moles of PCl3

Moles can be calculated as

MolesofPCI3=MassofPCI3Molarmass=200137.33=1.45

From the balanced equation we can say that,

3脳MolesofPCI3=MolesofHCI=4.35

03

Theoretical yield

The maximum possible mass of a product that can be formed in a chemical reaction, is known as its theoretical yield. Hence, Theoretical yield of HCl is

MassofHCI=Moles脳Molarmass=4.35脳36.5=158.775g
04

Percent yield calculation

Mass of HCl actually formed = 128 g (given)

Percent yield can be calculated using the given formula:

Percentyield=Actualyieldtheoriticalyield脳100=128158.775脳100=80.6%

So, Percent yield for the given process is 80.6%.

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