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What is the specific activity (in Ci/g) if 2.6gof an isotope emits4.13×108β− particles per hour?

Short Answer

Expert verified

The specific activity is 1.19×106Ci/g.

Step by step solution

01

Definition of Kinetics of Radioactive Decay

The decrease in the number of radioactive nuclei per unit time is the rate of decay, or activity, of a sample of a radioactive substance.

02

Calculation of the specific activity

An isotope's mass is calculated as follows: m=2.6g.

The radioactive isotope's activity is :

A=4.13×108decays/hour.

1Ci=3.70×1010decays.

We need to find the specific activity (in Ci/g)

Let's begin by converting the activity from decays/s to Ci

A=4.13×108decayshour×1hour3600seconds=1.147×1051Cidecays×13.70×1010decays/second=3.1×106Ci.

Now we can calculate the specific activity

specificactivity=Am=3.1×106Ci2.6g=1.19×106Ci/g.

Therefore, the required value is 1.19×106Ci/g.

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