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If2.81010% of the atoms of a radioactive isotope disintegrate in1.0yr , what is the decay constant of the process?

Short Answer

Expert verified

The decay constant value is2.81012year1.

Step by step solution

01

Definition of decay constant

The size of a population of radioactive atoms and the pace at which the population diminishes due to radioactive decay are proportionate.

02

Calculation of the decay constant

A: Activity, the amount of particles that have degraded during time.

N: Number of particles

k: decay constant

Every day, one trillionth of the atoms dissolve.

A=2.81010%decays/yearN=2.81010decays/year100N=2.81012decays/yearN.

Now, using this equation, compute the decays constant.

A=kNk=AN=2.81012decays/yearNN=2.81012year1.

Therefore, the computed value is 2.81012year1.

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