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How many MeV are released per nucleus when 3.2×10- 3molof chromium-49releases8.11×105kJ?

Short Answer

Expert verified

The energy released per nucleus is 2.63MeV/nucleus.

Step by step solution

01

Step 1:

- The number of moles of chromium-49 is3.2×10- 3mol

- Total energy released is8.11×105kJ

We have to find the energy released per nucleus inMeV

-1MeV = 1.602×10- 13J

Total number of nucleus is

Number of nucleus =3.2×10- 3³¾´Ç±ô×6.022×1023nucleus1mol=1.927×1021nucleus

Now, let us convert total energy released, fromkJ to MeV

Total energy released =8.11×105°ì´³Ã—1000J1kJ×1MeV1.602×10- 13J=5.06×1021MeV

Therefore, the energy released per nucleus in MeVis

Energy per nucleus=5.06×1021MeV1.927×1021nucleus=2.63MeV/ nucleus

Hence The energy released per nucleus is 2.63MeV/nucleus.

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