/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q14.141CP The electronic transition in Na ... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 14: Q14.141CP (page 625)

The electronic transition in Na from 3p1to3s1 gives rise to a bright yellow-orange emission at 589.2 nm. What is the energy of this transition?

Short Answer

Expert verified

The energy of this transition is3.371脳10- 19J.

Step by step solution

01

Convert wavelengths in nanometres (nm) to metres (m).

The following equation is used to determine the energy of the transition:

E=hc位______________1

E is the energy of transition, h is the Plank's constant, c is the light velocity and 位is the emission wavelength.

Plank's constant has a value of6.26脳10-34J.s.

The value of light velocity is2.99792脳108m/s.

The emission wavelength is 589.2 nm.

Convert wavelengths in nanometres (nm) to metres (m).

位=589.2nm脳1m109nm=589.2脳10-9m

02

Evaluation of energy of transition

Substitute all known values in equation (1).

E=6.26脳10-34J.s脳2.99792脳108m/s589.2脳10-9m=3.371脳10-19J

Therefore, the energy of transition is 3.371脳10-19J.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Which member of each pair has more ioniccharacter in its bonds:

(a) BeF2 or CaF2; (b) PbF2 or PbF4; (c) GeF4 or PF3?

The interhalogen IF undergoes the reaction depicted below (I is purple and F is green):

(a) Write the balanced equation.

(b) Name the interhalogen product.

(c) What type of reaction is shown?

(d) If each molecule of IF represents 2.50脳10-3mol, what mass of each product forms?

Bromine monofluoride (BF) disproportionates to bromine gas and bromine tri- and pentafluorides. Use the following to find 螖Horxnfor the decomposition of BrF to its elements:

3BrF(g)鈫�Br2(g)+BrF3(l)螖Horxn=-125.3KJ\hfill5BrF(g)鈫�2Br2(g)+BrF5(l)螖Horxn=-166.1KJ\hfillBrF3(l)+F2鈫�(g)BrF5(l)螖Horxn=-158.0KJ\hfill

Which member of each pair has more covalentcharacter in

its bonds: (a) LiCl or KCl; (b) AlCl3 or PCl3; (c) NCl3 or AsCl3?

Select the stronger bond in each pair:

(a) Cl-Cl or Br-Br

(b) Br-Br or I-I

(c) F-F or Cl-Cl.

Why doesn't the F-F bond strength follow the group trend?
See all solutions

Recommended explanations on Chemistry Textbooks

The Earths Atmosphere

Read Explanation

Organic Chemistry

Read Explanation

Making Measurements

Read Explanation

Physical Chemistry

Read Explanation

Chemical Analysis

Read Explanation

Nuclear Chemistry

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.