Q24.93P The reaction that will probably ... [FREE SOLUTION]

Chapter 24: Q24.93P (page 1105)

The reaction that will probably power the first commercial fusion reactor is
${}_{1}^{3}{H +}_{1}^{2} H {鈫�}_{2}^{4} {He +}_{0}^{1} n$
How much energy would be produced per mole of reaction?
(Masses of atoms: ${}_{1}^{3}{H = 3.01605amu;}_{1}^{2} H = 2.0140amu$ ;
${}_{2}^{4}{He = 4.00260amu;mass of}_{0}^{1} n = 1.008665amu$ .)

Short Answer

Expert verified

The energy per mole of the given reaction is $1689654573 \frac{kJ}{mol}$ .

Step by step solution

Definition of Concept

Electronegativity: An atom's chemical behavior in which it attracts the shared electron pair to itself is known as electronegativity. As the number of energy levels grows larger, electronegativity decreases.

Find the energy per mole of the given reaction

Considering the given reaction:

${}_{1}^{3}{H +}_{1}^{2} H {鈫�}_{2}^{4} {He +}_{0}^{1} n$

The total masses of both reactants and products must first be determined.

Mass of the reactants:

$3.01605 + 2.0140 鈥� = 5.03005amu$

The product's mass is:

$\begin{array}{rcl} 4.00260 + 1.008665 & = & 5.011265amu \\ 4m & = & 5.03005amu - 5.011265amu \\ = & 0.0188amu \end{array}$

To calculate the amount of energy released, we must use Einstein's equation:

$\begin{array}{rcl} E & = & {4mc}^{2} \\ E & = & [\frac{0.0188g}{mol}] [\frac{1kg}{1000g}] {[{2.99792脳10}^{8} \frac{m}{s}]}^{2} [\frac{1.J}{\frac{{kg.m}^{2}}{s^{2}}}] [\frac{1kJ}{1000.J}] \\ = & 1689654573 \frac{kJ}{mol} \end{array}$

Therefore, the required value is $1689654573 \frac{kJ}{mol}$ .

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Short Answer

Step by step solution

Definition of Concept

Find the energy per mole of the given reaction

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The reaction that will probably power the first commercial fusion reactor isH +1213H鈫�24He +01nHow much energy would be produced per mole of reaction?(Masses of atoms: H = 3.01605amu;1213H = 2.0140amu;He = 4.00260amu;mass of0124n = 1.008665amu.)

Short Answer

Step by step solution

Definition of Concept

Find the energy per mole of the given reaction

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Chemistry Textbooks

Organic Chemistry

Making Measurements

Kinetics

The Earths Atmosphere

Chemical Reactions

Physical Chemistry

Study anywhere. Anytime. Across all devices.