24.100 CP The overall reaction taking plac... [FREE SOLUTION]

Chapter 24: 24.100 CP (page 1106)

The overall reaction taking place during hydrogen burning in a young star is
$4 {鈥�}_{1}^{1} H {鈫�}_{2}^{4} H e + 2 {鈥�}_{1}^{0} 尾 + 2 鈥� 谓 + e n e r g y$
How much energy (in MeV) is released per He nucleus formed? Per mole of He? (Masses: ₁¹H atom=1.007825 amu ; ⁴₂He atom-4.00260 amu ; positron $- 5.48580 脳 10^{- 4} a m u$ .)

Short Answer

Expert verified

The energy (in MeV) is released per He nucleus formed is 25.71 MeV and the energy released per mole of helium is $1.548 脳 10^{25} M e V$ .

Step by step solution

Definition of Concept

Nuclear reaction: A nuclear reaction occurs when a lighter nucleus fuses together to form new stable nuclei, or when a heavier nucleus splits into stable daughter nuclei, releasing a large amount of energy.

Calculating the mass difference

Considering the given information:

$4_{1}^{1} H {鈫�}_{2}^{4} H e + 2_{1}^{0} 尾 + 2 v + e n e r g y$

$螖 m$ is the difference in the masses of the reactants and products..

$4_{1}^{1} H {鈫�}_{2}^{4} H e + 2_{1}^{0} 尾 + 2 v + e n e r g y m_{r e a c \tan t} = 鈥� 4 脳 m_{H} = 4 脳 1.007825 a m u = 鈥� 4.0313 a m u m_{p r o d u c t} = m_{H e} + 2 脳 m_{e} = 4.00260 a m u + 2 脳 5.4858 脳 10^{- 4} a m u = 4.0037 a m u 螖 m = m_{r c a c \tan t} - m_{p r o d u c t} = 4.0313 a m u - 4.0037 a m u = 0.0276 a m u$

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Definition of Concept

Calculating the mass difference

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The overall reaction taking place during hydrogen burning in a young star is4鈥�11H鈫�24He+2鈥�10尾+2鈥�谓+energyHow much energy (in MeV) is released per He nucleus formed? Per mole of He? (Masses: 11H atom=1.007825 amu ; 42He atom-4.00260 amu ; positron -5.48580脳10-4amu.)

Short Answer

Step by step solution

Definition of Concept

Calculating the mass difference

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Chemistry Textbooks

Organic Chemistry

The Earths Atmosphere

Chemistry Branches

Chemical Reactions

Nuclear Chemistry

Ionic and Molecular Compounds

Study anywhere. Anytime. Across all devices.