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In the naturally occurring thorium-232 decay series, the steps emit this sequence of particles: ,-,-,,,,,-,. Write a balanced equation for each step.

Short Answer

Expert verified

90232Th24+88228Ra88228Ra-10+89228Ac89228Ac-10+90228Th90228Th24+88224Ra88224Ra24+86220Rn86220Rn24+84216Po84216Po24+82212Pb82212Pb-10+83212Bi83212Bi-10+84212Po84212Po24+82208Pb

Step by step solution

01

Definition of Nuclear Chemistry

Nuclear chemistry is a branch of chemistry concerned with the 鈥渟tudy of changes鈥 in the nucleus of atoms. These nuclear alterations produce nuclear power and radioactivity, and the energy generated by nuclear reactions has a wide range of uses.

02

Explanation of the balanced equation.

decay is a radioactive process in which an alpha particle is emitted from a nucleus. decay A radioactive process in which a beta particle is emitted from a nucleus.

In the naturally occurring thorium-232 decay series, the steps emit this sequence of particles:

First decay process reaction

T90232hemitsemission):90232Th24+88228Ra

Second decay process reaction R88228aemits-emission):

R88228a-10+89228Ac

Third decay process reaction A89228cemits-emission):

A89228c-10+90228Th

Forth decay process reaction T90228hemitsemission):

T90228h24+88224Ra

Fifth decay process reaction (88224Raemitsemission):

R88224a24+86220Rn

03

Explanation of the balanced equation.

Sixth decay process reactionR86220nemitsemission):

R86220n24+84216Poo

Seventh decay process reactionP84216oemitsemission):

P84216o24+82212Pb

Eighth decay process reaction82212Pbemits-emission):

82212Pb-10+83212Bi

Ninth decay process reactionB83212iemits-emission):

B83212i-10+84212Po

Tenth decay process reactionP84212oemitsemission):

P84212o24+82208Pb

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