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What is the specific activity (in Bq/g) if of an isotope emits 3.77107particles per minute?

Short Answer

Expert verified

The specific activity is5.87102Bq/g.

Step by step solution

01

Definition of Kinetics of Radioactive Decay

The decrease in the number of radioactive nuclei per unit time is the rate of decay, or activity, of a sample of a radioactive substance.

02

Calculate the specific activity

An isotope's mass is calculated as follows:

m=1.07kg=1.07kg103g1kg=1.07103g.

The radioactive isotope's activity is :

A=3.77107decays /min.

1Bq=1decay.

We need to find the specific activity (in Bq/g)

Let's begin by converting the activity from decays/s to Bq.

A=3.77107decaysmin1min60s=6.28105decayss1Bq1decay/s=6.28105Bq.

We can now compute the specific activity=Am.

Therefore, the specific activity

=6.28105Bq1.07103g=5.87102Bq/g.

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